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BIOL 101 Complete Study Guide Unit 1: DNA, RNA, and Genetics 1. DNA structure What is DNA? DNA stands for deoxyribonucleic acid. It stores the genetic information that tells cells how to function, grow, and reproduce. What is the shape of DNA? DNA has a double-helix shape, which looks like a twisted ladder. What are the building blocks of DNA? Nucleotides. What are the three parts of a DNA nucleotide? * A phosphate group * A five-carbon sugar called deoxyribose * A nitrogenous base What are the four nitrogenous bases in DNA? * Adenine (A) * Thymine (T) * Cytosine (C) * Guanine (G) What are the DNA base-pairing rules? * Adenine pairs with Thymine (A–T). * Cytosine pairs with Guanine (C–G). What does complementary base pairing mean? Each DNA base has a specific partner. Knowing one DNA strand allows you to determine the matching strand. Example: * Original: A T C G * Complement: T A G C What holds the two DNA strands together? Hydrogen bonds between the nitrogenous bases. 2. DNA vs. RNA What is RNA? RNA stands for ribonucleic acid. It helps use the genetic instructions stored in DNA to make proteins. What are the main differences between DNA and RNA? DNA RNA Usually double-stranded Usually single-stranded Contains deoxyribose sugar Contains ribose sugar Uses thymine (T) Uses uracil (U) Stores genetic information Helps make proteins What are the four bases in RNA? * Adenine (A) * Uracil (U) * Cytosine (C) * Guanine (G) What replaces thymine in RNA? Uracil. What are the three main types of RNA? * mRNA (messenger RNA): Carries genetic instructions from DNA to the ribosome. * tRNA (transfer RNA): Brings amino acids to the ribosome. * rRNA (ribosomal RNA): Makes up part of the ribosome and helps build proteins. 3. DNA replication What is DNA replication? DNA replication is the process of making an identical copy of DNA before a cell divides. Why is DNA replication important? It ensures that each new cell receives a copy of the genetic information. What does semiconservative replication mean? Each new DNA molecule contains one original strand and one newly made strand. What enzyme unzips DNA? Helicase. What enzyme adds new DNA nucleotides? DNA polymerase. What enzyme connects DNA fragments on the lagging strand? DNA ligase. What is the leading strand? The strand that is copied continuously in the direction of the replication fork. What is the lagging strand? The strand that is copied in short sections called Okazaki fragments. What are Okazaki fragments? Short pieces of newly made DNA that form on the lagging strand. What is the job of DNA ligase? It joins the Okazaki fragments together. What are telomeres? Protective sections of DNA found at the ends of chromosomes. What is the purpose of telomeres? They help protect important genetic information from being lost when DNA is copied. What is DNA repair? The process cells use to identify and correct mistakes or damage in DNA. 4. Transcription What is transcription? Transcription is the process of copying genetic information from DNA into mRNA. Where does transcription happen in eukaryotic cells? In the nucleus. What enzyme helps make RNA during transcription? RNA polymerase. What is the purpose of transcription? To create an mRNA copy of a gene that can be used to make a protein. What are the RNA base-pairing rules? * DNA A pairs with RNA U. * DNA T pairs with RNA A. * DNA C pairs with RNA G. * DNA G pairs with RNA C. Example: DNA: A T C G RNA: U A G C What happens to mRNA before it leaves the nucleus in eukaryotic cells? It undergoes RNA processing. What are introns? Sections of RNA that are removed during RNA processing. What are exons? Sections that remain and are joined together to form mature mRNA. What is RNA splicing? The removal of introns and joining of exons. 5. Translation What is translation? Translation is the process of using mRNA instructions to build a protein. Where does translation happen? At the ribosomes in the cytoplasm or on the rough endoplasmic reticulum. What is a codon? A group of three mRNA bases that codes for an amino acid or a stop signal. What is an anticodon? A group of three bases on tRNA that pairs with a matching mRNA codon. What is the role of tRNA? It carries amino acids to the ribosome. What is the role of the ribosome? It reads mRNA and connects amino acids to build a protein. What is the start codon? AUG. What amino acid does AUG code for? Methionine. What are the three stop codons? * UAA * UAG * UGA What happens when a stop codon is reached? Translation ends, and the completed protein is released. 6. Gene expression and regulation What is gene expression? Gene expression is the process of using information from a gene to make a functional product, such as a protein. What is gene regulation? Gene regulation controls when, where, and how much a gene is expressed. Why is gene regulation important? It allows cells to perform different functions even though many cells contain the same DNA. What is an operon? A group of genes controlled together, commonly found in bacteria. What is the lac operon? A group of bacterial genes involved in breaking down lactose. What happens when lactose is present? Lactose helps remove the repressor’s blockage, allowing the genes to be expressed. What happens when lactose is absent? The repressor binds to the operator and prevents the genes from being expressed. Unit 2: Evolution and Natural Selection 1. Understanding evolution What is evolution? Evolution is the change in inherited characteristics of a population over generations. Does an individual organism evolve during its lifetime? No. Populations evolve over generations. What is a population? A group of individuals of the same species living in the same area. What is a species? A group of organisms that can reproduce with one another and produce fertile offspring, under the biological species concept. What is natural selection? Natural selection is the process in which organisms with inherited traits that improve survival or reproduction tend to leave more offspring. Who is associated with the theory of evolution by natural selection? Charles Darwin. What is adaptation? An inherited characteristic that helps an organism survive or reproduce in its environment. What is biological fitness? An organism’s ability to survive and reproduce, measured by its contribution of offspring to the next generation. Does the strongest organism always have the highest fitness? No. Fitness depends on how well an organism’s inherited traits help it reproduce in its particular environment. 2. Natural selection What are the main requirements for natural selection? * Individuals in a population have variation. * Some variation is inherited. * Organisms produce more offspring than can survive. * Individuals with certain inherited traits reproduce more successfully. What happens to helpful inherited traits over generations? They may become more common in the population. Can natural selection create traits because organisms need them? No. Natural selection acts on existing inherited variation. It does not create a needed trait simply because an organism needs it. What is an example of natural selection? If insects vary in color and birds more easily spot one color, insects with the less visible color may survive and reproduce more often. Over generations, that color may become more common. 3. Population genetics What is an allele? An alternative version of a gene. What is a gene pool? All the alleles present in a population. What is allele frequency? The proportion of a particular allele in a population. What does it mean when allele frequencies change? The population is evolving. What is genetic variation? Differences in genetic information among individuals in a population. Why is genetic variation important? It provides the differences that natural selection can act on. 4. Mechanisms of evolution What are the five major mechanisms that can change allele frequencies? * Mutation * Gene flow * Genetic drift * Natural selection * Nonrandom mating can change genotype frequencies and, in some circumstances, influence allele frequencies indirectly through selection. What is mutation? A change in DNA sequence. How can mutations affect evolution? They can introduce new genetic variations and sometimes create new alleles. What is gene flow? The movement of alleles between populations when individuals or their reproductive cells move between them. What is genetic drift? A random change in allele frequencies, especially noticeable in small populations. What is the bottleneck effect? A type of genetic drift that happens when a population becomes much smaller due to a random event. What is the founder effect? A type of genetic drift that occurs when a small group separates from a larger population and starts a new population. What is the difference between natural selection and genetic drift? Natural selection is based on differences in reproductive success associated with inherited traits. Genetic drift changes allele frequencies randomly. 5. Hardy-Weinberg equilibrium What is Hardy-Weinberg equilibrium? A model that describes a population that is not evolving with respect to the gene being studied. What are the five Hardy-Weinberg conditions? * No mutations * Random mating * No natural selection * Very large population * No gene flow What is the Hardy-Weinberg equation? p+q=1 What does p represent? The frequency of one allele. What does q represent? The frequency of the other allele. What is the genotype frequency equation? p^2+2pq+q^2=1 What does each part represent? * : Homozygous dominant * : Heterozygous * : Homozygous recessive What does homozygous mean? Having two identical alleles for a gene. What does heterozygous mean? Having two different alleles for a gene. Practice question: If q = 0.4, what is p? Answer: p=1-0.4=0.6 Practice question: If p = 0.6 and q = 0.4, what is the frequency of homozygous dominant individuals? Answer: p^2=0.6^2=0.36 Practice question: If p = 0.6 and q = 0.4, what is the frequency of heterozygous individuals? Answer: 2pq=2(0.6)(0.4)=0.48 Practice question: If p = 0.6 and q = 0.4, what is the frequency of homozygous recessive individuals? Answer: q^2=0.4^2=0.16 6. Evidence for evolution What are some forms of evidence for evolution? * Fossil records * Comparative anatomy * Molecular similarities * Embryology * Biogeography What are fossils? Preserved remains or traces of organisms that lived in the past. What is homologous anatomy? Similar body structures inherited from a common ancestor, even if they serve different functions. What is an example of homologous structures? The forelimbs of humans, whales, bats, and cats. What is analogous anatomy? Structures that perform similar functions but evolved independently and do not come from the same ancestral structure. What is an example of analogous structures? The wings of birds and insects. What is biogeography? The study of where organisms live and how their geographic distribution relates to evolution. How can DNA provide evidence for evolution? Organisms with more similar DNA sequences often share a more recent common ancestor. 7. Speciation What is speciation? The formation of new species. What is reproductive isolation? When populations can no longer successfully reproduce with one another. What is geographic isolation? When physical barriers separate populations, such as mountains, rivers, or oceans. What is allopatric speciation? Speciation that occurs when populations are geographically separated. What is sympatric speciation? Speciation that occurs without geographic separation. Unit 3: Classification, Taxonomy, and Phylogeny 1. Classification What is taxonomy? The science of naming and classifying organisms. What is systematics? The study of biological diversity and evolutionary relationships. What is binomial nomenclature? The two-part scientific naming system for organisms. What are the two parts of a scientific name? Genus and species. How should scientific names be written? The genus is capitalized, the species name is lowercase, and both are italicized. Example: Homo sapiens. What are the main taxonomic levels from broadest to most specific? * Domain * Kingdom * Phylum * Class * Order * Family * Genus * Species What are the three domains of life? * Bacteria * Archaea * Eukarya 2. Phylogenetic trees What is a phylogenetic tree? A diagram showing evolutionary relationships among organisms. What does a branch point represent? A common ancestor where evolutionary lineages split. What is a common ancestor? An ancestral organism or population from which two or more groups evolved. What are sister taxa? Two groups that share an immediate common ancestor. What does a node represent on a phylogenetic tree? A branching point representing a common ancestor. Does being next to another organism on a tree always mean they are closely related? No. Relationships are determined by shared branch points, not simply by how close the names appear. What is a clade? An ancestor and all of its descendants. What is a derived trait? A trait that evolved in a particular lineage and can help identify relationships among organisms. Unit 4: Prokaryotes, Eukaryotes, Bacteria, and Archaea 1. Cell types What are prokaryotic cells? Cells that do not have a nucleus or membrane-bound organelles. What are eukaryotic cells? Cells that have a nucleus and membrane-bound organelles. What organisms are prokaryotes? Bacteria and Archaea. What organisms are eukaryotes? Animals, plants, fungi, and protists. What is the main difference between prokaryotic and eukaryotic cells? Eukaryotic cells have a nucleus and membrane-bound organelles. Prokaryotic cells do not. Where is DNA located in a prokaryotic cell? In a region called the nucleoid. What is the function of the cell membrane? It controls what enters and leaves the cell. What is the function of ribosomes? They make proteins. 2. Bacteria and Archaea What are bacteria? Single-celled prokaryotic organisms found in many environments. What are Archaea? Single-celled prokaryotic organisms that are genetically and chemically distinct from bacteria. What is binary fission? A form of asexual reproduction in which one cell divides into two cells. Do bacteria and archaea have a nucleus? No. What is a bacterial cell wall commonly made of? Peptidoglycan. What is peptidoglycan? A material that provides structure and support to bacterial cell walls. 3. Gram-positive and Gram-negative bacteria What are Gram-positive bacteria? Bacteria with a thick peptidoglycan cell wall that usually stain purple during Gram staining. What are Gram-negative bacteria? Bacteria with a thinner peptidoglycan layer and an outer membrane that usually stain pink or red during Gram staining. What is the major difference between Gram-positive and Gram-negative bacteria? Gram-positive bacteria have thick peptidoglycan walls, while Gram-negative bacteria have thin peptidoglycan walls and an outer membrane. 4. Endosymbiotic theory What is the endosymbiotic theory? The theory that mitochondria and chloroplasts originated from free-living bacteria that were taken into ancestral eukaryotic cells. What organelles are explained by endosymbiotic theory? Mitochondria and chloroplasts. What evidence supports endosymbiotic theory? * They contain their own DNA. * They have their own ribosomes. * They divide in a way similar to bacteria. * They have double membranes. What is the function of mitochondria? They produce most of the cell’s ATP through cellular respiration. What is the function of chloroplasts? They carry out photosynthesis in plants and some other organisms. 5. Protists and fungi What are protists? A diverse group of eukaryotic organisms that do not fit into the traditional plant, animal, or fungi kingdoms. Are all protists single-celled? No. Many are single-celled, but some are multicellular. What are fungi? Eukaryotic organisms that absorb nutrients from their surroundings. What is the cell wall of fungi made of? Chitin. What are examples of fungi? * Mushrooms * Molds * Yeasts How do fungi obtain nutrients? They release digestive enzymes into their surroundings and absorb the broken-down nutrients. What is the role of decomposers? They break down dead organisms and recycle nutrients into the environment. Unit 5: Plants 1. Plant characteristics What are the major characteristics of plants? Plants are multicellular eukaryotes that generally have chloroplasts, cellulose cell walls, and carry out photosynthesis. What is photosynthesis? The process of using light energy to convert carbon dioxide and water into sugars and oxygen. What is the function of chlorophyll? It absorbs light energy for photosynthesis. What is the function of roots? They absorb water and minerals and help anchor the plant. What is the function of stems? They support the plant and transport materials. What is the function of leaves? They are the main organs where photosynthesis occurs in most plants. 2. Alternation of generations What is alternation of generations? A plant life cycle that alternates between two multicellular stages: the haploid gametophyte and the diploid sporophyte. What is a gametophyte? The haploid stage that produces gametes. What is a sporophyte? The diploid stage that produces spores through meiosis. What does haploid mean? Having one set of chromosomes, represented by . What does diploid mean? Having two sets of chromosomes, represented by . What is fertilization? The joining of two gametes to form a diploid zygote. What is meiosis? A type of cell division that reduces the chromosome number by half and produces haploid cells. What is the difference between spores and gametes? Spores can develop into a new organism without fusing with another cell. Gametes must fuse during fertilization to form a zygote. 3. Major plant groups What are the major groups of plants? * Nonvascular plants * Seedless vascular plants * Gymnosperms * Angiosperms What are nonvascular plants? Plants that lack specialized vascular tissues for transporting water and nutrients. What are examples of nonvascular plants? Mosses and liverworts. What are vascular plants? Plants that have specialized tissues to transport water, minerals, and sugars. What are the two major vascular tissues? * Xylem * Phloem What is the function of xylem? It transports water and minerals from the roots toward the rest of the plant. What is the function of phloem? It transports sugars and other organic nutrients throughout the plant. What are seedless vascular plants? Vascular plants that reproduce using spores instead of seeds. What is an example of a seedless vascular plant? Ferns. What are gymnosperms? Seed-producing plants with seeds that are not enclosed within fruits. What is an example of a gymnosperm? Pine trees. What are angiosperms? Flowering plants that produce seeds enclosed within fruits. What is the main difference between gymnosperms and angiosperms? Gymnosperms have exposed seeds, while angiosperms produce seeds enclosed in fruits. 4. Plant reproduction What is pollination? The transfer of pollen from the male reproductive structure to the female reproductive structure of a plant. What is pollen? A structure that carries the male gametophyte in seed plants. What is the purpose of flowers? Flowers are reproductive structures of angiosperms. What develops into a fruit? The ovary of a flower. What develops into a seed? The ovule after fertilization. What is the purpose of seeds? They protect and provide resources for the developing plant embryo. Unit 6: Animals 1. Animal characteristics What are the major characteristics of animals? Animals are multicellular eukaryotes that obtain nutrients by consuming other organisms or organic material. They do not have cell walls. Are animals prokaryotic or eukaryotic? Eukaryotic. Are animals unicellular or multicellular? Multicellular. Are animals autotrophs or heterotrophs? Heterotrophs. What is a heterotroph? An organism that obtains energy and nutrients by consuming other organisms or organic material. 2. Animal body plans What is symmetry? The arrangement of body parts around an axis or center. What is asymmetry? A body shape that cannot be divided into matching halves. What is radial symmetry? A body arrangement in which body parts are organized around a central axis. What is an example of an animal with radial symmetry? A jellyfish. What is bilateral symmetry? A body arrangement that can be divided into approximately equal left and right halves. What is an example of an animal with bilateral symmetry? A human. What is cephalization? The concentration of sensory organs and nervous tissue toward the front or head region of an animal. What is a body cavity? A fluid-filled space within an animal’s body that can contain and protect internal organs. 3. Major animal groups What are sponges? Simple aquatic animals that lack true tissues and organs. What is the scientific phylum for sponges? Porifera. How do sponges obtain food? They filter small food particles from water flowing through their bodies. What are cnidarians? Aquatic animals with specialized stinging cells. What is the scientific phylum for cnidarians? Cnidaria. What are examples of cnidarians? * Jellyfish * Corals * Sea anemones What are cnidocytes? Specialized stinging cells used for capturing prey and defense. What are arthropods? Animals with segmented bodies, jointed appendages, and an external skeleton. What is an exoskeleton? A hard external structure that supports and protects an animal’s body. What are examples of arthropods? * Insects * Spiders * Crabs * Lobsters What is molting? The process of shedding an old exoskeleton so an arthropod can grow. What are the major animal groups covered in this section? * Porifera: Sponges * Cnidaria: Jellyfish, corals, and sea anemones * Arthropoda: Insects, spiders, and crustaceans Note: Your lecture material did not provide a complete list of characteristics for every animal phylum, so I have not added unsupported details to those sections. Unit 7: Biotechnology 1. Biotechnology basics What is biotechnology? The use of living organisms, cells, or biological processes to develop useful products and technologies. What is genetic engineering? The process of directly changing an organism’s DNA. What is recombinant DNA? DNA made by combining genetic material from different sources. What is a plasmid? A small circular DNA molecule commonly found in bacteria. Why are plasmids useful in biotechnology? They can be used to carry selected genes into cells. 2. PCR What does PCR stand for? Polymerase chain reaction. What is PCR used for? To make many copies of a specific DNA segment. What are the three main stages of PCR? * Denaturation * Annealing * Extension What happens during denaturation? The DNA strands separate. What happens during annealing? Primers attach to complementary DNA sequences. What happens during extension? DNA polymerase adds nucleotides to build new DNA strands. 3. Gel electrophoresis What is gel electrophoresis? A laboratory technique used to separate DNA fragments based on size. How does gel electrophoresis separate DNA? An electric current moves DNA fragments through a gel. Smaller fragments generally travel farther than larger fragments. Why does DNA move toward the positive end of the gel? DNA has a negatively charged phosphate backbone. What can gel electrophoresis help scientists do? Compare DNA fragments and examine DNA samples. 4. Restriction enzymes and cloning What are restriction enzymes? Enzymes that cut DNA at specific sequences. What is DNA cloning? The process of making copies of a DNA segment or gene. What is a GMO? A genetically modified organism whose genetic material has been altered using genetic engineering or other genetic modification methods. What is a transgenic organism? An organism that contains genetic material introduced from another species. What is CRISPR? A gene-editing technology that allows scientists to make targeted changes to DNA. What is gene therapy? A medical approach that aims to treat or prevent disease by changing genetic material in a person’s cells. What is genomics? The study of an organism’s entire genome. What is proteomics? The study of the proteins produced by a cell, tissue, or organism. Practice Questions: Multiple Choice The answer is immediately underneath each question. Try answering before reading it. 1. What is the basic building block of DNA? A. Amino acid B. Nucleotide C. Protein D. Lipid Answer: B. Nucleotide 2. Which base pairs with adenine in DNA? A. Guanine B. Cytosine C. Thymine D. Uracil Answer: C. Thymine 3. Which enzyme separates DNA strands during replication? A. Ligase B. Helicase C. RNA polymerase D. Ribosome Answer: B. Helicase 4. What is the purpose of DNA replication? A. To create proteins B. To make RNA C. To copy DNA before cell division D. To destroy old DNA Answer: C. To copy DNA before cell division 5. What is the process of making mRNA from DNA called? A. Translation B. Transcription C. Replication D. Mutation Answer: B. Transcription 6. Where does translation occur? A. Nucleus B. Ribosome C. Cell membrane D. Golgi apparatus Answer: B. Ribosome 7. What does tRNA carry? A. DNA B. Glucose C. Amino acids D. Lipids Answer: C. Amino acids 8. What is the start codon? A. UAA B. AUG C. UGA D. UAG Answer: B. AUG 9. What is evolution? A. An individual changing during its lifetime B. A population changing genetically over generations C. An organism growing larger D. A cell dividing Answer: B. A population changing genetically over generations 10. Who is associated with evolution by natural selection? A. Gregor Mendel B. Charles Darwin C. Louis Pasteur D. Robert Hooke Answer: B. Charles Darwin 11. What is genetic drift? A. A random change in allele frequencies B. The movement of water C. The creation of proteins D. The copying of DNA Answer: A. A random change in allele frequencies 12. What is gene flow? A. DNA replication B. Movement of alleles between populations C. Protein synthesis D. Natural death Answer: B. Movement of alleles between populations 13. Which equation represents Hardy-Weinberg allele frequencies? A. B. C. D. Answer: B. 14. What are the three domains of life? A. Plants, animals, fungi B. Bacteria, Archaea, Eukarya C. Mammals, reptiles, birds D. Protists, fungi, plants Answer: B. Bacteria, Archaea, Eukarya 15. Which cells do not have a nucleus? A. Eukaryotic B. Prokaryotic C. Animal D. Plant Answer: B. Prokaryotic 16. What is the function of mitochondria? A. Protein storage B. ATP production C. DNA protection D. Photosynthesis Answer: B. ATP production 17. What is the cell wall of fungi made of? A. Cellulose B. Peptidoglycan C. Chitin D. Starch Answer: C. Chitin 18. What tissue transports water in plants? A. Phloem B. Xylem C. Epidermis D. Pollen Answer: B. Xylem 19. What is the function of phloem? A. Transport sugars B. Absorb sunlight C. Produce pollen D. Protect seeds Answer: A. Transport sugars 20. Which plants produce flowers? A. Mosses B. Ferns C. Gymnosperms D. Angiosperms Answer: D. Angiosperms 21. What is the scientific phylum for sponges? A. Cnidaria B. Porifera C. Arthropoda D. Chordata Answer: B. Porifera 22. What do arthropods have? A. Jointed appendages and an exoskeleton B. No body structure C. Only soft bodies D. Chloroplasts Answer: A. Jointed appendages and an exoskeleton 23. What is PCR used for? A. Separating proteins B. Copying DNA C. Producing ATP D. Growing plants Answer: B. Copying DNA 24. What does gel electrophoresis separate DNA by? A. Color B. Shape only C. Fragment size D. Temperature Answer: C. Fragment size 25. What is CRISPR used for? A. Editing DNA B. Separating cells C. Making ATP D. Producing pollen Answer: A. Editing DNA Fill-in-the-Blank Practice 1. DNA stands for __________. Answer: Deoxyribonucleic acid. 2. RNA uses __________ instead of thymine. Answer: Uracil. 3. The enzyme that unzips DNA is __________. Answer: Helicase. 4. The enzyme that connects Okazaki fragments is __________. Answer: DNA ligase. 5. The process of making RNA from DNA is called __________. Answer: Transcription. 6. The process of making proteins from mRNA is called __________. Answer: Translation. 7. A group of three mRNA bases is called a __________. Answer: Codon. 8. The movement of alleles between populations is called __________. Answer: Gene flow. 9. Random changes in allele frequencies are called __________. Answer: Genetic drift. 10. The formation of new species is called __________. Answer: Speciation. 11. The three domains are Bacteria, Archaea, and __________. Answer: Eukarya. 12. The cell wall of fungi contains __________. Answer: Chitin. 13. The plant tissue that transports water is __________. Answer: Xylem. 14. The plant tissue that transports sugars is __________. Answer: Phloem. 15. Flowering plants are called __________. Answer: Angiosperms. 16. The haploid plant stage is called the __________. Answer: Gametophyte. 17. The diploid plant stage is called the __________. Answer: Sporophyte. 18. Sponges belong to the phylum __________. Answer: Porifera. 19. Jellyfish belong to the phylum __________. Answer: Cnidaria. 20. The process used to make many copies of DNA is called __________. Answer: PCR. Important Terms to Memorize Term Meaning DNA Stores genetic information RNA Helps make proteins Nucleotide Building block of DNA and RNA Helicase Separates DNA strands DNA polymerase Builds new DNA DNA ligase Connects DNA fragments Transcription DNA to RNA Translation RNA to protein Codon Three mRNA bases Mutation Change in DNA Evolution Change in inherited traits in a population over generations Natural selection Differences in reproductive success based on inherited traits Genetic drift Random allele frequency change Gene flow Movement of alleles between populations Speciation Formation of new species Taxonomy Naming and classifying organisms Phylogeny Evolutionary relationships Prokaryote Cell without a nucleus Eukaryote Cell with a nucleus Mitochondria ATP production Chloroplast Photosynthesis Xylem Transports water Phloem Transports sugars Gametophyte Haploid plant generation Sporophyte Diploid plant generation Angiosperm Flowering plant Gymnosperm Plant with exposed seeds PCR Makes copies of DNA Gel electrophoresis Separates DNA fragments by size CRISPR Gene-editing technology Final Cram Sheet: What You Should Know Before Your Exam DNA and genetics * DNA: A–T and C–G * RNA: A–U and C–G * Helicase: unzips DNA * DNA polymerase: builds DNA * Ligase: joins DNA fragments * Transcription: DNA → RNA * Translation: RNA → protein * AUG: start codon * UAA, UAG, UGA: stop codons Evolution * Darwin: natural selection * Mutation: changes DNA * Genetic drift: random change * Gene flow: movement between populations * Bottleneck: population becomes much smaller * Founder effect: small group starts a population * Speciation: new species form * Hardy-Weinberg: , Classification and cells * Three domains: Bacteria, Archaea, Eukarya * Prokaryotes: no nucleus * Eukaryotes: have a nucleus * Mitochondria: ATP * Chloroplasts: photosynthesis * Fungi: chitin cell walls * Bacteria: peptidoglycan cell walls Plants * Xylem: water * Phloem: sugar * Gametophyte: haploid * Sporophyte: diploid * Gymnosperms: exposed seeds * Angiosperms: flowers and enclosed seeds * Mosses: nonvascular * Ferns: seedless vascular Animals and biotechnology * Porifera: sponges * Cnidaria: jellyfish, corals, sea anemones * Arthropoda: jointed appendages and exoskeleton * PCR: copies DNA * Gel electrophoresis: separates DNA by size * Restriction enzymes: cut DNA * CRISPR: edits DNA Study tip: Cover the answers with a piece of paper and try to answer every question from memory. Then uncover the answer and check yourself. Focus especially on DNA replication, transcription versus translation, Hardy-Weinberg equations, evolution mechanisms, plant life cycles, and the differences between prokaryotic and eukaryotic cells.
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29. An introduction to A Level organic chemistry Formulas, Fn groups, Naming Functional groups and formulae Functional group: atom/group of atoms in an organic molecule that determines its characteristic chemical and physical properties Arenes: aromatic compounds that contain a benzene ring chemical properties Compound can undergo Electrophilic attack: is e- rich due to π system of delocalised e- Resistant to addition reactions: delocalised e- ring system makes benzene stable physical properties b.p 80 C: Benzene has id-id forces of attraction between the molecules Insoluble in water: non-polar hydrocarbons in arene (not energetically favourable for benzene to break many H bonds between water molecules to be soluble) Halogenoarenes: aromatic compounds containing halogen bonded to benzene ring chemical properties Prone to Electrophilic attack can take part in substitution reactions physical properties Chloro, broom, iodo benzene liquid at r.t with oily texture b.p. Increases down group: larger halogen = more e- = stronger id-id forces = more energy to separate insoluble in water: non-polar hydrocarbon ring Phenols: aromatic compounds containing a hydroxide bonded to benzene ring chemical properties acidic: O in -OH donates a lone pair into ring (more acidic than alcohols) = increased e- density in ring = more reactive = easier for H to be donated react with reactive metals (e.g. Na) to form phenoloxide ions and H gas physical properties White, crystallline solid disinfectant-like smell soluble in water: can form H bonds with water due to -OH group Acyl chlorides: carboxylic acid derivatives containing a chlorine atom, and an acyl group attached to C=O chemical properties colourless extremely reactive and readily takes part in substitution (Cl substituted ) fuming liquids with strong smell: react with water vapor in air Physical properties react violently with water (cannot determine its solubility with water ) Amines: compounds with -NH2 (primary), -NH (2 °) , or -N (3 ° ) amine group chemical properties basic compounds: due to lone pair of e- on nitrogen physical properties lone pair on N can form H bonds soluble in water: form H bond with water solubility ↓ as nonpolar hydrocarbon chain gets longer / molecule gets bigger fishy smell Amides: compounds containing amine group (-NH2) carbonyl group (C=O) amide group -CONH2 chemical properties less basic than amides: lone pair of e- on N is delocalised physical properties soluble in water: form H bonds with water solubility ↓ as nonpolar hydrocarbon chain gets longer / molecule gets bigger Amino Acids: building blocks of proteins, consisting amine group (-NH2) and carboxylic group (-COOH) chemical properties react with bases to form salts react with alcohols to form esters react with amines to form amides physical properties most are soluble in water but insoluble in organic solvents most have chiral centres, exhibit optical isomers Formulae of Organic Compounds Nomenclature of Compounds Naming organic compounds Identify longest C chain containing the functional group Identify fn group on the chain to determine the suffix or prefix on the compound Count along the carbon chain such that the functional group has the lowest number Add any side chains or lower priority functional groups as prefixes to the beginning of the name in alphabetic order Use the prefixes di-, tri- and tetra- if there are two or more identical functional groups or side chains Characteristic organic reactions Electrophilic substitution Electrophile: e- loving species they are e- deficient and acts as e- pair acceptor Substitution reactions: reactions replacing 1 atom / group by another Electrophilic substitution: group / atom replaced by an electrophile e.g. bromine electrophile attacks e- - rich benzene ring Addition-elimination (nucleophilic) nucleophilic addition of small molecule followed by elimination of small molecule includes hydrolysis reaction of alcohols to form esters reaction with ammonia and 1° amines to form amides e.g. Hydrolysis of acyl chlorides Hydrolysis - acyl chloride to carboxylic acid water molecule adds across C=O bond HCL eliminated Ester formation - acyl chlorides + alcohol Alcohol adds across the C=O bond HCl molecule is eliminated Amide formation - acyl chloride + 1° amines + conc ammonia amine or ammonia adds across C=O bond (lone pair on N attacks carbonyl C atom in acyl chloride) HCl eliminated Shapes of aromatic organic molecules Aromatic molecules consist of one or more rings with conjugated π systems Conjugated π systems arise from alternating double and single bonds in which the electrons are delocalised Shape of benzene and aromatic compounds - why are they more stable? Benzene and other aromatic compounds are planar and regular because each carbon atom is sp² hybridised. Each C forms three σ bonds in a trigonal planar arrangement with bond angles of 120°. The remaining unhybridised p orbital on each carbon overlaps sideways with neighbouring p orbitals to form a continuous, delocalised π system above and below the ring. Because the π electrons are delocalised over the whole ring, all the C–C bonds are identical and have intermediate character between a single and double bond. This is why benzene is unusually stable. Why are benzene more stable? delocalised π electrons above and below the ring Optical isomerism, Chirality and drug production Stereoisomers: same structural formula, diff arrangement in space (geometrical, optical) Optical 4 diff groups of / atoms central chiral carbon chiral molecules exist as 2 optical isomers / enantiomers non-superimposable mirror images same physical / chemical properties rotate in opposite directions in plane polarised light (1 clockwise 1 anticlockwise ) Similarities of enantiomers differences in enantiomers same physical and chemical properties differ from ability to rotate plane polarised light and biological activity nonsuperimposable mirror images Biological activity of enzymes enzymes are chiral proteins, bond to specific active site for biological response mirror image of enantiomer will not bind to same active site as it is not the same shape, no biological response Optical activity and Racemic mixtures reaction mixture is optically active if there is an uneven mixture of each enantiomer (e.g. 20% rotates clockwise, 80% rotates anticlockwise, net effect is plane of polarised light rotates anticlockwise) racemic mixture: equal amounts of enantiomers present in soln optically inactive as enantiomers cancel out each others effect, plane polarised light not changed the rotation of plane polarised light can be used to determine the identity of an optical isomer e.g. pass plane polarised light through a sample containing one of the two optical isomers of a single substance Depending on which isomer sample contains, the plane polarised light will be rotated clockwise / anti-clockwise clockwise rotation: R enantiomer anticlockwise rotation: S enantiomer No effect will be observed when the sample is a racemic mixture Chirality and Drug production most drugs to treat disease have 1+ chiral centres and can ∴exist as enantiomers diff in biological activity in enantiomers means difference in effectiveness as medicine drugs should be prepared so that only 1 optical isomer produced, to ↑ effectiveness Potential different biological activity of enantiomers e.g. drug naproxen treats pain from arthritis 1 enantiomer eases pain 1 enantiomer causes liver damage separate racemic mixture into 2 pure enantiomers due to difference in biological activities reduce side effects ↓ dosage by half, reduces production cost chiral catalysts to produce 1 pure optical isomer only small amount chiral catalysis needed + reused e.g. enzyme 30. Hydrocarbons - Arenes Reactions of arenes substitution halogenation nitration Friedel-Craft's alkylation Friedel-Craft's acylation other reaction Complete Oxidation Hydrogenation Electrophilic substitution electrophile: e- pair acceptor, attracted to delocalised e- substitution: 1+ H replaced by a fn group generating electrophile+ using catalyst Electrophilic attack on benzene ring (electrophile accepts 2 π e- , +ve charge remains) regenerating aromaticity by heterolytically cleavage of C-H bond (bonding pair foes into benzene π system) Addition reactions of arenes arenes undergo substitution due to delocalisation of e-, aromaticity restored by heterolytic cleavage of C-H bond in addition, aromaticity / stability not restored (e.g. hydrogenation), Hydrogenation of benzene is less exothermic than expected for three isolated C=C bonds, because the aromatic stabilisation of benzene is lost Halogenation (in the aromatic ring) reactants: Cl2 / Br2 (Cl+ / Br+ electrophile) , arene conditions: rt and pressure catalyst: anhydrous AlCl3 / AlBr3 (catalyst needed due to stability of benzene structure) formation: AlCl3 + Cl2 ⇒ AlCl4- + Cl+ reformation: H+ + AlCl4- ⇒ AlCl4 + HCl product: halogenoarenes / aryl halide In halogenation of Alkylarenes, e- donating alkyl group activates positions 2, 4 (as well as OH-, NH2). forms 2 products multiple substitutions when excess halogen used Halogenation (of alkylarenes) in side chain free radical substitution reaction reactants: halogen, boiling alkyl arene conditions: UV light if excess halogen: all H on alkyl side chain will be substitution by X atoms Nitration reactants: conc HNO3 (NO2+ electrophile), arene conditions: 20-60 ° C (higher = more NO2+ substituted) catalyst: conc H2SO4 formation: HNO3 + H2SO4 ⇒ NO2+ + 2HSO4- + H3O+ reformation: H+ + HSO4- ⇒ H2SO4 In nitration of Alkylarenes, e- donating alkyl group activates positions 2, 4 Friedel-Crafts alkylation substitution of alkyl chain reactant: chloroalkane (CH3CH2+ electrophile), arene condition: heat under reflux catalyst: anhydrous AlCl3 formation: AlCl3 + CH3CH2Cl ⇒ CH3CH2+ + AlCl4- reformation: AlCl4- + H+ ⇒ AlCl3 + HCl Friedel-Crafts acylation substitution of an acyl group (group containing carbonyl, C=O ) reactant: acyl chloride (CH3CH2CO+ electrophile) conditions: heat under reflux catalyst: anhydrous AlCl3 formation: AlCl3 + CH3CH2COCl ⇒ CH3CH2C=O+ + AlCl4- reformation: AlCl4- + H+ ⇒ AlCl3 + HCl Complete oxidation of side chains alkyl side-chains in alkyl arenes are oxidised to carboxylic acids when refluxed with alkaline KMnO4 and then acidified with dilute H2SO4 reactants: hot alkaline KMnO4, dilute H2SO4, alkyl arenes conditions: heat under reflux Hydrogenation addition reaction to form cyclohexane reactants: H2 gas conditions: heat (200 ° C at 30 atm ) catalyst: Pt/Ni Directing effects of substituents on arenes substituents: already on arene that direct substitution reactions to diff. ring positions E- withdrawing groups / substituents e- donating groups / substituents remove e- density from π system in benzene ring deactivating groups (slow attack by e+) directs e+ to positions 3, 5 e.g. COOH, X, NO2 donate e- density into π system of benzene ring activating groups (allow e+ to react faster) directs e+ to positions 2, 4, 6 e.g R, NH2, OH 31. Halogen compounds Halogenoarenes: arenes bonded to X atoms Producing halogenoarenes substitution reactions of arenes with chlorine or bromine in presence of anhydrous AlCl3 catalyst reactants: Cl2 / Br2 (Cl+ / Br+ electrophile) , arene conditions: rt and pressure catalyst: anhydrous AlCl3 / AlBr3 (catalyst needed due to stability of benzene structure) formation: AlCl3 + Cl2 ⇒ AlCl4- + Cl+ reformation: H+ + AlCl4- ⇒ AlCl4 + HCl product: halogenoarenes / aryl halide Substitution of benzene Substitution of methylbenzene substitution of 6 position only occurs in excess chlorine Reactivity of halogenoarenes Why are aryl halides less reactive than haloalkanes? C-H bond in aryl halides is stronger due to the partial overlap of lone pairs on halogen atom with the π system in the benzene ring C-H bond ∴ has a partial double bond character 32. Hydroxy compounds Reactions of alcohols Formation of esters reaction: addition-elimination (esterification) reactants: alcohols/phenols, acyl chlorides nucleophile: OH- (attacks e- deficient carbonyl (COCl) C ) COCl bond breaks, Cl is substituted, HCl fumes formed Why are esters formed from acyl chlorides rather than from C. acids? more effective to form esters from acyl chlorides acyl chlorides are more reactive (produce esters faster) acyl chloride reactions go to completion (more ester formed) Esterification using phenols additional reactants: base (e.g. NaOH) base: deprotonate phenol to form phenoxide ion phenoxide better nucleophile than phenol, attack on carbonyl C occurs more readily Phenol phenol: benzene ring with -OH group attached Production of Phenol From reaction of phenylamine with nitrous acid (HNO3) reactants: NaNO2, dilute acid (to form HNO2), phenylamine conditions: ice (under 10 ° C) step 1 and 2, heat step 3 forming nitrous acid NaNO2 + HCl ⇒ (ice) HNO2 + NaCl forming unstable diazonium salt forming phenol via thermal decomposition (due to instability) reactions of phenol Many reactions due to e- rich benzene ring and polar -OH group with bases with reactive metals with diazonium salts nitration bromination Acid-base reactions Acid-base reaction of phenols with base -OH: slightly acidic (weak acids), act as acid in acid-base reaction dissolve in alkaline soln forming phenoxide salt and water Acid-base reaction of molten phenols with reactive metals forms soluble phenoxide salt and H2 gas Reaction with diazonium ions diazonium ions very reactive due to -N2+ group acid-base reaction conditions: ice for cold diazonium ion added to phenoxide ion Reactions of the aromatic ring phenols react more readily with e+ than benzene due to one lone pair of e- on O in -OH overlaps with π bonding system, ↑ e- density of phenol’s benzene ring and making it more susceptible to electrophilic attack -OH activates ring, directs e+ to 2, 4, 6 positions Nitration of phenols electrophilic substitution reaction reactant: dilute HNO3, phenol when conc HNO3 used, product is 2, 4, 6- trinitrophenol conditions: rt milder conditions as phenol is more reactive Bromination of phenols electrophilic substitution reaction reactants: bromine water, phenol conditions: rt phenol decocolourises orange bromine soln to form 2, 4, 6 - tribromophenol (white ppt) as phenol is more reactive, no need for anhydrous AlBr3 catalyst, can react with bromine water Reactions of other phenolic compounds (contain phenol functional group, e,g, 1-naphthol) -OH group is also e- donating, activates benzene ring to electrophilic substitution reactions, e+ directed to 2, 4 positions (on phenol) C in position 6 shared by both rings, no H atom = no substitution can react in similar way as phenol Acidity of phenols Phenols are weak acids phenols react more readily with e+ than benzene due to one lone pair of e- on O in -OH overlaps with π bonding system, ↑ e- density of phenol’s benzene ring and making it more susceptible to electrophilic attack Phenol’s conjugate base is the phenoxide ion. -ve charge is delocalised over the entire ion as a lone pair on O overlaps with the ring’s delocalised π system, which reduces charge density on oxygen H⁺ ions are ∴ less strongly attracted to phenoxide ion, so phenol is less likely to reform Therefore, phenol is more likely to lose H⁺ and act as an acid Stability of conjugate base phenoxide more stable as -ve charge spread out, so phenol more likely undergo ionisation eqm shifts right, more phenol donate H+ (act as acid) Relative acidities of water, phenol, ethanol smaller pKa = stronger acid order of acidity explained by conjugate bases Delocalisation of charge density phenoxide (conjugate base of phenol): charge density of O is spread out over ion, O less available for bond formation with H+ ethoxide (conjugate base of ethanol): ethyl group is e- donating, donates e- density to O atom, O more available for bond formation with H+ hydroxide (conjugate base of water): charge density of O cannot become delocalised over a ring, OH- more readily accepts H+ than phenoxide no e- donating alkyl groups to O, less -ve O, O less readily accepts H+ compared to ethoxide Overall conjugate base more readily accepts H+ = stronger conjugate base = weaker acid strong acid eqm shifts right favouring dissociated ions and H+ 33. Carboxylic acids and derivatives Benzoic acid: C6H5COOH can be used to synthesize esters Carboxylic acids Production of benzoic acid formation of benzoic acid from Oxidation of alkylbenzenes alkylbenzene heated under reflux with hot alkaline KMnO4, then acidified with dilute acid to protonate carboxylate salt and form benzoic acid reactants: hot alkaline KMnO4 (oxidising agent), dilute acid (e.g. HCl), alkylbenzene purple Mn2+ turns colourless as reduced to Mn4+ brown ppt MnO2 formed conditions: heat under reflux Reactions of Carboxylic acids Reactions of C, acids to form acyl chlorides reactants PCl5 (s) PCl3 (l) + heat SOCl2 (l) Forming carboxylic acids from oxidation of 1 ° alcohols alcohol ⇒ aldehyde ⇒ c. acid Further oxidation of c. acids such as methanoic and ethanedioic acid methanoic acid (strong reducing agent) gets further oxidised to CO2 by warming with mild oxidising agents like Fehling’s or Tollen’s reagent Fehlings: Cu2+ reduced to Cu+, form red ppt Cu2O Tollens: Ag+ reduced to Ag using stronger oxidising agents like acidified KMnO4 or acidified K2Cr2O7 KMnO4: purple soln turns colourless as Mn7+ reduced to Mn2+ K2Cr2O7: orange soln turns green as the Cr6+ reduced to Cr3+ ions Ethanedioic acid gets further oxidised to CO2 Conditions: Strong oxidised agent - warm acidified KMnO4 needed Relative acidities of C. acids, Phenols, and alcohols C acids can lose H+ in aq soln to form carboxylate salts and water Acidities of C. acids longer C chain = weaker acid inductive effect ↑ -ve charge on COO- group More substituted Cl atoms = stronger acid Cl atoms withdraw e- density from the –COOH group, weakening the O–H bond and stabilise carboxylate ion (reducing the -ve charge density on it) The more stable the carboxylate ion, the less likely it is to attract H⁺ and reform the O–H bond Acidities of c. acids, phenols, alcohols acidities explained by strength of O-H bond and stability of conjugate bases of acids Strength of O-H bond carboxylic acids e- in O-H bond drawn towards C-O bond, e- in C-O bond drawn to C=O bond O-H bond weakened due to C=O withdrawing e- density from it for itself easier to act as acid and lose H+ from OH alcohols lack e- withdrawing C=O group, O-H bond not weakened harder to act as acid and lose H+ Stability of conjugate bases carboxylate ion (c base of carboxylic acid) charge density on O spread over ion because charge is delocalised on an electronegative carbonyl O atom O less available for bond formation with H+ to reform -COOH eqm shifts right, C base more stable than carboxylic acid alkoxide ion (c base of alcohol) alkyl is e- donating group, donates e- density to O atom O more available for bond formation with H+ ion to reform OH lack ability to delocalised charge density on ion, c bases less stable than alcohols, weaker acids than c. acid and phenols eqm lies left phenoxide ion (c base of phenol) charge density of O spread out over ion due to delocalisation of e- (stabilises ion) O less available for bond formation with H+ Phenoxide more stable than phenol Phenoxide less stable than carboxylate since delocalisation of charge density is on C atoms, not electrogenative O atoms eqm lies more right than alcohols, more left than c. acids ethanol is weakest e- donating methyl group strengthens O-H bond methyl donates -ve charge to -COO-, more likely to accept H+ Esters - Production Esters: organic compounds with -COO- functions group nice smelling Naming esters alcohol acyl chloride / carboxylic acid e.g. Producing esters from alcohols and carboxylic acids condensation / esterification reaction Producing esters from alcohols and acyl chlorides more effective: acyl chlorides more reactive(faster), and reactions go to completion (no eqm, max yield) Acyl Chlorides Acyl chlorides: compounds with COCl fn group Production of acyl chlorides Carboxylic acid with solid PCl5 liquid PCl3 + heat liquid SOCl2 Reactions of acyl chlorides addition-elimination: addition of small molecule across C=O, followed by elimination of small molecule acyl chlorides under addition-elimination reactions such as hydrolysis to form carboxylic acid Reaction with alcohols and phenols to form esters Reaction with ammonia and amines to form amides General mechanism for addition-elimination reactions addition of nucleophile across C=O bond elimination of a small molecule such as HCl or H20 lone pair on nucleophile carries out initial attack on carbonyl carbon this is followed by the elimination of an HCl molecule Hydrolysis of acyl chlorides forms carboxylic acid and HCl water (nucleophile) adds across C=O bond HCl eliminated Formation of esters from acyl chlorides esterification reaction reactants: alcohol/phenol, acyl chloride conditions: rt reaction with phenol is slower than alcohol, base such as NaOH used to speed up reaction (deprotonates phenol to form phenoxide, better nucleophile to carry out attack) alcohol /phenol (nucleophile) adds across C=O bond, HCl / NaCl eliminated Formation of amides from acyl chlorides condensation reaction: nucleophile adds to C=O, Cl- eliminated, HCl formed reactants: ammonia or 1°/2 ° amines, acyl chloride nucleophile: Nitrogen (has lone pair of e- ) HCl formed is immediately neutralised by a 2nd molecule of ammonia / amine in excess, forming ammonium salt (e.g. NH4Cl, CH3NH3Cl) Relative ease of hydrolysis of aryl chlorides from most readily broken / easily hydrolysed acyl chloride > alkyl chloride > aryl chloride trend explained by strength of C-Cl bond acyl chlorides - hydrolysed at rt R-COCl C bonded to Cl is also bonded to O both Cl and O are very electronegative, pulling e- away from C, leaving it very δ+ C-Cl bond is weakened nucleophilic attack is more rapid alkyl chloride - hydrolysed by refluxing with strong alkali nucleophile R-C-Cl C bonded to Cl attached to 1 electronegative atom (Cl), pulls e- away from C C is not very δ+ (e- deficient) C-Cl bond is stronger than in acyl chlorides aryl chlorides - hydrolysis will not occur C bonded to Cl is part of delocalised π bonding system of benzene ring one lone pair of e- on Cl overlaps with delocalised system C-Cl bond has some double bond character, becoming stronger 34. Nitrogen compounds Primary and secondary amines 1 ° amines: organic compounds with NH2 fn group attached to an alkyl / aryl group 2 ° amines: organic compounds with group attached to a alkyl /aryl groups Naming -amine: after alkyl prefix (e.g. methyl amine) amino- : if another suffix present or branched/complex amines (e.g. amino methane) Production of Amines 1 ° and 2 ° amines prepared form diff reactions 1 ° amines: reaction of haloalkanes with ammonia reduction of nitriles reduction of amides 2 ° amines: reaction of haloalkanes with 1 ° amine Forming 1 ° amines from haloalkanes with ammonia nucleophilic substitution reaction reactants: excess, hot ethanolic ammonia nucleophile: N in ammonia (replaces X) conditions: heat under pressure Forming 1 ° amine from reduction of nitrile reactants: nitrile vapour, H2 gas conditions: LiAlH4 in dry ether (reducing agent), or Ni catalyst Forming 1 ° / 2 ° amines from reduction of amides reactants: LiAlH4 in dry ether (reducing agent) type of amine depends on nature of amide Forming 2 ° amines from haloalkanes with 1 ° amine nucleophilic substitution reaction reactants: 1 ° amine in ethanol nucleophile: N in 1 ° amine (replaces X) conditions: heat under pressure, sealed tube Reactions of Amines Condensation reaction between Acyl chloride and ammonia or amine produces Amides Cl in acyl chlorides is electronegative, draws e- density from carbonyl C C is e- deficient, attacked by nucleophile like N in ammonia and amines C-Cl bond broken, amide formed reaction with amines ⇒ substituted amide reaction with ammonia ⇒ nonsubstituted amide Why is acyl chloride a more effective reactant than carboxylic acids in formation of amides? c acids less reactive than acyl chloride reaction with c acids dosent fo to completion Basicity of aq soln of Amines and ammonia N in ammonia and amines can accept proton H+, can ∴ act as bases in aq soln (when donating lone pair to form dative bonds) Strength of bases strength of amine depends on availability of lone pair of e- on N to form a dative covalent bond with H+ lone pair more readily available to form dative bond = stronger base positive inductive effect ↑ basicity: alkyl groups donate e- density to N, causing lone pair to become more available delocalisation ↓ basicity: aromatic rings cause lone pair to be delocalised into benzene ring, causing lone pair to be less available Phenylamine and Azo compounds Phenylamine: organic compound with benzene ring and amine fn group Production of phenylamine 3 step synthesis, followed by separation / purification Nitration (forming nitrobenzene) reactants: benzene, conc HNO3 catalyst: conc H2SO4 conditions: 25-60 ° C Reduction (forming phenylamine ion) conditions: hot tin (Sn) and conc HCl under reflux Deprotonation (forming phenylamine) reactants: NaOH, phenylamine ion separation/purification phenylamine separated from reaction mixture by steam distillation Reactions of Phenylamine Both benzene ring and NH2 can take part in chemical reactions bromination of phenylamine formation of diazonium salt Bromination of phenylamine to form 2, 4, 6- tribromophenylamine electrophilic substitution reaction electrophile: N, donate e- density into benzene ring, ↑ e- density in benzene ring activates it, more readily attacked by electrophiles reactants: aqueous bromine, phenylamine conditions: rt Formation of diazonium salt (salt containing N2+ group) reactants: nitrous acid/HNO2, HCl, phenylamine HNO2 formed in test tube with NaNO2 and dilute HCl conditions: below 10 ° C diazonium salt forms phenol upon warming with water Azo compounds Azo compounds: organic compounds with R-N=N=R / azo group often used as dyes Diazonium compounds: contain N2+ group Formation of Azo compounds from coupling reaction of benzene diazonium chloride salt with phenol multi-step process forming nitrous acid reactants: NaNO2, HCl conditions: test tube, under 10 °C / ice NaNO2 + HCl ⇒(ice) HNO2 + NaCl Diazotisation reactants: phenylamine, HNO2, dilute HCl conditions: below 10 ° C / ice (prevent thermal decomposition of diazonium ion to phenol, N and HCl) coupling reaction reactants: phenol, diazonium ion (acts as electrophile, sub into benzene ring of phenol) conditions: alkaline conditions (NaOH deprotonates phenol to phenoxide, more reactive to e+) Why are azo compounds very stable? The delocalised e- in π bonding systems extend across both benzene rings and the –N=N– bridge Other days formed from similar route e.g. formation of yellow dye from coupling reaction between benzene diazonium chloride and C6H5N(CH3)2 Amides Amide: organic compounds with CONR2 amide group non-substituted / 1 ° amide: N bonded to 2H atoms substituted / 2 ° amide: 1 or both H replaced by a hydrocarbon group Production of Amides Formation of Amides from acyl chlorides / c. acid with ammonia / amine condensation reaction: nucleophile adds to C=O, Cl- eliminated, HCl formed nucleophile: Nitrogen (has lone pair of e- ) conditions: rt HCl formed is immediately neutralised by a 2nd molecule of ammonia / amine in excess, forming ammonium salt (e.g. NH4Cl, CH3NH3Cl) Reactions of Amides Amide group can undergo reactions Hydrolysis with aqueous alkali or aqueous acid Reduction with LiAlH4 Hydrolysis of amides to form c. acid and ammonia/ 1 ° amine conditions: reflux with aq acid / alkali products differ depending with amide is substituted nonsubstituted ⇒ c. acid + ammonia substituted ⇒ c. acid + 1 ° amine when refluxed in excess acid⇒ ammonium salt formed base⇒ carboxylate ion formed (deprotonation) Reduction of amides to form amine conditions: LiAlH4 reducing agent nonsubstituted amide ⇒ 1 ° amine + H2O substituted amide ⇒ 2 ° amine + H2O Relative basicity of Amides and Amines lone pair of e- more readily available for dative bonding = stronger base more e- =stronger base amides - weaker base e- withdrawing O in C=O causes lone pair on N to delocalise into C=O group, removed e- density from N lone pair on N less readily available for bonding amine - stronger base e- donating alkyl groups ↑ e- density on N lone pair on N more readily available for bonding Amino Acids Amino acids: organic compounds with 2 fn groups basic amino -NH2 group acidic carboxylic acid -COOH group due to presence of basic and acidic group, they are amphoteric (act as acid and base) R group can be acidic, basic, or neutral Acid-base properties of amino acids + formation of Zwitterion amino acids can undergo most reactions of amines and c. acids, including acid-base reactions (amine + acid, C. acid + base) Amino acids can interact intramolecularly to form zwitterion Zwitterion: ion with both +ve (NH3+) and -ve (COO-) charge formed from amino acids in water due to charges, there are strong intermolecular forces of attraction between amino acids this makes amino acids soluble crystalline solids Zwitterions act as buffer soln acid added: pH ↓ COO- accepts H+ to reform COOH, zwitterion becomes +vely charged base added: pH ↑ NH3+ donates H+ to reform NH2, zwitterion becomes -vely charged Isoelectric point: point at which charge = 0 / zwitterion is neutral a pH level unique to each amino acid due to R group Formation of Peptide bonds NH2 group of one amino acid can react with COOH group of another amino acid to form dipeptide condensation reaction: H2O eliminated peptide bond / link formed dipeptides can undergo condensation reaction again to form tripeptide ( 3 amino acids) polypeptide: many amino acids join to form long chain of molecules proteins are polypeptides Electrophoresis Analytical separation technique, separates ions by placing them in an electric field Sample of amino acids placed between 2 oppositely charged electrodes +ve ions move to -ve electrode -ve ions move to +ve electrode Rate of ion movement depends on size of ions (larger = slower) charge of ions (highly charged = quicker) Electropherogram: bands on gel after electrophoresis each band = particular species Amino acids can be separated according to charge and mass they are colourless, sprayed with ninhydrin (brown/purple stain) to show where they have gone to Changes in charge of amino acid due to pH of solution isoelectric point: no overall charge, no movement of zwitterions pH > isoelectric point: -ve charge, move to +ve electrode pH < isoelectric point: +ve charge, move to -ve electrode -ve charged amino acid: NH3+ donated H+, NH2 and COO- left +ve charged amino acid: COO- accepted H+, NH3+ and COOH left 35. Polymerisation Condensation Polymerisation - Forming polymers Forming polymers such as polyesters, polyamides, proteins Formation of polyesters addition polymerisation: monomers with C=C bonds join to form polymers condensation polymerisation: Small molecule is lost when monomers join together to form polyester polyesters have ester links Monomers for polyesters OH on dicarboxylic acid and H of diol expelled as H2O to form polyester diol (2 -OH) + dicarboxylic acid (2 -COOH) 2 hydroxy carboxylic acids (OH and COOH fn group) Formation of polyamides condensation polymerisation polyamides have peptide links Monomers for polyamides H on diamide and OH on dicarboxylic acid / Cl on dichloride expelled as H2O / HCl as polyamide forms diamide (2 -NH2) + dicarboxylic acid diamide + dichloride (2 -COCl) 2 aminocarboxylic acids (OH and COOH fn group) Making proteins/polypeptides from amino acid monomers (aminocarboxylic acid) amine group (-NH2) and carboxyl group (-COOH) of an amino acid polymerise with another amino acid forms peptide links proteins can be broken into its constituent amino acids through hydrolysis You can deduce the repeat units of a condensation polymer by identifying the linking between monomers chain of C: addition polymer ester link: polyester peptide link: polyamide You can identify monomers from small molecule expelled H2O: c acid H: amine Cl: dioyl chloride Predicting type of polymerisation Identifying type of polymerisation by looking at functional groups Addition polymerisation monomer contains C=C bond double bond opens up to add monomers to either side of starting polymer forms polyalkenes co-polymer: 2+ monomers used to make 1 repeating unit Condensation polymerisation makes polyamides and polyesters summary: Identifying type of polymerisation by considering structure of polymer backbone Addition polymerisation no fn groups on polymer backbone, usually chain of C atoms sidechains might branch off from backbone (e.g. benzene rings, nitrile groups (CN), halogens Condensation polymerisation backbone of polyesters contain ester links (-COO-) backbone of polyamides contain peptide links (-CONH-) Degradability of Polymers Polyalkenes and biodegradability polyalkenes are nonpolar and saturated, making them nonbiodegradable and chemically inert instead, they can be melted and recycled for new uses The energy released from burning can be used to generate electricity Burning plastics in oxygen releases carbon dioxide and water (complete combustion) which can contribute to global warming Photodegradation of polymers some polymers are biodegradable due to their ability to breakdown using light C=O groups along polymer chains absorb UV light this weakens C=O areas of polymers and breaks them down into smaller molecules e.g for polyesters and polyamides Disadvantages of photodegradability weaker polymers UV light not available (e.g. in landfills) Biodegrading polyesters and polyamides via hydrolysis polyesters and polyamides can be broken down by hydrolysis (advantage) hydrolysis: breakdown of molecules using water acid hydrolysis: acid catalyst used alkaline hydrolysis: alkaline catalyst used heating with catalyst breaks polymer Hydrolysis of polyamides acid hydrolysis: breaks polymer into di carboxylic acid and ammonium ions alkali hydrolysis breaks polymer into its sodium salts (e.g. dicarboxylic acid salt and diamines) Hydrolysis of polyesters acid hydrolysis: diol + dicarboxylic acid alkali hydro lists: diol + dicarboxylic acid salt 36. Organic synthesis Elucidating organic molecules - fn groups, properties, reactions Fn groups in AS required as well as: Production of fn groups benzoic acids acyl chlorides amides Producing benzoic acid reactants: methylbenzene oxidation: reflux with hot alkaline KMnO4 to form potassium benzoate protonation with dilute HCl to form benzoic acid Producing acyl chlorides reactants: c. acid substitution reaction: -OH replaced by Cl Producing amides condensation reaction reactants: acyl chloride, NH3 (nonsubstituted amide) / methyl amine (substituted amide) conditions: rt Reactions of functional groups Electrophilic substitution reactions of benzene reaction electrophile halogenation X+ nitration NO2+ alkylation R+ acylation RCO+ Hydrogenation of benzene addition reaction Esterification of phenol more efficient with acyl chloride than carboxylic acid Acid-base reactions of phenol phenol + base ⇒ soluble salt + water Nitration of phenol Bromination of phenol Multi-step synthetic routes Aliphatic reactions Aromatic reactions Analysis 37. Analytical techniques Thin- Layer Chromatography (TLC) Separate small samples 2 phases: stationary and mobile phase Stationary phase thin metal sheet coated in Al2O3, or SiO2 solutes adsorb onto surface and travel thru plate Mobile phase flows over stationary phase polar (water or alcohol) or nonpolar (alkanes), any liquid solvent or gas solvent carries components investigated in coloured components: investigated under UV light using ninhydrin Conducting a TLC analysis prep beaker with small amount of solvent on TLC plate, draw baseline in pencil place spot of reference compound on the left, then a spot of sample on right of baseline and air dry reserve allows identification of compounds in sample put TLC plate inside beaker with solvent - make sure pencil line above solvent, place lid to cover beaker as solvent reaches top, remove plate and draw another pencil line where solvent reached (solvent front) to use to calculate Rf Rf values The extent to which components are separated depends on solubility of each component in the mobile phase and interaction between each component and the stationary phase less polar components travel further up ⇒ larger Rf ⇒ more soluble in mobile phase more polar components do not travel far up ⇒ more attracted to polar stationary phase Gas / Liquid chromatography Analysing bases, volatile liquids, solids in vapour form Stationary phase nonpolar, non-volatile liquid applied to the inner walls of a capillary column mobile phase unreactive carrier gas noble, or inert diatomic e.g. He, N2, Ar Retention time: time taken for sample molecule to travel through the column from time inserted to time detected often recorded on chromatogram each peak = a volatile compound in the analysis sample. each peak has its own rt rt compared with data book values to identify unknown molecules longer rt: nonpolar components, attractiveness to nonpolar liquid in stationary phase shorter rt: polar components, interact with carrier gas Relative concentration of each component = area under each peak Area under peak = ½ base x height peaks roughly take shape of Δ % composition of a particular molecule in a mixture Carbon-13 NMR spectroscopy carbon-13 NMR : analytical tool used to analyse samples and determine the structure of substances Each Carbon environment gives a peak solvent used to dissolve samples for 13C-NMR : CDCl3 (solvent peak around 70 ppm) all 13C-NMR spectra measured relative to TMS / tetramethylsilane ( 0 ppm) predict the number of carbon environments refers to a specific c atom and the combination of atoms, bonds, fn groups attached each unique c environment produces a peak in 13C - NMR if there is a line of symmetry through the molecule, they belong to same environment and product a single peak e.g. predict no. peaks in 13C-NMR spectrum of 1,3-dihydroxybenzene 4 environments = 4 peaks predict each carbon’s chemical shift this is the frequency of an atomic nucleus relative to TMS reference compound measured in ppm example- 13C-NMR spectrum for propanone both CH3 groups are in same environment 2 environments = 2 peaks C=O peak over 200 C-H peaks 0-50 Proton (1H) NMR spectroscopy Technique used to determine structure of molecules paired with other techniques like Mass spec Magnetic field strengths of protons in organic compounds measured and recorded on H NMR spectrum all samples measured against reference compound TMS / Tetramethylsilane single sharp peak at 0 ppm Sample peaks plotted as a ‘shift’ away from this reference peak gives rise to ‘chemical shift’ values for protons on the sample compound (measured in ppm) Features of NMR spectrum intensity of peak against chemical shift area under peak: no. protons in particular environment height: intensity / absorption from protons Molecular / chemical environments diff. arrangements of H atoms have diff environments (identical / symmetry = same environment) no. environments = no. diff chemical shifts / peaks e.g. How many different 1H chemical environments occur in 2-methylpropane? 2 1H chemical environments 2 peaks on 1H NMR spectrum Chemical shift values for H molecular environments symmetrical H = same environment 1 ppm → Alkane 2 ppm → Next to C=O 7 ppm → Benzene ring 9–10 ppm → Aldehyde 10–12 ppm → Carboxylic acid Low resolution 1H NMR peaks on a low resolution NMR spectrum refer to the molecular environments of an organic compound High resolution 1H NMR number of peaks a signal splits into = n + 1 n = number of H on adjacent C atom n+1 splitting patterns Common pairs of splitting patterns TMS and deuterated solvents TMS gives sharp peak at 0 on NMR spectrum why is TMS an ideal reference chemical? it is inert and volatile it reduces undesirable chemical reactions with compound analyses it mixes well with most organic compounds Deuterated solvents in 1H NMR CDCl3 used as a solvent, no peak why is a solvent needed for samples in 1H NMR? dissolving samples in solvent help separate molecules and prevent them from interacting what must the solvent do? be a good solvent for organic molecules not contain any H atoms, does not interfere with NMR signals examples of non-deuterated solvents Carbon tetrachloride, CCl4: This solvent does not contain hydrogen, so it does not produce 1H NMR signals. It is suitable for 1H NMR but does not dissolve all molecules well. examples of deuterated solvents Deuterated solvents are often used in 1H NMR because deuterium (²H) is an isotope of H whose nuclei absorb in a different region from protons, so it gives no signal in a ¹H NMR spectrum Deuterochloroform / Chloroform-d, CDCl3: preferred, contains deuterium (2H) instead of H, does not interfere with the H NMR Deuterium oxide / Heavy water, D2O: deuterium atoms exchange reversibly with the H in the -OH and -NH, signals identified in NMR Identifying -OH and -NH signals Protons in -OH (hydroxyl) and -NH (amine) groups give singlet peaks in ¹H NMR but these signals can be tricky: peaks are broad or sometimes fall outside normal chemical shift ranges H in these groups exchanges quickly with protons from water or acids, so only one peak appears Their chemical shift ranges may overlap with other types of protons To identify these groups more clearly, proton exchange with deuterium oxide (D2O) is used: The deuterium atoms in D2O exchange reversibly with the protons in the -OH or -NH groups -OH + D2O ⇌ -OD + HOD -NH-CO- + D2O ⇌ -ND-CO- + HOD Since deuterium does not absorb in the same region as protons in the NMR spectrum, the signal for -OH or -NH disappears after D2O is added This confirms the presence of -OH or -NH groups in the molecule If peak disappears after D2O, it is due to the exchange of a proton from an -OH or -NH group
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