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What is a bronsted-lowry acid
An acid that DONATES a proton (H+)
What is the equation for a bronsted-lowry acid
HA (aq) + H2O (l) → A- (aq) + H3O+ (aq)
What ia bronsted-lowry base
A base ACCEPTS a proton (H+)
What is the equation for a bronsted-lowry base
B (aq) + H2O (l) → BH+ (aq) + OH- (aq)
Strong acid:
Completely WHAT
Concentration are WHAT
Strong acid:
Completely DISSOCIATES
[HA]i = [A-] = [H3O+]
How do you find pH through an acid
pH = -log[H3O+] at 25 celcius
Weak acid:
Concentrations are WHAT
[HA]i doesn’t = [A-]e = [H3O+]
Strong base:
Completely WHAT
Concentration are WHAT
Strong base:
Completely DISSOCIATED
[B]i = [BH+] = [OH-]
How do you find pH of a base
pOH = -log[OH-]
pH = 14 - pOH at 25 celcius
Weak acid:
Concentrations are WHAT
Weak acid:
[B]i doesn’t = [BH+]e = [OH-]
Equation for Ka (acids)
Ka = [A-][H3O+] / [HA]
Equation for Kb (bases)
Kb = [BH+][OH-] / [B]
OR
Kb = [HA][OH-] / [A-]
What is Kw equal to
Kw = [H3O+][OH-]
Kw = 1.0×10^-14 at 25 celcius
pKa = WHAT
Ka = WHAT
pH = WHAT
[H3O+] = WHAT
pKa = -log(Ka)
Ka = 10^-pKa
pH = -log(H+)
[H3O+] = 10^-pH
pKb = WHAT
Kb = WHAT
pOH = WHAT
[OH-] = WHAT
pKb = -log(Kb)
Kb = 10^-pKb
pOH = -log(OH-)
[OH-] = 10^-pOH
An acidic solution is WHAT
[H3O+] > [OH-] (not always less than 7)
An neutral solution is WHAT
[H3O+] = [OH-] (not always 7 )
An basic solution is WHAT
[H3O+] < [OH-] (not always more than 7)
Strong acid
Reacts completely with WATER, leaving the CONJUGATE BASE and H3O+
HUGE Ka values
7 strong acids (on data sheet)
Weak acids HA + H2O →← A- + H3O+
Does not completely react with water. At equilibrium you have HA, A- and H3O+ present
Moderate Ka value
In very weak acids
Do not react with water therefore do not produce H3O+ in water
An increase in Ka = a WHAT in kPa therefore the solution is a WHAT since it produces more products (WHAT)
An increase in Ka = a DECREASE in kPa therefore the solution is a STRONG ACID since it produces more products (H3O+)
An increase in Kb = a WHAT in kPb therefore the solution is a WHAT since it produces more products (WHAT)
An increase in Kb = a DECREASE in kPb therefore the solution is a STONG BASE since it produces more products (OH-)
The stronger the acid the WHAT the conjugate base
The stronger the acid the WEAKER the conjugate base
Conjugate bases of Strong acids and conjugate acids of strong bases do not HWAT
Are very weak acids or bases therefore do not react with water to produce H3O+ or OH-
%dissociation / %ionization
Percentage of a WHAT that dissociates in solution
A good way to describe the WHAT of your acid
The STRONGER the acid, the WHAT the % dissociation
%dissociation / %ionization
Percentage of a ACID/BASE that dissociates in solution
A good way to describe the STRENGTH of your acid
The STRONGER the acid, the LARGER the % dissociation
How to calculate %dissociation / ionization
Starting with a HA (weak acid)
% dissociation = [A-]equilibrium / [HA]initial x 100%
Starting with HA + A- (buffer)
% dissociation = [A-]equilibrium / [HA]equilibrium + [A-]equilibrium x 100%
Soluble salts are those that WHAT into WATER
Soluble salts are those that DISSOCIATE 100% into WATER
Many acids are delivered not as their fully protonated forms, but as salts of their WHAT or WHAT (eg, Ammonium chloride, Sodium acetate)
Many acids are delivered not as their fully protonated forms, but as salts of their CONJUGATE ACID or BASE (eg, Ammonium chloride, Sodium acetate)
Predicting if a salt solution will generally be acidic basic or neutral can help direct WHAT
Equilibrium calculations
Generally salts that cause a change in pH are called WHAT as they react with water in solution
Generally salts that cause a change in pH are called HYDROLYZING SALTS as they react with water in solution
Ions will only react if the “conjugate” makes a WHAT or WHAT
Ions will only react if the “conjugate” makes a WEAK ACID or WEAK BASE
Steps to determine pH of salt solutions
Determine ions in salt
Determine if ions react with water
Determine pH