Chapter 4 - Roots of Polynomials

0.0(0)
studied byStudied by 0 people
0.0(0)
full-widthCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/19

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No study sessions yet.

20 Terms

1
New cards

Quadratic roots (ax^2 + bx + c = 0): sum of roots

α + β = -b/a

2
New cards

Quadratic roots (ax^2 + bx + c = 0): product of roots

αβ = c/a

3
New cards

Cubic roots (ax^3 + bx^2 + cx + d = 0): sum of roots

α + β + γ = -b/a

4
New cards

Cubic roots (ax^3 + bx^2 + cx + d = 0): sum of pairwise products

αβ + βγ + γα = c/a

5
New cards

Cubic roots (ax^3 + bx^2 + cx + d = 0): product of roots

αβγ = -d/a

6
New cards

Quartic roots (ax^4 + bx^3 + cx^2 + dx + e = 0): sum of roots

α + β + γ + δ = -b/a

7
New cards

Quartic roots (ax^4 + bx^3 + cx^2 + dx + e = 0): sum of pairwise products

αβ + αγ + αδ + βγ + βδ + γδ = c/a

8
New cards

Quartic roots (ax^4 + bx^3 + cx^2 + dx + e = 0): sum of triple products

αβγ + αβδ + αγδ + βγδ = -d/a

9
New cards

Quartic roots (ax^4 + bx^3 + cx^2 + dx + e = 0): product of roots

αβγδ = e/a

10
New cards

Reciprocals (quadratic)

1/α + 1/β = (α + β)/(αβ)

11
New cards

Reciprocals (cubic)

1/α + 1/β + 1/γ = (αβ + βγ + γα)/(αβγ)

12
New cards

Reciprocals (quartic)

1/α + 1/β + 1/γ + 1/δ = (αβγ + βγδ + γδα + δαβ)/(αβγδ)

13
New cards

Product of powers (quadratic)

α^n × β^n = (αβ)^n

14
New cards

Product of powers (cubic)

α^n × β^n × γ^n = (αβγ)^n

15
New cards

Product of powers (quartic)

α^n × β^n × γ^n × δ^n = (αβγδ)^n

16
New cards

Sum of squares (quadratic)

α^2 + β^2 = (α + β)^2 − 2αβ

17
New cards

Sum of squares (cubic)

α^2 + β^2 + γ^2 = (α + β + γ)^2 − 2(αβ + βγ + γα)

18
New cards

Sum of squares (quartic)

α^2 + β^2 + γ^2 + δ^2 = (α + β + γ + δ)^2 − 2(αβ + αγ + αδ + βγ + βδ + γδ)

19
New cards

Sum of cubes (quadratic)

α^3 + β^3 = (α + β)^3 − 3αβ(α + β)

20
New cards

Sum of cubes (cubic)

α^3 + β^3 + γ^3 = (α + β + γ)^3 − 3(α + β + γ)(αβ + βγ + γα) + 3αβγ