Subnetting

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/11

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

12 Terms

1
New cards

Subnetting

Dividing a network into smaller subnetworks by borrowing bits from the host portion of an IP address.

2
New cards

Number of Subnets

Calculated as 2^n

3
New cards

Number of Hosts

Calculated as 2^m - 2

4
New cards

Increment

The size of each subnet

5
New cards

Borrow 3 bits in Class C

Number of subnets: 2^3 = 8.

6
New cards

14 hosts needed

Number of host bits required: m = 4 (since 2^4 - 2 = 14).

7
New cards

Increment for /26

Increment: 2^6 = 64.

8
New cards

16 hosts needed

Number of host bits required: m = 5 (since 2^5 - 2 = 30).

9
New cards

Increment for /28

Increment: 2^4 = 16.

10
New cards

Borrow 1 bit in Class C

Number of subnets: 2^1 = 2.

11
New cards

18 hosts needed

Number of host bits required: m = 5 (since 2^5 - 2 = 30).

12
New cards

Borrow 2 bits in Class C

Number of subnets: 2^2 = 4.