Photons and wave-particle duality

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89 Terms

1
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Light waves can behave like _____ (e.g. photons) and _____

particles

waves

2
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What is the phenomenon called when light behave like particles and waves?

The wave-particle nature of light/ wave-particle duality

3
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How do we know light interacts with matter (e.g. electrons) as a particle and what it is?

The photoelectric effect- phenomenon in which electrons are emitted from surface of metal upon the absorption of electromagnetic radiation

4
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How do we also know light behaves like a wave?

As it propagates through space shown from diffraction and interference of light in Young’s double slit experiment

5
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Electromagnetic waves carry energy in _____ called ___

discrete packets

photons

6
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Energy of photons are quantised according to what equation?

E=hf

7
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Although the wave theory provided good explanations for phenomena such as interference and diffraction, but _______________

it failed to explain the photoelectric effect

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term image
9
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photons are ___________

fundamental particles which make up all forms of electromagnetic radiation

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Photon definition

Massless “packet” or a “quantum” of electromagnetic energy

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This means energy is not transferred continuously but as ______ of energy.

What does this mean?

discrete packets

each photon carries a specific amount of energy, and transfers this energy all in one go, rather than supplying a consistent amount of energy

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How can you calculate energy of a photon (given):

E=hf

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Wave equation units: E = hc/𝛌

E= energy of photon (J)

h= Planck’s constant (Js)

c= speed of light (m/s)

f= frequency (Hz)
𝛌= wavelength (m)

14
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What does the wave equation show?

  • Higher the frequency of EM radiation, higher energy of photon

  • Energy of a photon is inversely to wavelength, E∝1/λ

  • A long-wavelength photon of light has a lower energy than a shorter-wavelength photon

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Energy of photons is inversely proportional to what?

Wavelength

16
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How to calculate number of photons hitting the surface every second?

Power of light source/ energy of 1 photon

17
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What is an electronvolt?

  • Unit which is commonly used to express very small energies

  • cuz quantum energies tend to be smaller than 1 J

18
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What equation is electronvolt derived from?

definition of pd

V= E/Q

19
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What does this mean?

When an electrovolt travels through a potential difference, energy is transferred between 2 points in a circuit or electric field

20
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What is an electronvolt defined as and why?

Energy gained by an electron travelling through a p.d. of 1 volt

1 eV= 1.6× 10^-19 J

cuz…

if an electron, with charge 1.6 ×10^-19, travels through a pd of 1V, E transfer is = to

E=QV = 1.6× 10^-19 X 1V = 1.6×10^-19 J

21
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When a charged particle is accelerated through a p.d. it gains _____ ______?

Kinetic energy

22
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How does this relate to electronvolts and what equation does this make?

If an electron accelerates from rest, an electronvolt is = to KE gained

eV= ½ mv²

23
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What can equation be rearranged to give?

speed of electron

<p>speed of electron </p><p></p>
24
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How convert between eV and J?

eV —>J: x 1.6×10^-19

J —>eV: 1.6 × 10^-19

25
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What can be used to investigate wave properties of electrons?

Electron diffraction tubes

26
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How is electron diffraction done?

  • Electrons are accelerated in an electron gun (produced a narrow stream of electrons from heated cathode, which is then accelerated by anode)

  • Accelerated to high potential

  • Directed through a thin film of graphite

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What happens when electron diffraction is done?

  • Electrons diffract from gaps between carbon atoms

  • Produce a circular pattern on a fluorescent screen (emit light when exposed to high energy rays)

<ul><li><p>Electrons diffract from gaps between carbon atoms </p></li><li><p>Produce a circular pattern on a fluorescent screen (emit light when exposed to high energy rays)</p></li></ul>
28
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What does increasing voltage between anode and cathode do?

Causes energy and ∴ speed, of electrons to increase

29
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What is the KE of an electron proportional to? (+equation)

Voltage across the anode-cathode

Ek = ½ mv2 = eV

30
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What does electron diffraction show?

Evidence for wave-like behaviour of particles as they diffract which is a wave-like behaviour

31
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Who discovered matter, such as electrons can behave as waves?

Louis de Broglie

32
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What did De Broglie show?

A diffraction pattern is produced when a beam of electrons is directed at a thin graphite film

33
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Diagram of experiment

knowt flashcard image
34
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How does the diffraction rings change for low and high accelerating _____?

VOLTAGE

Low- far apart- increases diameter of rings

High- close together- reduced diameter of given ring

35
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What must happen in order to observe the diffraction of electrons?

Must be focused through a gap similar to their size, e,g. atomic lattice

36
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Why was graphite film ideal for the purpose of having a gap similar to size of electron?

Cuz it has crystalline structure

gaps between neighbouring planes of atoms in crystals act as slits, allowing electron waves to spread out and create a diffraction pattern

37
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What is the diffraction pattern observed as on a screen?

Concentric rings (2 or more rings have same centre point)

38
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If electrons acted as electrons in this experiment what would be observed?

partiles would be distributed uniformly across the screen

39
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What is known as de broglie equation:

λ= h/p (given)

40
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What are units and symbols mean in λ=h/p?

λ= de Broglie wavelength(m)

h= Planck’s constant (Js)

p= momentum (kg m s-1)

41
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What does de Brogile equation link + what does this show?

particle-like property (momentum) to wave-like property (wavelength) demonstrating wave-particle duality for all particles

42
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How can de Broglie wavelength be related to speed of a moving particle:

Since momentum p=mv

therefore

λ=h/mv

43
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How to form equation that the de Broglie equation gives form relates de Broglie wavelength of particle to its KE + what is it?

Combining:

de Brogile equation - λ=h/p

KE- E= ½ mv²

—> momentum and KE relate by: p=√2mE

Gives:

λ= h/ √2mE

E- KE of particle (J)

m- mass of particle (kg)

v- speed of particle (m/s)

44
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What are the units of λ= h/ √2mE?

E- KE of particle (J)

m- mass of particle (kg)

v- speed of particle (m/s)

45
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What is the photoelectric effet?

Phenomena in which electrons are emitted from surface of metal upon absorption of electromagnetic radiation

46
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Electrons removed from metal in this manner are known as _____

photoelectrons

47
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What does the photoelectric effect provide evidence for and how this is shown?

that light is quantised/ carried in discrete packets

because…

each electron can absorb only a single photon

means only frequencies of light above threshold frequency will emit a photoelectron

48
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What is the particle nature of light?

  • In classical wave theory, EM radiation is assumed to behave as a wave

  • Demonstrated by EM light exhibiting phenomena such as diffraction and interference

  • Photoelectric effect + atomic line spectra can only be explained if EM radiation is assumed to behave as particles

49
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How to demonstrate photoelectric effect?

  • On gold leaf electroscope

  • Plate of metal, usually zinc, is attached to a gold leaf, which initially has neg charge, causing it to be repelled by central negatively charged rod

  • Neg charge. electrons build ip on zinc plate

  • UV light is shone onto metal plate, leading to emission of photoelectrons

  • Causes extra electrons on central rod and gold leaf to be removed, so the gold leaf begins to fall back towards central rod. Cuz they become less negatively charge hence repel less

<ul><li><p>On gold leaf electroscope</p></li><li><p>Plate of metal, usually zinc, is attached to a gold leaf, which initially has neg charge, causing it to be repelled by central negatively charged rod</p></li><li><p>Neg charge. electrons build ip on zinc plate </p></li><li><p>UV light is shone onto metal plate, leading to emission of photoelectrons </p></li><li><p>Causes extra electrons on central rod and gold leaf to be removed, so the gold leaf begins to fall back towards central rod. Cuz they become less negatively charge hence repel less </p></li></ul>
50
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What where the observations of the gold leaf experiment?

  • Placing UV source closer to metal plate causes gold leaf to fall more quickly

  • Using higher f light source does not change how quickly gold leaf falls

  • Using filament light source causes no change in gold leaf’s position

  • Using pos charged plater causes no change in gold leaf’s position

  • Emission of photoelectrons happens as soon as the radiation is incident on surface of metal

51
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Why does placing the UV light source closer to metal plate cause gold leaf to fall more quickly?

  • Placing UV source closer to plate increases intensity incident on the surface of the metal

  • Increasing intensity/ brightness of incident radiation increases n. of photoelectrons emitted per second

  • ∴ gold leaf loses neg charge more rapidly

52
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Why does using a higher frequency light source not change how quick the gold leaf falls?

  • Max KE of emitted electrons increases w. the frequency of the incident radiation

  • In the case of the photoelectric effect, energy and frequency are independent of intensity of radiation

  • So, intensity of incident radiation affects how quickly the gold leaf falls, not the frequency

53
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Why does using a filament light source cause no change in the gold leaf’s position?

  • If the incident f is below certain threshold frequency, no electrons are emitted, no matter the intensity of the radiation

  • Filament light source has frequency below the threshold frequency of the metal, so no photoelectrons are released

54
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Why does using a pos charged plate cause no change in gold leafs position?

  • If plate is pos charged, means there is an excess of pos charge on surface of metal plate

  • Electrons are neg charged, so will not be emitted unless they are on surface of metal

  • Any electrons emitted will be attracted back by pos charges on surface of metal

55
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Why does emission of photoelectrons happen as soon as radiation is incident on surface of the metal?

  • A single photon interacts with a single electron

  • If energy of photon is equal to the work function of metal, photoelectrons will be released instantaneously

56
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number of photoelectrons emitted is ____ to the number of photons incident on the surface in which the photoelectric effect is taking place

equal

57
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Since energy is always conserved, energy of an incident photon is equal to:

Work function + max KE of photoelectron

58
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Energy of a photon, hf, is transferred to electron to release it from material (work function) and remaining amount is given as KE to emit photoelectron

59
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What is photoelectric equation + what units mean?

E= hf= Φ + ½ mv2max

h= plancks constant (Js)

f= frequency of incident radiation (Hz)

Φ= work function of the material (J)
KE max= max KE of photoelectrons (J)

60
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What does photoelectric equation demonstrate:

  • If the incident photons do not have a high enough frequency and energy to overcome the work function (Φ), then no electrons will be emitted

  • hf0 = Φ, where f0 = threshold frequency, photoelectric emission only just occurs

  • KEmax depends only on the frequency of the incident photon, and not the intensity of the radiation

  • The majority of photoelectrons will have kinetic energies less than KEmax

61
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How can photoelectric equation be rearranged into straight line equation:

y = mx + c

KEmax = hf - Φ

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if graph of max KE against f, what are the key elements:

  • The work function Φ is the y-intercept

  • The threshold frequency f0 is the x-intercept

  • The gradient is equal to Planck's constant h

  • There are no electrons emitted below the threshold frequency f0

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Threshold frequency definition:

The minimum frequency of incident electromagnetic radiation required to remove a photoelectron from the surface of a metal

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Threshold wavelength definition:

The longest wavelength of incident electromagnetic radiation that would remove a photoelectron from the surface of a metal

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work function Φ/ threshold energy, of a material definition:

The minimum energy required to release a photoelectron from the surface of a metal

66
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an electron can only escape from the surface of the metal if it absorbs a photon which has an energy equal to __ or higher

Φ

67
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What is KE related to?

Independent of intensity

Dependent of frequency

68
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What is photoelectric current?

rate of emission of photoelectrons emitted per second

69
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What is photoelectric current proportional to and why?

intensity of radiation incidence to metal

because intensity is proportional to number of photons striking the metal per second, since each photoelectron absorbs a single photon, the photoelectric current must be proportional to intensity of incident radiation

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term image
71
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work function is = to

Φ=hf0

72
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Wave theory and particle theory: No electrons are emitted if the incident radiation frequency f0

Wave theory: E spreads out evenly over wavefront, each wave would add more E to electron. eventually electron would emit, at any f

Particle theory: Each photon has energy E=hf. If f of photon is greater than f0, then the energy of photon is great enough to eject an electron

73
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Wave theory and particle theory: speed of emitted electrons depends only on the f

Wave theory: E is proportional to I for wave. ∴ more I light would pass more energy to the electrons. they would emit faster

Particle theory: E=hf ∴ greater f meant greater energy of photon and greater emitted speed of electrons

74
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Wave theory and particle theory: electron emission was instantaneous

Wave theory: If wave was incident for long enough, enough energy would eventually transfer and an electron would emit with a time delay

Particle theory: above a certain f, one photon interacts with one electron and is emitted immediately

75
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How experiment to find planck’s constant works?

  • Using LEDs by considering the energies of the photons they emit

  • LEDs convert electrical energy into light energy

  • Emit visible photons when p.d. across them is above critical value (threshold p.d)

  • When this happens it emits photons of specific wavelength

  • at this p.d work done is given by W=VQ

  • Energy is same as energy of the emitted photon

  • Threshold p.d X charge on electron = energy of emitted photon

    Ve= hf

  • Expressing this in terms of wavelength of emitted photon wavelength gives

    eV= hc/λ

76
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From de Broglie equation what is wavelength inversely proportional to?

Momentum, p

<p>Momentum, <em>p</em></p>
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What is the change to a line in graph for photoelectric effect if the metal has work function energy greater than previous one?

Shifted to the right threshold frequency is greater

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EQ: Describe + explain photoelectric effect in terms of photons interacting with the surface of a metal?

  • Is removal of electrons if exposed to em rad

  • Surface electrons are released

  • Single photon interacts single electron

  • E is conserved

  • E of photon= hf

  • Einsteins photoelectric equation: hf= φ + KE

  • Electrons released when hf>φ/ f is greater than threshold f, none is opposite

  • KE is independent if I when electrons r emitted

  • I increases rate of electrons released

  • I has no effect when there is no emission of electrons

79
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EQ: Explain what energy levels are + how they can be used to explain the emission of photons from atoms

  • Electrons have discrete energies in atom

  • each photon produced by electron moving between levels

  • photon E = to E difference between levels

    E1-E2= hf

  • Electron loses energy

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EQ: If 2 laser have same power but 2nd has higher f, explain why laser emitting 2nd light emits fewer photons per second compared to 1

2 has higher f ∴ energy per photon is higher so fewer needed to produce same power

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How to work out current ?

Electrons emitted per second X 1.6×10^-19 (elementary charge)

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Reasons photoelectron emission is not 100 per cent

-Reflection/ absorption at top layer

- Photons below threshold e/ photons absorbed by electrons wo being released

- recombination of ion pairs in insulating layer

-scattering of light/photons out of insulating layer

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How to calculate p.d.

eV= ½ mv²

V= ½ mv² / e

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what is speed of photons?

speed of light

85
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photons

particles of light

Sometimes referred to as a quantum of energy of EM radiation. A quantum in this context just means a set finite amount

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What is plancks constant measured in?

Js

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What quantity can be measured in eV?

energy

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What is de broglies equation and what does it do?

λ= h/p

relates wave and particle properties wavelength wave-property and momentum a particle property

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potential divider curcuit equation

<p></p>