Energetics

0.0(0)
Studied by 1 person
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/25

Last updated 9:47 PM on 4/7/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

26 Terms

1
New cards

Enthalpy of formation (ΔHf )

Enthalpy change when one mole of a substance is formed from its constituent elements with all substances in their standard states: Exothermic (-)

e.g. Na2O(s)

2 Na(s) + ½ O2(g) → Na2O(s)

2
New cards

Enthalpy of combustion (ΔHc )

Enthalpy change when one mole of a substance undergoes complete combustion in oxygen with all substances in their standard states: Exothermic (-)

e.g. hydrogen

H2(g) + ½ O2(g) → H2O(l)

3
New cards

Enthalpy of neutralisation (ΔHneut )

Enthalpy change when 1 mole of water is formed in a reaction between an acid and alkali under standard conditions: Exothermic (-)

e.g. H2SO4 + NaOH

½ H2SO4(aq) + NaOH(aq) → ½ Na2SO4(aq) + H2O(l)

4
New cards

(First) Ionisation enthalpy (ΔHIE )

Enthalpy change when each atom in one mole of gaseous atoms loses one electron to form one mole of gaseous 1+ ions: Endothermic (+)

e.g. magnesium

Mg(g) → Mg+(g) + e-

5
New cards

(Second) Ionisation enthalpy (ΔHIE )

Enthalpy change when each ion in one mole of gaseous 1+ ions loses one electron to form one mole of gaseous 2+ ions: Endothermic (+)

e.g. magnesium

Mg+(g) → Mg2+(g) + e-

6
New cards

(First) Electron affinity (ΔHEA )

Enthalpy change when each atom in one mole of gaseous atoms gains one electron to form one mole of gaseous 1- ions: Exothermic (-) for many non metals

e.g. oxygen

O(g) + e- → O-(g)

7
New cards

(Second) Electron affinity (ΔHEA )

Enthalpy change when each ion in one mole of gaseous 1- ions gains one electron to form one mole of gaseous 2- ions: Endothermic (+) as adding negative electron to negative ion

e.g. oxygen

O- (g) + e- → O2-(g)

8
New cards

Enthalpy of atomisation (ΔHatm )

Enthalpy change when one mole of gaseous atoms is produced from an element in its standard state: Endothermic (+)

e.g. iodine

½ I2(s) → I(g)

9
New cards

Hydration enthalpy (ΔHhyd)

Enthalpy change when one mole of gaseous ions become hydrated (dissolved in water): Exothermic (-)

e.g. magnesium ions

Mg2+(g) → Mg2+(aq)

10
New cards

Enthalpy of solution (ΔHsol )

Enthalpy change when one mole of an ionic solid dissolves in an amount of water large enough so that the dissolved ions are separated and do not interact with each other: Varies

e.g. magnesium chloride

MgCl2(s) → Mg2+(aq) + 2 Cl-(aq)

11
New cards

Bond dissociation enthalpy (ΔHBDE )

Enthalpy change when one mole of covalent bonds is broken in the gaseous state: Endothermic (+)

e.g. I-I bond

I2(g) → 2 I(g)

12
New cards

Lattice enthalpy of formation (ΔHLE )

Enthalpy change when one mole of a solid ionic compound is formed from its constituent gaseous ions: Exothermic (-)

e.g. magnesium chloride

Mg2+(g) + 2 Cl- (g) → MgCl2(s)

13
New cards

Lattice enthalpy of dissociation (ΔHLE )

Enthalpy change when one mole of a solid ionic compound is broken up into its constituent gaseous ions: Endothermic (+)

e.g. magnesium chloride

MgCl2(s) → Mg2+(g) + 2 Cl- (g)

14
New cards

Enthalpy of vaporisation (ΔHvap )

Enthalpy change when one mole of a liquid is turned into a gas: Endothermic (+)

e.g. H2O(l)

H2O(l) → H2O(g)

15
New cards

Enthalpy of fusion (ΔHfus )

Enthalpy change when one mole of a solid is turned into a liquid: Endothermic (+)

e.g. Mg(s)

Mg(s) → Mg(l)

16
New cards

Mean bond enthalpy

  • Energy needed to break one mole of covalent bonds in the gaseous state

  • Averaged over a range of different compounds/molecules

17
New cards

State the assumptions made during calculations in calorimetry. (3 marks)

  • All heat released from the reaction was absorbed by the solution

  • Reaction goes to completion

  • Specific heat capacity of solution is 4.18 J-1 g-1

18
New cards

The enthalpy of combustion determined experimentally is less exothermic than that calculated using enthalpies of formation.

Give four possible reasons for this. (4 marks)

  • Heat escaped to surroundings

  • Incomplete combustion of (substance)

  • Evaporation of (substance) between weighing and setting light to it

  • Didn’t stir to make temperature the same throughout

19
New cards

Define the term enthalpy change

Heat energy change at a constant pressure

20
New cards

Suggest how the students’ method, and the analysis of the results, could be improved in order to determine a more accurate value for the enthalpy of reaction. Justify your suggestions.

Do not refer to the precision of the measuring equipment. Do not change the amounts or the concentration of the chemicals. (6 marks)

Stage 1 : Improved insulation

  • Insulate the beaker or use a polystyrene cup or a lid

  • To reduce heat loss

Stage 2 : Improved temperature recording

  • Record the temperature for a suitable time before adding the metal

  • To establish an accurate initial temperature

  • Record temperature values at regular time intervals

  • To plot the temperature results against time on a graph

Stage 3 : Improved analysis of results

  • Extrapolate the cooling back to the point of addition

  • To establish a (theoretical) maximum temperature OR temperature change

21
New cards

Explain why the enthalpy of hydration becomes less exothermic from Li+ to K+. (2 marks)

  • (From Li+ to K+ ) size (of ion) increases

  • Electrostatic attraction between metal ion and Oδ– of water decreases

22
New cards

Explain why the enthalpy of lattice dissociation for sodium oxide is greater than the enthalpy of lattice dissociation for sodium chloride. (2 marks)

  • Oxide ions have higher negative charge OR smaller size OR higher charge density/higher charge/size ratio than chloride ions

  • stronger attraction between O2- and Na+ ions

23
New cards

Give a reason why data books do not contain a value for the enthalpy of solution of sodium oxide. (1 mark)

It reacts with water OR It reacts to form a solution of NaOH

24
New cards

Explain why the enthalpy of hydration of fluoride ions is more negative than the enthalpy of hydration of chloride ions. (2 marks)

  • Fluoride ions/F ions are smaller OR F has a higher charge density

  • Stronger attraction of fluoride ion to δ+ on H/ electron deficient H in water

25
New cards
<p>Table 3 shows lattice enthalpies based on a perfect ionic model and lattice enthalpies from Born–Haber cycles for three metal chlorides.</p><p>Discuss the values in Table 3. In your answer you should </p><ul><li><p>compare the three values based on a perfect ionic model </p></li><li><p>compare the values based on a perfect ionic model to the values from a Born–Haber cycle for each compound. </p></li></ul><p>(6 marks)</p>

Table 3 shows lattice enthalpies based on a perfect ionic model and lattice enthalpies from Born–Haber cycles for three metal chlorides.

Discuss the values in Table 3. In your answer you should

  • compare the three values based on a perfect ionic model

  • compare the values based on a perfect ionic model to the values from a Born–Haber cycle for each compound.

(6 marks)

Stage 1: comparing values from perfect ionic model

  • Value for CaCl2 is larger OR Values for KCl and AgCl are similar OR Values for CaCl2 > AgCl > KCl

  • Ca2+ has a larger charge/ is a smaller ion OR Ag+ and K+ have smaller charge or larger ions

  • CaCl2 has stronger ionic bonds or stronger attraction between + and - ions (Ca2+and Cl- ) OR AgCl and KCl have weaker ionic bonds or weaker attraction between + and - ions (Ag+/ K+ and Cl- )

Stage 2: similarities in the perfect ionic model and Born-Haber cycle

  • CaCl2 has similar values (between the perfect ionic model and Born-Haber cycle)

  • KCl has similar values (between the perfect ionic model and Born-Haber cycle)

  • CaCl2 and KCl have (almost) perfect ionic bonding or + ions are point charges/(perfectly) spherical

Stage 3 difference in the perfect ionic model and Born-Haber cycle values

  • AgCl has larger difference in values (between the perfect ionic model and Born-Haber cycle)

  • AgCl contains (some) covalent character

  • Ag+ more polarising/distorts electron cloud more

26
New cards

Suggest a change to the student’s method, using the same apparatus, that would reduce the percentage uncertainty in the temperature change. Give a reason for your answer. (2 marks)

  • use a larger mass/amount of NH4NO3 / solid

  • so temperature change/decrease is greater OR final temperature is lower