d/dx [cos] =
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Calculus
AP Calculus BC
Unit 2: Differentiation: Definition and Fundamental Properties
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-sinx * x’
d/dx [cotx] =
-csc²x * x’
d/dx [cscx] =
-cscxcotx * x’
d/dx = [sinx] =
cosx * x’
d/dx [tanx] =
sec²x * x’
d/dx [secx] =
secxtanx * x’
d/dx [√x] =
1/2√x
d/dx [1/x] =
-1/x²
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Flashcard (46)