1/11
Looks like no tags are added yet.
Name | Mastery | Learn | Test | Matching | Spaced |
---|
No study sessions yet.
Subnetting
Dividing a network into smaller subnetworks by borrowing bits from the host portion of an IP address.
Number of Subnets
Calculated as 2^n
Number of Hosts
Calculated as 2^m - 2
Increment
The size of each subnet
Borrow 3 bits in Class C
Number of subnets: 2^3 = 8.
14 hosts needed
Number of host bits required: m = 4 (since 2^4 - 2 = 14).
Increment for /26
Increment: 2^6 = 64.
16 hosts needed
Number of host bits required: m = 5 (since 2^5 - 2 = 30).
Increment for /28
Increment: 2^4 = 16.
Borrow 1 bit in Class C
Number of subnets: 2^1 = 2.
18 hosts needed
Number of host bits required: m = 5 (since 2^5 - 2 = 30).
Borrow 2 bits in Class C
Number of subnets: 2^2 = 4.