Unit C

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ΔHrxn= ? - ?

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1

ΔHrxn= ? - ?

H(products) - H(reactants)

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If ΔH is large and negative….

the reaction is THERMODYNAMICALLY FAVORABLE

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3

if ΔH is large and positive….

the reaction is NOT thermodynamically favorable

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4

If the energy of the products is GREATER than the energy of the reactants….

the reaction is ENDOthermic

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5

If the energy of the products is LESS than the energy of the reactants….

the reaction is EXOthermic

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Exothermic reactions feel….

Hot

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7

Endothermic reactions feel…

Cold

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1 pair of electrons shared; longest and weakest bond

Single bond

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2 pairs of electrons shared; shorter and stronger bond

Double bond

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3 pairs of electrons shared; shortest and strongest bond

Triple bond

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11

Breaking of bonds is…

Endothermic (+ΔH)

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Forming of bonds is…

Exothermic (-ΔH)

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In an exothermic reaction: BDE of reactants is _____ than BDE of products

GREATER (products are lower than reactants on the graph)

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In an endothermic reaction: BDE of reactants is _____ than BDE of products

LESS (products are higher than reactants on the graph)

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BDE to estimate ΔHrxn:

ΔHrxn= ???

ΔHrxn = (BDE reactants) + (BDE products)

REMEMBER: BDE is ADDING

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Multiply ____ by the same number the ____ are multiplied by when balancing equations for Hess’s Law

the ΔH value, coefficients

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If something is mixing/dissolving, it is…

Thermodynamically favorable (even without added stirring)

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What are IMFs?

Intermolecular Forces; attractions between molecules

  • tells if the substance is mixable or not

  • weaker than bonds

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Dispersion Forces

  • present in all molecules and atoms

  • weakest IMF

  • randomly caused by electron movement in orbital

  • if electrons gather on one side of the molecule, they can create an instantaneous dipole

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Dipole-Dipole

  • negative end of 1 polar molecule is attracted to the positive end of another polar molecule

  • stronger IMF than Dispersion Forces because electrons always gathered on that side (permanent Dipole rather than instantaneous)

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Hydrogen Bonding

  • found in polar molecules with Hydrogen attached to Florine, Oxygen, or Nitrogen

  • stronger than Dispersion Forces and Dipole-Dipole forces because F, O, and N are more electronegative (chemlab coming in clutch)

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Ion-Dipole

  • cations attracted to the negative end of dipole

  • anions attracted to the positive end of dipole

  • stronger than Dispersion, Dipole-Dipole, and Hydrogen Bonds

  • strength increases as charge increases

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Lattice Energy

Bonds/IMFs between solute particles of an ionic crystal are broken

  • ENDOTHERMIC REACTION (breaking bonds=endothermic)

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If IMFs between solvent molecules broken, then…

the reaction is ENDOthermic (breaking bonds=endothermic)

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IMFs between solute and solvent particles FORMED

reaction = EXOthermic (forming bonds=exothermic)

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Hydration

  • Energy IN to break apart crystal structure

  • Energy IN to separate Hydrogen Bonds between H2O molecules

  • Energy OUT as cations and anions attract to the water molecules

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ΔHsolute=

Bonds/IMFs breaking

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ΔHsolvent=

IMFs/Bonds breaking

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ΔHmix=

IMFs forming

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ΔHsoln=

ΔHsolute + ΔHsolvent + ΔHmix

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If ΔHmix > ΔHsolute + ΔHsolvent then

yes dissolve

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If ΔHmix < ΔHsolute + ΔHsolvent then

no dissolve

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Experimental ΔHsoln calculation:

q = mcΔT = ΔH * moles

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Experimental ΔHcomb calculation:

q = mcΔT = -ΔH * moles

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Definition of ΔH

Enthalpy change; heat transferred between system and surrounding under constant pressure

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0th Law of Thermodynamics

2 systems in equilibrium with the 3rd system are in thermal equilibrium with each other

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1st Law of Thermodynamics

Energy is neither created nor destroyed (conservation of energy)

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2nd Law of Thermodynamics

Entropy of an isolated system always increases (hot —> cold)

  • ΔE = q + w

    • ΔE: change in internal energy

    • q: heat absorbed

      • if q>0 then sys gaining heat from surr

    • w: work

      • if w>0 then sys gaining work from surr

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3rd Law of Thermodynamics

Entropy of a system approaches a constant as temperature approaches 0K (absolute zero)

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ΔH units

kJ/mol

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Entropy (S) and ΔS units

J/molK

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If ΔS is positive, then…

Entropy is INCREASING

  • products are more randomly arranged than reactants

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If ΔS is negative, then….

Entropy is DECREASING

  • reactants are more randomly arranged than products

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When determining entropy, look at…

  1. Phase (gas has highest entropy)

  2. Number of molecules (more molecules means more entropy)

  3. Molecule size/shape (larger, more “floppy” molecules have greater entropy)

  4. Larger atoms (larger atoms have more entropy)

  5. Temperature (higher temperature means greater entropy)

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