AP Physics C Mechanics EXAM REVIEW

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created 2025; EHS

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49 Terms

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vectors

quantities with magnitude and direction; ex- velocity, displacement, acceleration, force, momentum

can be written in component form: v= ai +bj+ ck

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scalar

quantities with only a magnitude; ex- distance, speed, mass, energy, temperature, time

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Dot Product (vector multiplication)

method 1: A*B = |A||B|cosθ

method 2: A*B= AxBx + AyBy + AzBz

produces a scalar

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Cross Product (vector multiplication)

method 1: |AxB| = |A||B| sinθ

method 2: if A= Axi + Ayj + Azk and B= Bxi + Byj + Bzk

then AxB= (AyBz - AzBy)i - (AxBz + AzBx)j + (AxBy - AyBx)j

produces a vector

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average displacement, velocity, and acceleration

displacement: ∆x=(xf - xi) units: m

velocity: ∆v= ∆x/t units: m/s

acceleration: ∆a= ∆v/t units: m/s2

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instantaneous displacement, velocity, and acceleration

displacement: x(t)= ∫v(t) dt

velocity: vinst= dx/dt; v(t)= ∫a(t) dt

acceleration: ainst=dv/dt OR ainst=d2x/dt2

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graphical representation of position, velocity, and acceleration

slope of x(t) = v(t)

slope of v(t) = a(t)

area under curve of a(t) = v(t)

area under curve of v(t) = x(t)

<p>slope of x(t) = v(t) </p><p>slope of v(t) = a(t) </p><p>area under curve of a(t) = v(t) </p><p>area under curve of v(t) = x(t) </p>
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how to linearize data in desmos

steps

  • add table, insert values, and adjust window

  • determine the type of non-linear relationship (ex: inverse, square, inv-square, root, inv-root, quadratic, log, exponential)

  • create new variables to represent the transformation

  • plot the new data points

  • draw a line of best fit

non-linear power function relationship examples (c is constant):

  • inverse: y= c/x

  • square: y= cx2

  • inv-square: y= c/x2

  • root: y= c√x

  • inv-root: y=c/√x

<p>steps </p><ul><li><p>add table, insert values, and adjust window </p></li><li><p>determine the type of non-linear relationship (ex: inverse, square, inv-square, root, inv-root, quadratic, log, exponential) </p></li><li><p>create new variables to represent the transformation </p></li><li><p>plot the new data points </p></li><li><p>draw a line of best fit </p></li></ul><p>non-linear power function relationship examples (c is constant): </p><ul><li><p>inverse: y= c/x</p></li><li><p>square: y= cx<sup>2</sup></p></li><li><p>inv-square: y= c/x<sup>2</sup></p></li><li><p>root: y= c√x</p></li><li><p>inv-root: y=c/√x</p><p></p></li></ul><p></p><p></p>
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kinematic equations for constant acceleration

vf= vi + at

x= xi + vit + 1/2at2

vf2= vi2 + 2a(xf - xi)

x= 1/2(vi + vf)t

only when acceleration is constant!!

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Reference frames

the velocity of an object depends on the location and motion of the observer.

EX1: Object A is moving left at 4m/s and Object B is moving is moving right at 6 m/s. the velocity of Object A from the reference frame of Object B is 10 m/s to the left.

EX2: an observer on land is watching a river. the velocity of the water relative to the observer is VWL, the velocity of the boat relative to the water is VBW, the boat moves perpendicular to VWL. what is the velocity of the boat relative to the land? VBL2 = VBW2 + VWL2

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projectile motion

break down into horizontal and vertical components of d, v, and a. a faster horizontal velocity will result in a greater horizontal distance. horizontal motion of an object does not affect its vertical motion. the horizontal motion of a projectile is independent of its vertical motion and the vertical motion is independent of its horizontal motion.

the horizontal acceleration is zero and the vertical acceleration is constant. use kinematic equations in the vertical and horizontal directions separately. the time of the horizontal and vertical directions is the same.

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launch angles in projectile motion

the greater the launch angle the greater the vertical distance of the projectile. the optimal angle for max range is 45 degrees.

<p>the greater the launch angle the greater the vertical distance of the projectile. the optimal angle for max range is 45 degrees. </p>
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projectile motion equations

hmax= (vi2sin2θi)/(2g)

tmax h= (visinθi)/g

R= (vi2sin2θi)/g

Rmax=vi2/g

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Uniform Circular Motion

ac= v2/r

v= rω

T= (2πr)/v

ω= (2π)/T

ac= rω2

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Tangential and Radial Acceleration

a= √(ar2+at2)

<p>a= √(a<sub>r</sub><sup>2</sup>+a<sub>t</sub><sup>2</sup>)</p>
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QUESTION: which of the following are accelerating?

  1. a car slowing down

  2. ball being swung in a circle

  3. vibrating string

  4. moon orbiting

  5. skydiver at terminal speed

  6. astronaut orbiting in space

  7. ball rolling down a hill

  8. person driving straight at a constant speed with their foot on the gas

objects changing direction or changing speed are accelerating. therefore 1, 2, 3, 4, 6, and 7 are accelerating while 5 and 8 are not

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newtons first law

in the absence of external forces and when viewed from an inertial reference frame, an object at rest remains at rest and an object in motion will stay in motion with a straight-line velocity, unless acted on by an external force.

-condition 1: object can move but must be at a constant speed

-condition 2: object is a rest

constraint: forces must be balanced, sum of forces is zero

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inertial frame of reference

a non-accelerating frame of reference

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inertia vs weight

inertia- quantity of matter, aka mass (unit kg)

weight- mass effected by gravity; w=mg; (unit newton)

mass never changes; weight changes with gravity

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facts about forces

unit: Newton (N)

a push or a pull

can exist during physical contact or without contact

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equilibrium

when the sum of the forces acting on the object is zero; Fnet=0

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newtons second law

the acceleration of an object is directly proportional to the net force and inversely proportional to the mass;

a=Fnet/m

ΣF=ma

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static vs kinetic friction

static- friction that keeps an object at rest and prevents it from moving

Ff=FNµs

kinetic- friction that acts during motion

Ff=FNµk

µ has no units

friction depends on the materials sliding against each other, NOT surface area!

<p>static- friction that keeps an object at rest and prevents it from moving </p><p>F<sub>f</sub>=F<sub>N</sub>µ<sub>s</sub></p><p>kinetic- friction that acts during motion </p><p>F<sub>f</sub>=F<sub>N</sub>µ<sub>k</sub></p><p>µ has no units </p><p>friction depends on the materials sliding against each other, <strong>NOT </strong>surface area! </p><p></p>
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newtons third law

for every action force there is an equal and opposite reaction force

  • they NEVER cancel out

ie: a person exerts a force on a wall and the wall exerts a force on the person

ie: mcar Acar = Mtrain atrain

<p>for every action force there is an equal and opposite reaction force </p><ul><li><p>they NEVER cancel out </p></li></ul><p>ie: a person exerts a force on a wall and the wall exerts a force on the person </p><p>ie: m<sub>car </sub>A<sub>car </sub>= M<sub>train </sub>a<sub>train </sub></p><p></p>
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Air resistance

linear: R= -bv

  • b is a constant

  • velocity (v) is changing

m(dv/dt)=mg-bv

to find terminal 0=mg-bv therefore vT=mg/b

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centripetal force

Fc=mv2/r

has to be supplied by another force

ie: a cart on a roller coaster at the top of a hill the Fc=Fg-FN while a cart at the bottom of the hill Fc=FN-Fg

centripetal force is the net force directed toward the center of a circular path, allowing an object to maintain circular motion. it can be provided by tension, gravity, friction, depending on the situation.

<p>F<sub>c</sub>=mv<sup>2</sup>/r</p><p>has to be supplied by another force </p><p>ie: a cart on a roller coaster at the top of a hill the F<sub>c</sub>=F<sub>g</sub>-F<sub>N</sub> while a cart at the bottom of the hill F<sub>c</sub>=F<sub>N</sub>-F<sub>g </sub></p><p>centripetal force is the net force directed toward the center of a circular path, allowing an object to maintain circular motion. it can be provided by tension, gravity, friction, depending on the situation. </p>
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resistive forces

R=-bv

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basics of energy

  • work- force applied through a distance; must be parallel; W=Fd

  • kinetic energy- energy of motion; KE= ½ mv2

  • potential energy- energy of position; 2 types: gravitational (U= mgh) and elastic (U= ½ kx2)

  • power- rate at which energy is transferred/consumed- P=W/t or P=E/t

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work

W= F∆d → FdCosθ

work is found by multiplying the force times the displacement and result is energy.

units: joules (J)

F and d must be parallel

W= ∫ F(x)dx → work is the area under the force vs displacement graph

Wnet= ∆K → W=(mv2/2 - mv02/2)

W= -∆U → W= mgy - mgy0 → work equals the negative change in potential energy

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energy conservation

∆K = -∆U

K-K0 = -(U-U0)

in a closed isolated system energy is conserved, meaning the initial energy equals the final energy.

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Elastic Potential Energy

hooks law: Fs=-Kx

negative because it’s a restoring force that works in the opposite direction of the displacement

Us= ½ Kx2

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power

Power = work/time

P= Energy/time

P= F v → P= F(d/t)

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Momentum and Impulse

  • momentum: moving mass- inertia in motion

    • momentum = mass x velocty →(p= mv); units: kgm/s

  • Impulse: applying a force for a period of time to change momentum

    • Impulse= forceavg x time →(J= Favgt) or J= ∆p; units: Ns or Kgm/s

  • relationship: the area under the curve of a force vs time graph is the impulse/change in momentum.

  • increasing momentum: apply the greatest force for the longest period of time (ie: following through)

  • Decreasing momentum: extending the impact time (ie: air bags)

  • bouncing delivers a greater impulse (∆p= 2mv)

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conservation of momentum

in a closed isolated system total momentum is conserved

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collisions

elastic collisions: momentum AND kinetic energy are conserved (ie: billiard balls)

inelastic collisions: ONLY momentum is conserved (ie: car crashes)

  • perfectly inelastic collisions: objects stick together

  • imperfectly inelastic collisions: objects don’t stick together

  • pay attention to signs!

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center of mass

use for elastic collisions only!

vcm= Σ mivi / mi

subtract Vcm from initial velocity to enter Center of mass reference frame; add Vcm to final velocity to leave the center of mass reference frame.

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rotation of a rigid object a fixed axis

  • angular position: θ = S/r

    • S is arc length

    • r is radius of rotation

    • θ is the angle through which the object rotates

  • angular speed: ωavg = ∆θ/∆t or ω= dθ/dt or ω= 2π/T

    • ω is angular speed (units rad/sec)

    • T is the period

  • Angular acceleration: αavg= ∆ω/∆t or α= dω/dt

    • α is angular acceleration (units rad/sec2

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rigid object under constant acceleration

ωf=ωi+αt

θf= θi+ωit+1/2 αt2

ωf2=ωi2+2α(θf-θi)

θf=θi+1/2(ωi+ωf)t

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angular and translational quantities

v= rω

a= rα

ac = rω²

angular speed radius does not matter

linear/translational speed radius matters

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Torque

T= rFsinθ

force should be perpendicular to the lever arm

units: Nm

ΣT=

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moment of inertia

I= Σ miri²

Hoop/Thin Cylindrical Shell: Icm= 1MR2

Solid Cylinder/disk: Icm= 1/2MR2

Hollow cylinder: Icm=1/2M(R12+R22)

Long thin rod with rotation axis through center: Icm=1/12ML2

Long thin rod with rotation axis through end: I=1/3ML2

Rectangular plate: Icm=1/12M(a2+b2)

Solid Sphere: Icm=2/5MR2

thin spherical shell: Icm= 2/3MR2

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Parallel Axis Theorem

I= Icm+ MD2

  • D= distance between parallel lines

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Rotational Kinetic Energy

KR=1/2 Iω2

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energy considerations

dW= Fds = (F sinθ)rdθ

Power= dW/dt = tω

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rolling motion of a rigid object

VT= ωR

VCM= Rω

acm= Rα

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angular momentum

L= position cross linear momentum

L= mvr sinθ

L= Iω

angular momentum is conserved in an isolated system

∆L= 0 with no external torques

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gravity

Fg= G(m1m2)/r²

don’t forget r is measured to the center of mass!!

Ug= Gm1m2/r

escape speed as the particle gets infinitely faraway velocity approaches 0

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oscillatory motion

Fs= -kx

ax=-k/m x

ω=√(k/m)

x(t)= Acos(ωt+∅)

Vmax= ωA

a(max)= ω²A

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spring constant (k)

in series: ktotal= (1/k)+(1/k)…

in parallel: ktotal= k+k+k…