Electrophilic Addition of Halogens to Alkenes

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13 Terms

1
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What is an electrophile?

A species which is strongly attracted to electrons because it is electron-deficient.

2
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Electrophiles are usually…

Positively charged.

This means they have the ability to accept a lone pair of electrons.

3
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What is a nucleophile?

A species which is strongly attracted to positive charge.

4
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Nucleophiles are usually…

Negatively charged.

5
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How do nucleophiles react?

Nucleophiles react by donating a lone pair of electrons to an electron-deficient species to form a covalent bond.

6
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Do halogen molecules have permanent dipoles?

No.

Halogens are non-polar molecules.

7
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Explain why electrophiles are attracted to the C=C double bonds in alkenes.

  • The C=C double bond is a region of high electron density.

  • Electrophiles are attracted to electrons.

8
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Describe what happens when a halogen molecule (bromine) approaches the C=C double bond in an alkene molecule(ethene).

  • As the bromine molecules approaches the ethene molecule, the high electron density of the C=C double bond repels the electron pair in the bromine molecule.

  • This induces a dipole in the bromine molecule.

  • The bromine atom nearest to the double bond exhibits a partially positive charge (δ+). This positive atom acts as the electrophile.

<ul><li><p>As the bromine molecules approaches the ethene molecule, the high electron density of the C=C double bond <strong>repels</strong> the electron pair in the bromine molecule.</p></li></ul><p></p><ul><li><p>This induces a dipole in the bromine molecule.</p></li></ul><p></p><ul><li><p>The bromine atom nearest to the double bond exhibits a partially positive charge (<span>δ+). This positive atom acts as the </span><strong><span>electrophile.</span></strong></p></li></ul>
9
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Describe what happens when a dipole has been induced in the halogen (bromine) molecule.

  • The C=C double bond breaks.

  • The bromine atom with a partially positive (δ+) charge is attracted to the region of high electron density of the double bond.

  • This causes a bond to be formed between this delta positive bromine atom and one of the carbon atoms in the double bond, causing the double bond to break.

  • A carbocation is formed.

<ul><li><p><span>The C=C double bond breaks.</span></p></li></ul><p></p><ul><li><p><span>The bromine atom with a partially positive </span>(δ+) <span>charge is attracted to the region of high electron density of the double bond.</span></p></li></ul><p></p><ul><li><p><span>This causes a bond to be formed between this delta positive bromine atom and one of the carbon atoms in the double bond, causing the double bond to break.</span></p></li></ul><p></p><ul><li><p><span>A carbocation is formed.</span></p></li></ul>
10
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What happens to the electrons in the bromine molecule when a bond is formed between the partially positive bromine atom and one of the carbon atoms in the double bond?

Electrons from the Br-Br bond move to the partially negative bromine atom, leaving a bromide ion with a lone pair of electrons.

This is an example of heterolytic bond fission.

<p>Electrons from the Br-Br bond move to the partially negative bromine atom, <mark data-color="yellow">leaving a bromide ion with a lone pair of electrons</mark>.</p><p>This is an example of heterolytic bond fission.</p>
11
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What is heterolytic bond fission?

When the covalent bond breaks unevenly, and one of the bonded atom receives the shared pair of electrons.

12
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What is a carbocation?

A carbocation is a positively charged carbon ion formed by the loss of a bonding electron.

This means there are 3 covalent bonds instead of 4.

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Describe what happens after a carbocation is formed.

  • The bromide ion with a negative charge approaches the carbocation and forms a covalent bond with it by donating its lone pair of electrons.

  • The product formed is 2-dibromoethane.

<ul><li><p>The bromide ion with a negative charge approaches the carbocation and forms a covalent bond with it by donating its lone pair of electrons.</p></li></ul><p></p><ul><li><p>The product formed is 2-dibromoethane.</p></li></ul>