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5 natures of gases
Gasses have mass (low density compared to solids and liquids)
Gasses are compressible
Gasses fill their containers
Gasses diffuse (move from areas of high to low concentration)
Gasses exert pressure (sum of collisions of gas molecules with themselves and their container)
Things that affect rate of diffusion
Size & energy influence speed of diffusion (heavier atomic mass -> slower diffusion)
Atmospheric pressure
Pressure of the gas in the air on the earth (measured by a barometer)
Gas law units
Pressure: 1 atm = 760 torr = 760 mmHg = 101.3 kPa
Temperature: 0ºC = 273.15 K (MUST USE KELVIN!!!)
Volume: 1 L = 1000 mL = 1000 cm^3
Dalton’s law of partial pressure
P total = P1 +P2 + P3…
Ideal Gas Law
PV = nRT (number of moles (n) of contained gas)
International Gas Law Constant (R)
Changes depending on unit of pressure
R for atm = 0.0821
R for mmHg and torr = 62.4
R for kPa = 8.314
Manometer
Tool used to measure the pressure of contained gas by comparing it to atmospheric pressure
Manometer Problems (P = pressure)
If Pgas > Patm: Pgas = Patm + ∆z
If Pgas < Patm: Pgas = Patm - ∆z
Use mole ratio when solving for
Molar mass
Na -> Nb
# molecules a -> # molecules b
Avigadro’s #
1 mole (6.02*10^23) = the amount of molecules in an element as appears on periodic table
4 unusual properties of water
High surface tension: Water is polar & very attracted to itself via h-bonding which creates a sort of skin on the surface of the water
High boiling point: Water is polar & very attracted to itself via h-bonding, so it takes lots of energy for H2O to break h-bonds and escape as vapor
Ice is less dense than water: Frozen water forms a lattice pattern which fills with air and causes ice to be less dense than water
Water is the universal solvent: Because water is polar, it has the ability to attract other polar molecules and pull them apart
Like dissolves like
Polar dissolves polar, nonpolar dissolves nonpolar
Factors affecting rate of solvation and why
Stirring: makes H2O molecules tear the solute apart
Temperature: increased temp -> increased KE -> increased collisions and contact between solute and solvent
Particle Size: Decreased particle size -> increased surface area and contact
Factors affecting solubility:
Gasses
Temperature is directly proportional to solubility
Increase in temp -> increase in solubility
Pressure: N/A
Solids
Temperature is inversely proportional to solubility
Increase in temp -> decrease in solubility
Pressure is directly proportional to solubility
Increase in pressure -> increase in solubility
Ion dipole forces
Exist between an ionic compound in water (ex: Cl and positive poles in water)
Strongest IMF!!!
Hydrogen bonding
Stronger version of DP-DP, hydrogen with strong positive charge due to electronegativity of O, N, or F becomes attracted to the O, N, or Fs of other molecules
Dipole-Dipole
Polar molecules with oppositely charged ends attract each other
LDF (London dispersion forces)
Exists between all molecules; is a temporary force that exists when adjacent electrons are positioned to make the atoms form temporary dipoles
Is the weakest IMF!!!
Colligative properties
properties that depend only on the number of solute particles and not their identity
BP elevation and FP depression
Difference in temp of boiling/freezing point of solution vs boiling/freezing point of pure solvent
Steps to solve colligative property problem
Solve for molality
Solve for ∆Tf & ∆Tb
∆Tf = Kf * m
∆Tb = Kb * m
Solve for new boiling or freezing point
BP solution = BP + ∆Tb (elevation)
FP solution = FP + ∆Tf (depression)
Collision theory
Particles that collide with sufficient energy will react to form products
Activation energy
The minimum energy needed by colliding particles in order to react
Activated complex
An unstable arrangement of atoms that exists momentarily at the peak of the activation energy barrier
Reaction rate 4 factors affecting it
4 factors:
Concentration: More particles -> more collisions -> faster rate
Temperature: Increase in temp -> more collisions -> faster rate
Particle Size: Increase in surface area -> more collisions -> faster rate
Catalyst: Makes reaction easier by lowering activation energy
The rate law
shows the relationship of the reaction rate to the rate constant and the concentrations of the reactants raised to some power
For aA + bB -> cC + dD: Rate = k[A]^x[B]^y
Le chatlier’s principle
f stress is applied to a system (reaction) at equilibrium, the system changes to relieve the stress
Stresses that exist
Change in concentration: If you remove a reactant or product, the reaction will favor the reaction making it (opposite also true)
Change in temperature: If you heat a system it will favor the reaction using heat (opposite also true)
Exothermic: absorb heat (heat is a reactant)
Endothermic: give of heat (heat is a product)
Change in pressure/volume: If pressure is increased the system will favor the reaction making less moles of gas (opposite also true)
IF NO GASSES, NO EFFECT!!!
Acid properties
Acids contain an ionizable hydrogen, are sour, and have a pH of less than 7
Bases properties
Bases contain an ionizable hydroxide, are bitter, slippery when wet, and have a pH of more than seven
6 strong acids & bases: (Ionize completely in water)
6 strong acids | 6 strong bases |
HClO4 (perchloric acid) | LiOH (lithium hydroxide) |
HCl (hydrochloric acid) | AQZNaOH (sodium hydroxide) |
HBr (hydrobromic acid | KOH (potassium hydroxide) |
HI (hydroiodic acid) | Ca(OH)2 (calcium hydroxide) |
HNO3 (nitric acid) | Sr(OH)2 (strontium hydroxide) |
H2SO3 (sulfuric acid) | Ba(OH)2 (barium hydroxide) |
Arrhenius acids and bases
Arrhenius acids give off hydrogen in water
Arrhenius bases give off hydroxide in water
Mono, di, & triprotic acids: Acids with one, two and three ionizable hydrogens
Bronstead lowry acids and bases: (relationship between them that does not involve water)
Acids give off hydrogen ions
Bases can gain hydrogen ions
Amphoteric substances ca lose or gain a hydrogen ion
Conjugate acids: The product formed when a base gains a hydrogen
Conjugate bases: The product formed when an acid loses a hydrogen
Ion product constant (Kw)
At 25ºC, Kw = 1.0*10^-14
(In pure water [H] = 1.0*10^-7)
pH equations
If given [H]
pH = -log([H])
[OH] = kw/[H]
If given pH
pOH = 14-pH
[H] = 10 ^-pH
If given [OH]
pOH = -log([OH])
[H] = kw/[OH]
If given pOH
pH = 14-pOH
[0H] = 10 ^-pOH
Weak acids & bases
Do not fully dissociate in water
Weak acids → strong conj bases (opposite also true)
Ka & Kb
Extent of proton transfer between the acid/base and H2O
Determines strength of acid/base (smaller ka = weaker acid)
Ka equation
Keq * [H20] = [H3O][A]/[HA] (products/reactants)
Solving Ka/Kb steps (given: M and pH)
Is it a strong acid? if not, make ICE table
create ICE table & Ka equation
use pH to find [H]
plug in [H] for x in Ka equation
Solving [OH] & pH steps (given Ka/Kb, M)
check to see if [HA]/Kb > 500
create ICE table & Kb equation
use Kb equation to find Kb using algebra
use [OH] to find pH
Ha and Ka relationship
if [HA]/Kb > 500: change in initial concentration of x is negligible (can remove x from E row)
if [HA]/Kb < 500: change in initial concentration of x is not negligible (must keep x in E row)
% dissociation
Acids: final [H30]/initial acid * 100
Bases: final [OH]/initial base * 100
Neutralization reaction
when an acid and a base react and neutralize each other (moles H = moles OH, produces water)
Neutralized products formula
combine cation from base and anion from acid + HOH to make product formulas
Neutralization problems
Given V & M of one substance, V of another (use train tracks to solve for M)
Buret
a graduated glass tube with a tap at one end, for delivering known volumes of a liquid, especially in titrations
Titrant/standard solution
The substance of known concentration added to the analyte in a titration
Analyte
The substance of unknown concentration
Equivalence point
Point in a titration where neutralization occurs
End point
Point at which the indicator changes color in titration