Biology - Mendel

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86 Terms

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Alleles

  • Different forms of a gene that exist at a locus.

  • Wild type allele is typically the most commonly found allele in a population.

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Variant/Mutant Allele

  • Different from wildtype allele.

  • May or may not adversely affect gene product.

  • May or may not result in detectable phenotype.

<ul><li><p>Different from wildtype allele.</p></li><li><p>May or may not adversely affect gene product.</p></li><li><p>May or may not result in detectable phenotype.</p></li></ul><p></p>
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Homozygous

  • If identical alleles are present on both homologous chromosomes, the organism/cell is said to be _________ for that allele.

  • Two wild type alleles on tow mutant alleles highlight the same allele, so _____ can be used for both.

  • FC/FC and fc/fc.

<ul><li><p>If identical alleles are present on both homologous chromosomes, the organism/cell is said to be <strong>_________&nbsp;</strong>for that allele.</p></li><li><p>Two wild type alleles on tow mutant alleles highlight the same allele, so _____ can be used for both.</p></li><li><p>FC/FC and fc/fc. </p></li></ul><p></p>
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Heterozygous

  • If one allele is wild type* and the other allele is not (i.e., a mutant allele), the organism/cell is said to be HETEROZYGOUS for that allele. 

  • FC/fc.

<ul><li><p>If one allele is wild type* and the other allele is not (i.e., a mutant allele), the organism/cell is said to be <strong>HETEROZYGOUS</strong> for that allele.&nbsp;</p></li><li><p>FC/fc.</p></li></ul><p></p>
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Allelic Series

  • The known mutant alleles for a given gene plus its wild-type allele.

  • All alleles of the same gene. 

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Wild-Type

  • Most common allele in a population and functionally normal. 

<ul><li><p>Most common allele in a population and functionally normal.&nbsp;</p></li></ul><p></p>
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Flower Colour (FC) Gene

  • Purple flowers: functional protein produced.

  • White flowers: no functional protein (absence of pigment).

  • Gene named FC for “Flower Color.”

  • Functional allele = FC; non-functional allele = fc (both listed when referred to).

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Alleles on Structural & Functional Levels

  • Different alleles can arise from mutations in various regions of a gene (e.g., promoter, coding region, or intron).

  • Structural changes in DNA (mutations) can affect whether a functional protein is produced.

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Null Mutations

  • No functional protein produced; gene “OFF.”

  • m1, m2, m3, and m6. 

<ul><li><p>No functional protein produced; gene “OFF.”</p></li><li><p>m1, m2, m3, and m6.&nbsp;</p></li></ul><p></p>
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Leaky Mutation

  • Produces reduced protein activity; gene partially “ON.”

  • m4.

<ul><li><p>Produces reduced protein activity; gene partially “ON.”</p></li><li><p>m4. </p></li></ul><p></p>
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Synonymous Mutation

  • DNA change does not alter amino acid; no effect on protein function.

  • m5.

<ul><li><p>DNA change does not alter amino acid; no effect on protein function.</p></li><li><p>m5. </p></li></ul><p></p>
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Silent Mutation

  • Mutation with no functional consequence.

  • m7. 

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FC / FC and fc / fc

  • Example of homozygous wild-type and mutant genotypes. 

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+/+ and -/-

  • General symbols for wild-type and mutant alleles.

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FC⁺ / FC⁺ and fc⁻ / fc⁻: “+” and “−”

  • Denote wild-type and mutant forms of a specific gene.

  • “-” would suggest a complete loss of function.

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FC⁺ / FC⁺ and fc¹ / fc¹

  • Superscripts identify specific alleles.

  • Has partial function and is specified in the scientific paper. 

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Uppercase/Lowercase Allele

  • Uppercase indicates a dominant allele; lowercase indicates a recessive allele.

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Heteroallelic

  • Two different mutant alleles. 

  • What if an individual has two mutant alleles that are different from each other.

  • Also called transheterozygous or compound heterozygotes

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Hemizygous

  • (A situation where a cell/organism has only one copy of a gene/locus/chromosomal region).

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Hemizygous

  • A condition where a cell or organism has only one copy of a gene, locus, or chromosomal region.

  • Example 1: Deletion — the corresponding gene or region is missing on the homologous chromosome.

  • Example 2: Naturally single-copy genes — common for genes on X or Y chromosomes in XY individuals.

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True-Breeding (Flower Ex)

  • When plants consistently produce offspring with the same trait when self-crossed (e.g., white × white → white).

  • Occurs when individuals are homozygous for the allele(s) controlling the trait.

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Flower Colour Determination

  • May depend on one gene (FC) or multiple genes (FC, W, GD, HE).

    • Monogenic traits. 

    • Polygenic traits. 

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Monogenic Traits

  • Controlled by a single gene (often with multiple alleles). 

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Polygenic Traits

  • Controlled by multiple genes, producing more complex variation.

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Dominant Allele

  • In a heterozygous organism, its phenotype is expressed even when a recessive allele is present.

  • Typically represented by uppercase letters (e.g., A).

  • Dominance is relative — it may be observed at the organismal level but not always at the molecular or cellular level.

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Recessive Allele

  • Its phenotype is masked by the dominant allele in a heterozygote.

  • Example: If A is dominant, a is the recessive allele.

  • Typically represented by lowercase letters (e.g., a).

  • The terms dominant and recessive are always defined in relation to each other.

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Complete Dominance

  • The dominant allele (FC) completely masks the recessive allele (fc) in heterozygotes.

  • Both FC/FC and FC/fc produce the same phenotype (purple petals).

  • The fc allele is fully recessive when paired with FC.

  • Wild-type alleles are often dominant over their mutant counterparts.

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Haplosufficient

  • A single functional copy of a gene is enough to produce the wild-type phenotype.

  • Deals with a molecular mechanistic view. 

  • In FC/fc plants, one working FC allele provides sufficient gene product for normal color (purple petals).

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Incomplete Dominance

  • Not all alleles show simple dominant/recessive relationships.

  • The heterozygote displays an intermediate or blended phenotype between the two homozygotes.

  • One functional copy is NOT sufficient for a wild type phenotype.

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Four-o’clock Plants

  • Cᴿᴱᴰ / Cᴿᴱᴰ: Red petals.

  • Cᵂᴴᴵᵀᴱ / Cᵂᴴᴵᵀᴱ: White petals.

  • Cᴿᴱᴰ / Cᵂᴴᴵᵀᴱ: Pink petals (intermediate phenotype).

  • Heterozygotes show a phenotype midway between both homozygous parents.

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Haploinsufficiency

  • One functional copy is NOT sufficient for a wild type phenotype.

  • One wild type copy is not sufficient to produce a wild type phenotype. Could result in complete or incomplete dominance. 

  • More phenotypic difference. 

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Codominance I

  • Both alleles in a diploid organism show phenotypic effects.

  • Hbᴬ / Hbᴬ: Normal red blood cells.

  • Hbˢ / Hbˢ: Severe anemia, sickled cells.

  • Hbᴬ / Hbˢ: Some sickling under low oxygen, generally no anemia.

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Sickle Cell Anemia

  • Caused by a point mutation in hemoglobin.

  • Missense mutation: A → T at position 6 of the beta-globin chain.

  • Too inflexible and cannot go through capillaries/BVs.

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Hemoglobin A

  • Tetramer.

  • Two different gene that encode β-chain and α-chain.

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Hbs

  • Hbˢ differs from Hbᴬ by a missense mutation substituting Valine for Glutamic Acid at position 6 of the β-chain.

  • Hbᴬ / Hbˢ: No anemia; some sickling under low oxygen.

  • Common in parts of Africa; one Hbˢ allele gives malaria resistance.

  • This selective benefit is a heterozygous advantage.

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Codominance (II)

  • Genotypes & Phenotypes: Hbᴬ / Hbᴬ = normal RBCs; Hbˢ / Hbˢ = severe anemia, sickled RBCs; Hbᴬ / Hbˢ = no anemia, some slightly sickled RBCs.

  • Cause: Sickle Cell Anemia — point mutation in hemoglobin (Hbˢ vs Hbᴬ).

  • Dominance: Organism level — Hbᴬ is dominant; cellular level — incomplete dominance (some sickled cells).

  • Protein level: Both Hbᴬ and Hbˢ produced equally → codominance.

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Dominant Negative Effect

  • The gene product from the mutant allele interferes with the gene product from the wild type allele (see also Muller’s morph “Antimorph” and next slide), blocking the wild type function.

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Gain-of-Function Effect

  • The mutant allele acquires a new property not present in the wild type allele, and this new property causes a phenotype (see also slides on Muller’s morph “Hypermorph” and “Neomorph”).

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Dominance of a Mutant Allele Ex. 1

  • A mutant protein interacts with the normal protein it can render the protein as non-functional.

    • The shape is altered. 

  • Mutant affects the function by b/e non-functional or reduce its function. 

  • This can be diver, tetranometer, etc. 

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Dominance of a Mutant Allele Ex. 2

  • The normal protein is affected by binding to the mutated protein.

  • As a result, the dimer is non-functional.

<ul><li><p>The normal protein is affected by binding to the mutated protein. </p></li><li><p>As a result, the dimer is non-functional. </p></li></ul><p></p>
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Mutant Allele Classification

  • Dominance/recessive describes relationships between alleles, not individual alleles themselves.

  • A more useful system classifies alleles based on the type of genetic defect.

  • H.J. Muller (Nobel Prize, 1946) designated five classes of mutant alleles called “morphs” (meaning “form”).

  • These classifications are still used today, sometimes alongside modern equivalents.

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Amorph (Null) Mutations

  • “A” = absence; complete loss-of-function; also called null mutation.

  • Caused by deletions, missense mutations that inactivate protein, or nonsense mutations.

  • Classification is based on phenotype, not the type of molecular change.

  • Any mutation causing total loss-of-function is an amorphic allele.

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Hypomorphs

  • “Hypo” = reduced; allele is partially functional but below wild-type levels.

  • Most commonly used term in Muller’s system; modern equivalents: partial loss-of-function or leaky.

  • Mutation may affect a regulatory element (reducing gene expression).

  • Or a point mutation may reduce the activity of the gene product.

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Hypomorphs

  • Mutation in the regulatory region. 

  • mRNA stability, doesn’t interact as good with a protein partner, etc. 

  • All can lead to hypomorphism.

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Porphyrias

  • Porphyrias affect heme biosynthesis (8 genes).

  • Most disease-causing alleles are amorphic or hypomorphic; patients usually heterozygous or heteroallelic.

  • Heme precursors build up in the mitochondria.

  • Complete loss of heme is lethal.

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Porphyrias - Symptoms & Treatment

  • Light sensitivity, gum recession, extreme neuropathic pain.

    • Sensitivity in UV.

  • Heme or glucose injections can reduce symptoms.

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Hypermorph (Increased Function)

  • “Hyper” = increased; gene is more active than wild type.

  • Modern equivalent: gain-of-function (but distinct from neomorphs).

  • Cause: regulatory mutations increasing expression or coding mutations making protein more active; normal product, just more or more active.

  • Gene product is produced in normal cellular context (unlike neomorphs).

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Antimorphs

  • “Anti” = against; mutant gene product antagonizes wild-type function (in a heterozygous setting).

  • May dimerize with wild-type protein and inactivate it.

  • Can also compete for substrate or binding partner.

  • Usually dominant in inheritance.

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Myostatin Mutations

  • Function: Myostatin represses muscle growth; loss-of-function increases muscle mass.

  • Cattle: Stop mutation → amorph (no myostatin).

  • Sheep: Point mutation in non-coding mRNA creates microRNA binding site → hypomorph.

  • Outcome: Reduced myostatin activity increases muscle; mutation type determines amorph vs hypomorph.

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Neomorphs

  • “Neo” as in “new.”

  • The mutant gene product acquires a new function not found in the wild type protein.

  • This could involve new interactions, new substrates, or expression in the wrong cell type or developmental stage.

  • Neomorphs are generally dominant or semidominant.

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Oncogenes - Relocation

  • Example: Burkitt lymphoma caused by relocation of MYC oncogene next to a new regulatory element.

  • MYC: normally important for cell proliferation.

  • Mechanism: Recombination with chromosome 14 places MYC under incorrect regulatory control.

  • Result: gain of new function leading to abnormal cell proliferation (neomorph).

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Oncogenes - Hybrid

  • Disease: Chronic Myelogenous Leukemia (CML).

  • Mechanism: Translocation between chromosome 9 (ABL) and chromosome 22 (BCR1).

  • Result: Formation of BCR-ABL fusion gene → hybrid oncogene.

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Proto-Oncogene

  • The wild-type version of the oncogene.

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Mutation Classification

  • Classification schemes are not mutually exclusive; they describe mutations at different levels:

    • DNA/chemical level: e.g., frameshift.

    • Gene product level: e.g., functional vs nonfunctional.

    • Phenotypic level: mutant vs wild type.

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Allelic Interactions

  • Dominant vs recessive, incomplete (semi-) dominance, codominance.

  • Patterns depend on perspective, e.g., cell vs organism

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Muller’s Morphs

  • Classify all types of mutations.

    • Amorph, hypomorph, hypermorph, neomorph, and antimorph. 

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Complementation Tests

  • Used to determine if mutations are in the same or different genes.

  • Mutations that complement: occur in different genesnon-allelic mutations.

  • Mutations that fail to complement: occur in the same geneallelic mutations.

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Complementation in Genetic Screens

  • Complementation tests help identify new mutants.

  • After a genetic screen, we may have multiple mutants but don’t know if the same gene is affected more than once.

  • Complementation allows us to group mutants by gene.

  • Understanding this requires knowing how genetic screens are conducted.

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Chemical Mutagenesis (Classic Approach)

  • Method: Feed a chemical mutagen, usually to males, to mutagenize sperm.

  • Efficiency: More efficient than X-rays; one male can fertilize many females.

  • Common mutagen: EMS (ethylmethane sulfonate).

  • Effect: Mostly G→A and T→C transitions; used in Drosophila, C. elegans, Arabidopsis.

<ul><li><p><strong>Method:</strong> Feed a chemical mutagen, usually to males, to mutagenize sperm.</p></li><li><p><strong>Efficiency:</strong> More efficient than X-rays; one male can fertilize many females.</p></li><li><p><strong>Common mutagen:</strong> <strong>EMS (ethylmethane sulfonate)</strong>.</p></li><li><p><strong>Effect:</strong> Mostly <strong>G→A</strong> and <strong>T→C</strong> transitions; used in <strong>Drosophila, C. elegans, Arabidopsis</strong>.</p></li></ul><p></p>
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EMS-Induced Mutations

  • EMS (ethylmethane sulfonate, C₃H₈SO₃) is an alkylating agent that adds ethyl groups to nucleotides.

  • Causes mispairing during DNA replicationpoint mutations.

  • Commonly used in genetic screens.

  • Efficient for creating G→A and T→C transitions.

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Mutant Hunts = Genetic Screens

  • Animals are mutagenized and thousands of progeny are examined to isolate new mutants.

  • Heidelberg Screen (1979–1980, Drosophila): analyzed abnormal larval cuticle patterns.

  • Isolated 600 mutants representing 120 genes using complementation tests.

  • One of the most famous mutant hunts in developmental biology.

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Heidelberg Screen Impact

  • Revolutionized understanding of developmental processes.

  • Many genes discovered are conserved in humans.

  • Genes serve as models for human diseases.

  • Nobel Prize 1995 awarded to Eric Wieschaus & Christiane Nüsslein-Volhard.

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Preaxial Polydactyly

  • Can be caused by mutation in the regulatory region of the human sonic hedgehog gene, which is important for limb development.

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Mutagenesis & Screening (EMS Example)

  • Procedure: Feed EMS → establish heterozygous +/m stocks → test homozygous m/m flies for a phenotype (e.g., inability to fly to light).

  • Selection: Keep stocks where homozygotes show the phenotype.

  • Example Outcome: Suppose we now have 20 different stocks.

  • Question: How many different genes are affected?

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Mutagenesis Scenarios (EMS Example)

  • Extreme possibility I: 20 mutations are in 20 different genes.

  • Extreme possibility II: 20 mutations are in the same gene.

  • Use complementation tests to determine which scenario is correct.

  • This helps map mutations to specific genes in genetic screens.

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Complementation Tests - Mutant Collection (1)

  • 20 mutants labeled m1…m20, all fully recessive.

  • Homozygotes (m1/m1, m2/m2) show the mutant phenotype (cannot fly to light).

  • Heterozygotes with wild type (m1/+, m2/+) show wild type phenotype.

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Complementation Tests - Concept (2)

  • If m1 and m2 are in the same gene, m1/m2 heteroallelic flies fail to complement → mutant phenotype.

  • If m1 and m2 are in different genes, double heterozygotes (m1/+ ; +/m2) complement → wild type phenotype.

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Complementation Concept - Purpose (3)

  • Complementation tests determine if two mutations are alleles of the same gene.

  • Helps map mutations to specific genes in a collection.

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Crossing Homozygous Alleles

  • Take two homozygous recessive mutants with the same phenotype and cross them.

  • Wild type offspring: Alleles complement each other → mutations are in different genes.

  • Mutant offspring: Alleles fail to complement → mutations are in the same gene.

<ul><li><p>Take two homozygous recessive mutants with the same phenotype and cross them.</p></li><li><p>Wild type offspring: Alleles complement each other → mutations are in different genes.</p></li><li><p>Mutant offspring: Alleles fail to complement → mutations are in the same gene.</p></li></ul><p></p>
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Complementation in a Two-Gene Pathway (1)

  • Example: Purple flower pigment requires two genes: A (first step) and B (second step).

  • True-breeding lines homozygous for either A or B produce red pigment.

  • Often only the phenotype (white or red) is known, not the underlying genotype.

  • Consider four true-breeding white-petal lines; genotype unknown, only phenotype observed.

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Complementation in a Two-Gene Pathway Purpose (2)

  • Complementation tests determine whether mutations in different lines affect the same or different genes in the pathway.

  • Mutations in the same gene fail to complement → offspring show mutant phenotype.

  • Mutations in different genes complement → offspring show wild-type phenotype.

  • Helps map which gene is mutated even when phenotype alone is insufficient.

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Complementation in a Two-Gene Pathway - Case 1

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Complementation in a Two-Gene Pathway - Case 2

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Complementation Groups Setup (1)

  • Six true-breeding white-petal mutant lines: a, b, c, d, e, f.

  • Pairwise crosses performed; offspring scored as w = white (mutant) or p = purple (wild type / complemented).

<ul><li><p>Six true-breeding white-petal mutant lines: <strong>a, b, c, d, e, f</strong>.</p></li><li><p>Pairwise crosses performed; offspring scored as <strong>w = white (mutant)</strong> or <strong>p = purple (wild type / complemented)</strong>.</p></li></ul><p></p>
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Complementation Groups Results (2)

  • Group I: b, c, f (all fail to complement each other).

  • Group II: d, e (fail to complement each other).

  • Group III: a (no complementation partner among these lines).

<ul><li><p><strong>Group I:</strong> b, c, f (all fail to complement each other).</p></li><li><p><strong>Group II:</strong> d, e (fail to complement each other).</p></li><li><p><strong>Group III:</strong> a (no complementation partner among these lines).</p></li></ul><p></p>
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Complementation Groups Interpretations (3)

  • Each complementation group = mutations in the same gene.

  • Different groups = mutations in different genes (they complement).

  • Conclusion: these six mutants represent 3 genes affecting pigment.

<ul><li><p>Each complementation group = mutations in the <strong>same gene</strong>.</p></li><li><p>Different groups = mutations in <strong>different genes</strong> (they complement).</p></li><li><p><strong>Conclusion:</strong> these six mutants represent <strong>3 genes</strong> affecting pigment.</p></li></ul><p></p>
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Distinct Mechanisms for Blonde Hair

  • Phenotypic similarity: Solomon Island blond hair (Melanesia) and Swedish blond hair (Northern Europe) look alike.

  • Different genetic causes: Each form of blond hair is due to a mutation in a different gene.

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Solomon Island Blond Hair

  • Gene: TYRP1 (Tyrosinase-related protein 1).

  • Genotype: Homozygous recessive (TYRP1⁻ / TYRP1⁻).

  • Inheritance: Must inherit the blond variant from both parents.

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Swedish Blond Hair

  • Gene: KITLG (KIT Ligand).

  • Genotype: Homozygous recessive (KITLG⁻ / KITLG⁻).

  • Inheritance: Must inherit the blond variant from both parents.

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F₁ Hybrid Cross Blonde Hair

  • Genotype: TYRP1⁻ / TYRP1⁺ ; KITLG⁻ / KITLG⁺.

  • Phenotype: Not blond—likely darker hair.

  • Interpretation: The wild-type alleles (TYRP1⁺, KITLG⁺) are dominant over the blond variants.

  • Concept: Example of complementation — two mutations in different genes restore the wild-type phenotype.

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Spirit Bear

  • Blonde, not albino.

  • Point mutation in melanocortin 1 receptor (Mc1r) affects melanocyte pigment production.

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Rescue by Complementation - Problem

  • A mutant line from a genetic screen may contain multiple mutations (e.g., m₁ in gene 1 and m₂ in gene 2).

  • Even if m₁ is identified, it’s uncertain whether additional mutations contribute to the phenotype.

  • Goal: Determine which mutation actually causes the observed defect.

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Rescue by Complementation - Solution

  • Introduce a wild-type copy of the suspected gene (m₁⁺) into the mutant.

  • The added gene may integrate into the genome (transgenic) or remain independent (transformant, e.g., plasmid).

  • If phenotype is rescued, the defect was caused by m₁.

  • If not rescued, another gene (e.g., m₂) likely contributes to the phenotype.

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Complementation Test - Host Cell [Control] (1)

  • Genotype: Mutant allele ura3.

  • Phenotype: Cannot synthesize uracil → fails to grow without added uracil.

  • Interpretation: Mutation in ura3 disrupts pyrimidine (uracil) biosynthesis.

  • Result on Minimal Medium (–Uracil): No colony growth.

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Complementation Test - Experimental (2)

  • Genotype: ura3 host transformed with plasmid carrying URA3⁺ (wild-type).

  • Mechanism: Functional URA3⁺ complements the defective ura3 allele.

  • Phenotype: Regains ability to synthesize uracil autonomously.

  • Result on Minimal Medium (–Uracil): Colonies grow → phenotype rescued.

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Complementation Test - Transformant [Negative Control] (3)

  • Genotype: ura3 host transformed with plasmid carrying unrelated gene (e.g., Leu2⁺).

  • Phenotype: Still unable to grow without uracil—mutation unrescued.

  • Control Purpose: Confirms that complementation is gene-specific, not due to plasmid presence.

  • Result on Minimal Medium (–Uracil): No colony growth.