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Faraday’s Law
The induced electromotive force in any closed circuit is equal to the negative of the time rate of change of the magnetic field enclosed by the circuit.
Maxwell’s Laws
1) A time-varying magnetic field acts as a source of electric field.
2) A time-varying electric field acts as a source of magnetic field.
Thermal Radiation
Interatomic collisions cause the kinetic energy of the atoms to change, resulting in the charge acceleration of the electrons, which in turn produces electromagnetic radiation over a wide range of wavelengths.
Blackbody
Blackbodies are idealised objects that emit thermal spectra of a universal character.
The work function
The threshold of energy a photon needs to have for a photoelectron to be released
Compton shift
The shift in wavelength of one of the 2 peaks of scattered X rays varies with the angle at which the scattered x-rays are observed.
The principle of complementarity
Without considering both wave and particle properties, you cannot describe a particle or a photon completely. Moreover, these wave and particle properties cannot be observed simultaneously
Boundary conditions for the Schrodinger equation
1) The wave function must be continuous
2) The slope of the wave function must be continuous (the derivative of the wave function must be the same on both sides) except when the wave function is infinite
Frank-hertz experiment procedure(1914)
Aim: To confirm that radiation is quantised
Procedure:
A glass tube filled with mercury vapour
Electrons emitted from the heated cathode
Accelerated towards the Anode grid
Current reaching the plate against the Voltage plotted
Results: Current drops at multiples of 4.9v due to inelastic collisions exciting atoms from the ground state
Bohr model main 4 Assumptions
Discrete orbits and energies in ‘stationary states’
Classical mechanics describes these states
A single quantum of energy is released in a jump between states
allowed orbits determined by the quantisation of angular momentum
4 quantum numbers
Principle Quantum number - n
Angular Momentum Quantum Number - l
Magnetic Quantum number - ml
Spin quantum number - ms
Stern-Gerlach
Aim: To prove spatial quantisation
Procedure: Fired silver atoms (l=0) through a non-uniform magnetic field
Results: 2 images (suggesting l=1/2)
implying another contribution to angular momentum (intrinsic spin)
Fine structure splitting
The fact that most spectral lines can be split into two smaller spectral lines when using more accurate equipment
Spin-orbit coupling
Interaction between the internal magnetic field of the atom and the intrinsic angular momenta of the electron.
The orbital momentum corresponds to an internal magnetic filed which interacts with the spin of the electron.
Zeeman Effect Cause
Interaction between the angular momentum of the electron and an external field.
4 properties of elements and main findings
1 Atoms with larger nuclear charges have a shrinkage in the p shell due to the nucleus pulling electrons closer
2 Ionisation Energies - Atoms with entirely filled subshells have much higher Ionisation energies due to the extra energy needed to break open shells
3 Good electrical conductors have low resistivity and loosely bound electrons that can flow as delocalised electrons
4 Magnetic properties are stronger due to the larger angular momentum of f subshell
What is the most striking feature of X-ray line spectra and why?
The frequencies and wavelengths of lines vary smoothly from element to element
as they are dependent on binding energies of inner electrons which increase uniformly with atomic number Z
Bremstrahlung Radiation
X-rays may be produced if electrons decelerate or stop in the target material
Electron collisions- X-ray
An electron collides with an atom displacing an electron and leaving a vacancy in a shell
Another electron de-excites to fill the shell releasing an X-Ray
Bohr model 5 limitations
No proper account of quantum mechanics
2d model in 3d world
For single-electron atoms
predicted angular momenta too large by hbar
no selection rules
Schrodinger - Free particle steps
Choose V(x)=0
Rearrange TISE for the second derivative
try particular solution: Aealphax
Find alpha=ik
sub psi into TISE
Find E=..
Schrodinger’s - Infinite Well
Outside box: psi(x)=0
Inside box: V(x)=0
General solution: psi(x)=A sin(kx)+Bcos(kx)
Boundary Conditions:
1) x=0, psi = 0 → B=0
2) x=L, psi = 0 and k=npi/L→ psi(x)=A sin(npix/L)
Total probability= 1:
Integrate between 0 and L
A=sqrt(2/L)
Psi = sqrt(2/L) sin (npix/L)
Energy = Substitute k=npi/L into energy for a free particle