1/54
Looks like no tags are added yet.
Name | Mastery | Learn | Test | Matching | Spaced |
---|
No study sessions yet.
Lipids
Heterogenous tissue components
Lipids
Bulk of organic matter of living cells with protein and carbohydrates
Esters
Lipids are actual or potential ____ of fatty acids.
Carboxylic acid; Alcohol
Many lipids result from the chemical reaction oof a ____ with an _____
Triglycerides
Esters formed from one molecule of glycerol (an alcohol) and three fatty acid molecules (carboxylic acids)
Insoluble
Lipids are ___ in water
Soluble
Lipids are ___ in fat solvents (ether, chloroform, hot alcohol, and benzene)
Simple Lipids
Esters of fatty acids with various alcohols
Compound Lipids
Esters of fatty acids with alcohols and a phosphate, carbohydrate or nitrogenous component
Derived Lipids
Derivatives obtained by the hydrolysis of simple and compound lipids.
Detection of certain characteristic groups
Analysis of lipids includes _____ based on their reactions with various reagents.
Saponification Number and the Iodine Number
Two determinations applied to fats demonstrating following properties of fats:
Solubility in organic solvents
Formation of emulsion
Hydrolysis of fats to their constituent substances
Saponification
Process wherein fats are boiled with
alkali, producing glycerol and the metallic salt of the fatty acid (i.e., soaps).
Sodium
→ Hard Soaps
Potassium
→ Soft Soaps
RCOOH + KOH
Fatty acid + Potassium hydroxide
(Palmitic acid)
→ RCOOK + H2O
→ K salt of fatty acid + H2O
(Potassium palmitate)
Saponification Number
Number of mg of KOH required to neutralize the fatty acid liberated in the saponification of 1g fat or oil.
Saponification Number
It is a measure of the mean molecular weight (or
chain length) of all the fatty acids present in the
sample in the form of triglycerides.
True
TRUE OR FALSE: The 3 moles of fatty acids in a mole of triglyceride will neutralize 3 moles of KOH per mole of triglyceride split.
↑ Saponification Number
= ↓ Average Molecular Weight of Fatty Acid
Saponification Number
The average molecular weight of the fatty acid may be calculated directly from the ____.
known amount of KOH in alcohol
In the determination of the saponification number, a _________ is used to split the ester linkages of the triglycerides.
neutralize the freed fatty acids
The excess KOH over and above required to ______ is determined by titrating to a phenolphthalein end point.
difference
The saponification number is then calculated from the _____ in the amount of standard HCl needed to neutralize a known volume of KOH in the blank and the excess KOH in the solution containing the sample of fat.
Saponification Number Formula
(𝑉𝑜𝑙. 𝑜𝑓 𝐻𝐶𝑙 𝑖𝑛 𝑏𝑙𝑎𝑛𝑘 − 𝑉𝑜𝑙. 𝑜𝑓 𝐻𝐶𝑙 𝑖𝑛 𝑠𝑝𝑒𝑐𝑖𝑚𝑒𝑛) × 𝑁 𝑜𝑓 𝐻𝐶𝑙 × 56.1 / 1.5 × 𝑠𝑝𝑒𝑐𝑖𝑓𝑖𝑐 𝑔𝑟𝑎𝑣𝑖𝑡𝑦 𝑜𝑓 𝑠𝑝𝑒𝑐𝑖𝑚𝑒𝑛
1st Step of Identifying the Unknown Oil Sample
Compute for the saponification number using the specific gravity of each possible oil. If the given specific gravity is in a range, try random values within the range.
Castor Oil
179 - 185 Saponification Number
Corn Oil
188 - 193 Saponification Number
Olive Oil
190 - 195 Saponification Number
Coconut Oil
255 - 258 Saponification Number
2nd Step of Identifying the Unknown Oil Sample
Compare the computed saponification number with the theoretical range of saponification number for each type of oil.
3rd Step of Identifying the Unknown Oil Sample
Choose the type of oil where the computed saponification number is closest to or falls within its theoretical range.
Double bonds (unsaturated lipids/fats); point of unsaturation
When fats containing ____ are treated with iodine, bromine, iodine bromide or iodine chloride, the double bonds become halogenated. They will add a halogen at the.
Iodine Number
Number of grams of iodine required to saturate 100g of unsaturated fat.
Iodine Number
A measure of the relative degree
of unsaturation of a fatty acid.
Wijs Method
Uses Iodine Chloride (ICl) as a carrier
Rosenmund-Kuhnhenn Method
Uses a pyridine sulfate dibromide solution
Hanus Method
Uses Iodine Bromide as carrier. Mainly determines the excess bromine remaining in the solution after the sample was reacted with a known amount of bromine (blank).
TITRATION SUMMARY
Amber/Brown → Light Yellow → Add starch → Blue → Colorless
Iodine Number Formula
(𝑉𝑜𝑙𝑜𝑓𝑁𝑎 𝑆 𝑂 𝑖𝑛𝑏𝑙𝑎𝑛𝑘−𝑉𝑜𝑙𝑜𝑓𝑁𝑎2𝑆2𝑂3 𝑖𝑛𝑠𝑝𝑒𝑐𝑖𝑚𝑒𝑛)×𝑁 o𝑓 𝑡𝑖𝑡𝑟𝑎𝑛𝑡 × 12.69 / 0.3 × 𝑠𝑝𝑒𝑐𝑖𝑓𝑖𝑐 𝑔𝑟𝑎𝑣𝑖𝑡𝑦 𝑜𝑓 𝑠𝑝𝑒𝑐𝑖𝑚𝑒𝑛
1st Step in Identifying the Unknown Oil Sample of Iodine Number
Compute for the iodine number using the specific gravity of each possible oil. If the given specific gravity is in a range, try random values within the range.
2nd Step in Identifying the Unknown Oil Sample of Iodine Number
Compare the computed iodine number with the theoretical range of iodine number for each type of oil.
3rd Step in Identifying the Unknown Oil Sample of Iodine Number
Choose the type of oil where the computed saponification number is closest to or falls within its theoretical range.
Olive Oil
75 - 95 Iodine Number
Coconut Oil
8 - 9.5 Iodine Number
a) Solubility in water
Which of the following is NOT a characteristic of lipids?
a) Solubility in water
b) Insolubility in water
c) Solubility in fat solvents
d) Esters of fatty acids
b) Simple lipids, compound lipids, and derived lipids
What are the three types of lipids based on their composition?
a) Fats, oils, and waxes
b) Simple lipids, compound lipids, and derived lipids
c) Phospholipids, glycolipids, and sterols
d) Saturated, unsaturated, and trans fats
d) Nitrogenous base
Which component is NOT included in the structure of compound lipids?
a) Fatty acids
b) Alcohols
c) Phosphate
d) Nitrogenous base
c) Derived lipids
Which type of lipid is formed by derivatives obtained by the hydrolysis of simple and compound lipids?
a) Simple lipids
b) Compound lipids
c) Derived lipids
d) Phospholipids
c) Solubility in organic solvents and hydrolysis of fats
Which properties of fats are demonstrated in the determination of saponification number and iodine number?
a) Solubility in water and formation of emulsion
b) Formation of emulsion and hydrolysis of fats
c) Solubility in organic solvents and hydrolysis of fats
d) Solubility in organic solvents and formation of
emulsion
a) Wijs Method
Which method for determining iodine number uses iodine monochloride (ICl) as a carrier?
a) Wijs Method
b) Rossenmund-Kuhnhenn Method
c) Hanus Method
d) None of the above
b) Iodine number
In the Hanus Method, what is primarily determined by measuring the excess bromine remaining in the solution after the sample reacts?
a) Amount of saturated fats
b) Iodine number
c) Unsaturated fatty acids
d) Presence of impurities
a) Position of the double bond
Which factor primarily determines a double bond's ability to add halogen in the determination of iodine number?
a) Position of the double bond
b) Temperature of the reaction
c) Length of the fatty acid chain
d) Concentration of the halogen reagent
c) To avoid interference from light-sensitive reagents
Why is the reaction and titration in the Hanus Method performed in relatively dark conditions?
a) To prevent excess bromine
b) To stabilize iodine radicals
c) To avoid interference from light-sensitive reagents
d) To accelerate the reaction rate