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Vector Line equations given a point and direction
l=a+td
Vector line equation given 2 points
l=a+t(b-a)
Vector line to Cartesian equation (2 dimensions)
Split vector into i and j components
Equate each component to x and y. There will be 3 variables - x, y, and t
Solve the x equation for t, so you have t in terms of x
Sub this equation of t into y
Vector line to Cartesian equation (3 dimensions)
Split vector into i and j components
Equate each component to x, y, and z
Solve each one for t, so you have t in terms of x, y, and z
Equate them all, so you have …x=…y=…z
Cartesian equation to vector line (2 dimensions)
Find any point on the line - try x or y = 0
Convert the point to a vector. This will become a.
Take the gradient - m - and turn it into a vector using rise/run, run =1 i.e. gradient of 2 turns into i + 2j. The line is parallel to this vector, so this becomes d. DONE!
Cartesian equation into vector line (3 dimensions)
Let each part of the equation equal t
Solve for x, y, z in terms of t
Equate them for i, j, and k
Shortest distance from a point to a line
Let point A equal the point, point P equal a point on the line
Distance from A to P is AP, find AP=P-A
Solve AP·d =0 to find t where they are perpendicular
Sub t into AP
Find |AP|
Point on a line such that the distance to a point is the shortest
Let point A equal the point, point P equal a point on the line
Distance from A to P is AP, find AP=P-A
Solve AP·d =0 to find t where they are perpendicular
Sub t into P
Intersection of 2 lines
equate i,j,k to find the parameter(s) - check with all equations. Sub back into equation to find value