Estimation of Population Proportion + Comparing Population Means

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/12

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

13 Terms

1
New cards

population proportion

the percentage of people who agree/disagree

2
New cards

p hat, the sample proportion, a point estimate of the actual proportion p

3
New cards

p̂ point estimation formula

# of yes/no / n where n is the size of the sample

4
New cards

p̂ interval estimation formula

[ p̂ - Z √ (p̂ (1 - p̂)) / n, p̂ + Z √ (p̂ (1 - p̂)) / n ]

( n mist be sufficiently large )

5
New cards

Prove n is sufficiently large for population proportion

(n * p̂ >= 15) and ( n * (1 - p̂) >= 15)

6
New cards

What is the half length of a population proportion at a 95% confidence level?

Z √ (p̂ (1 - p̂)) / n

7
New cards

Steps to evaluate population proportion

  • Formula

  • Plug In

  • Interperet

  • Check Assumptions

8
New cards

Find the sample size of a population proportion given a half length of .05, a confidence interval of 99%, assume p = .5. Is the sample size liberal or conservative?

Z² * .5(.5) / .05²

liberal

9
New cards

Find the sample size of a population proportion given a half length of .1, a confidence interval of 90%, and assume no information on p. Is the sample size liberal or conservative?

Z² * .25 / .1²

conservative

10
New cards

Why is .25 a conservative estimate of p̂?

The maximum value of p(1 - p) is .25

11
New cards

Make a 92% confidence interval estimating the distance of µ1 - µ2

[ (ā - ē) ± t.96, n+m-2 * Sp √(1/n + 1/m) ]

12
New cards

Sp formula

( (n - 1) * Sx2 + (m - 1) * Sy2 ) / (n + m - 2)

13
New cards

Interval estimation of the distance between of µ1 - µ2 assumptions

  • Normal Data for BOTH n and m

  • Equal Approximate Variance

  • Independent Samples