Lecture 8: Sex Linkage

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22 Terms

1
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Describe the various mechanisms in which organisms determine sex.

  • In some organisms, like humans, sex is determined by the X and Y sex chromosomes

    • Females are XX

    • Males are XY

  • In other organisms, like birds, butterflies, and some reptiles, sex is determined by the X and Z chromosomes

    • Females are ZW

    • Males are ZZ

  • In some organisms, such as turtles and alligators, sex is determined by the temperature at which eggs are incubated

The X and Y sex chromosomes pair during meiosis and segregate, but are not homologous — most genes on the X chromosome differ from genes on the Y chromosome, and this difference in the number of sex-linked alleles produces distinct patterns of inheritance in males and females.

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Thomas Hunt Morgan’s fruit fly experiments

Morgan was breeding fruit flies when he noticed an interesting phenotype: some fruit flies had white instead of red eyes

Question: What is the genetic basis of the white-eyed phenotype?

  • Bred a white-eyed fly (ww) and a red-eyed (W+W+) fly

  • F1 generation (W+w) all had red eyes

    • Pattern of inheritance seemed to be Mendelian

    • Morgan expected a 3:1 ratio in F2 offspring

  • But instead, Morgan found that 100% of females were red-eyed, 50% of males were red-eyed, and 50% of males were white-eyed

Conclusion: The white-eyed phenotype in fruit flies was not transmitted through Mendelian patterns of inheritance.

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Fruit fly eye color is sex-linked, with red eyes being dominant and white eyes being recessive. If a heterozygous red-eyed female is crossed with a red-eyed male, what are the expected phenotypic ratios in the offspring?

Red-eyed female: XW+ Xw

Red-eyed male: XW+ Y

Punnett square ratios:

  • XW+ XW+ (red-eyed female)

  • XW+ Xw (red-eyed heterozygous female)

  • XW+ Y (red-eyed male)

  • Xw Y (white-eyed male)

Expected results: 100% red-eyed females, 50% red-eyed males, 50% white-eyed males

<p>Red-eyed female: XW+ Xw</p><p>Red-eyed male: XW+ Y</p><p></p><p>Punnett square ratios: </p><ul><li><p>XW+ XW+ (red-eyed female)</p></li><li><p>XW+ Xw (red-eyed heterozygous female)</p></li><li><p>XW+ Y (red-eyed male)</p></li><li><p>Xw Y (white-eyed male)</p></li></ul><p></p><p>Expected results: 100% red-eyed females, 50% red-eyed males, 50% white-eyed males</p>
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Describe the significance of Morgan’s experiments.

  • Morgan’s work showed that the gene for eye color in fruit flies was located on the X chromosome only, and that no homologous allele is present on the Y chromosome → proved that genes are inherited on chromosomes, supporting the chromosome theory of inheritance

  • Female organisms have cells with two X chromosomes (XX) — females can be homozygous or heterozygous for the eye-color allele

  • Male organisms have cells with one X and one Y chromosome (XY) — males cannot be homozygous or heterozygous because they only have 1 copy of the X chromosome

    • Males are hemizygous (only having one copy of a gene or  chromosome) for X-linked loci

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X chromosome

Contains genetic information essential for both males and females — at least one copy of this chromosome is required for proper cell functioning

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Sex-determining region Y (SRY)

Also known as the male-determining gene; located on the Y chromosome

  • A single Y, even in the presence of several Xs, still produces a biological male phenotype

  • The absence of Y results in a biological female phenotype

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XX with an insertion of the SRY gene on an X chromosome will result in…

A biological male phenotype

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XO with an insertion of the SRY gene on an autosomal chromosome will result in…

A biological male phenotype

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Karyotyping

A technique to visualize chromosomes — actively dividing cells are halted in metaphase by treatment with a mitotic spindle inhibitor, and chromosomes are arranged according to size

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Turner syndrome

XO → biological female phenotype

Memorization trick: turner = “turn her" (biological female sex, two syllables)

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Klinefelter syndrome

XXY, XXXY, XXXXY, XXYY → biological male phenotype

Memorization trick: Kline “felt her” (many Xs but biological male sex)

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Poly-X females

XXX, XXXX, or more → biological female phenotype

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Pseudoautosomal regions

  • The only regions where the X and Y chromosomes are homologous

  • Located at both tips of the X and Y chromosomes

  • Essential for X-Y chromosome pairing in meiosis in males

<ul><li><p>The only regions where the X and Y chromosomes are homologous</p></li><li><p>Located at both tips of the X and Y chromosomes</p></li><li><p>Essential for X-Y chromosome pairing in meiosis in males</p></li></ul><p></p>
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Define aneuploidy and explain how aneuploidy can occur because of errors in meiosis I, meiosis II, and mitosis.

A change in the number of individual chromosomes

<p>A change in the number of individual chromosomes</p>
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Polyploidy

An increase in the number of sets of chromosome

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Describe the types of aneuploidy.

Nullisomy: loss of both members of a homologous chromosome pair (2n-2)
Tetrasomy: gain of a homologous chromosome pair (2n+2)

Monosomy: loss of a single chromosome (2n-1)
Trisomy: gain of a single chromosome (2n+1)

<p>Nullisomy: loss of both members of a homologous chromosome pair (2n-2)<br>Tetrasomy: gain of a homologous chromosome pair (2n+2)</p><p>Monosomy: loss of a single chromosome (2n-1)<br>Trisomy: gain of a single chromosome (2n+1)</p>
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Explain the problem of XX-XY gene dosage.

In females, there are two copies of the X chromosome and two copies of each autosome, so the genes on the X chromosome and autosomes are in balance

In males, there is only one copy of the X chromosome and two copies of every autosome, so males are likely to produce lower amounts of proteins encoded by X-linked genes than of proteins encoded by autosomal gene

  • Some organisms have evolved mechanisms to overcome this problem and equalize the amounts of protein produced by the single X chromosome and two autosomes

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Dosage compensation

Mechanisms to equalize the different amounts of protein produced by the single X chromosome and two autosomes in males

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X-inactivation in females

An important mechanism to normalize X gene dosage between females (XX) and males (XY)

  • Within each female cell, one of the two X chromosomes is randomly inactivated

  • The inactivated X chromosome condenses into a Barr body

Because of X-inactivation, females are hemizygous at the cellular level for X-linked genes

  • In females that are heterozygous at an X-linked locus, 50% of the cells express one allele and 50% express the other allele — proteins encoded by both alleles are produced, but not within the same cell

  • The cells in an individual female are not identical with respect to expression of the genes on the X chromosome

  • Females are mosaics for the expression of X-linked genes!

<p>An important mechanism to normalize X gene dosage between females (XX) and males (XY)</p><ul><li><p>Within each female cell, one of the two X chromosomes is randomly inactivated</p></li><li><p>The inactivated X chromosome condenses into a<strong> <mark data-color="yellow" style="background-color: yellow; color: inherit;">Barr body</mark></strong></p></li></ul><p></p><p>Because of X-inactivation, females are hemizygous at the cellular level for X-linked genes</p><ul><li><p>In females that are heterozygous at an X-linked locus, 50% of the cells express one allele and 50% express the other allele — proteins encoded by both alleles are produced, but <u>not within the same cell</u></p></li><li><p>The cells in an individual female are <strong>not identical</strong> with respect to expression of the genes on the X chromosome</p></li><li><p>Females are mosaics for the expression of X-linked genes!</p></li></ul><p></p>
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Random X-inactivation

  • Occurs early in development

  • After an X chromosome has become inactivated in a cell, it remains inactive in that cell and in all somatic cells that descend from that cell

  • Neighboring cells tend to have the same X chromosome inactivated, producing a patchy mosaic pattern in heterozygous females (ex. calico cats)

<ul><li><p>Occurs early in development</p></li><li><p>After an X chromosome has become inactivated in a cell, it remains inactive in that cell and in all somatic cells that descend from that cell</p></li><li><p>Neighboring cells tend to have the same X chromosome inactivated, producing a <strong>patchy mosaic pattern</strong> in heterozygous females (ex. calico cats)</p></li></ul><p></p>
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Describe the three reasons for non-random X-inactivation.

  1. Random chance

  2. Genetic bias — found in females heterozygous for a disease

  • Example: Buildup of uric acid in Lesch-Nyhan syndrome due to mutations in the X-linked HPRT1 gene

    • Females heterozygous for this disease experience less severe effects due to cell sharing of the HPRT1 enzyme across gap junctions 

    • Wild-type cells that express the HPRT1 enzyme are able to share the enzyme with mutant cells lacking it

    • This is an example of non-random X-inactivation due to genetic bias, where cells are more likely to inactivate the mutated X chromosome to facilitate sharing of the enzyme

  1. Cellular selection — due to a growth advantage or disadvantage

  • Example 1: Loss-of-function mutation in TORC1

    • TORC1 is a protein complex that is part of the G1 cell cycle checkpoint, responsible for sensing nutrient availability

    • If nutrients are limited, TORC1 will arrest the cell cycle in G1

    • If there is a mutation in TORC1 so that TORC1 is unable to sense nutrient availability, cells with the mutation will divide without adequate nutrients and die

    • If the mutated TORC1 is on the Xm chromosome, those cells will have a higher chance of dying, so there will be non-random X-inactivation where cells that inactivate the mutated Xm chromosome have a survival advantage over cells that inactivate the normal Xp chromosome

  • Example 2: Gain-of-function mutation in TORC1

    • A gain-of-function mutation in TORC1 will stimulate the cell cycle and result in increased rates of cell division for cells containing the mutated Xm chromosome — therefore, there will be non-random X-inactivation because cells containing the mutated Xm chromosome will outcompete cells containing the normal Xp chromosome

<ol><li><p><strong>Random chance<br></strong></p></li><li><p><strong>Genetic bias</strong>&nbsp;— found in females heterozygous for a disease</p></li></ol><ul><li><p>Example: Buildup of uric acid in Lesch-Nyhan syndrome due to mutations in the X-linked HPRT1 gene</p><ul><li><p>Females heterozygous for this disease experience less severe effects due to cell sharing of the HPRT1 enzyme across gap junctions&nbsp;</p></li><li><p>Wild-type cells that express the HPRT1 enzyme are able to share the enzyme with mutant cells lacking it</p></li><li><p>This is an example of non-random X-inactivation due to genetic bias, where cells are more likely to inactivate the mutated X chromosome to facilitate sharing of the enzyme</p></li></ul></li></ul><img src="https://knowt-user-attachments.s3.amazonaws.com/15b8501e-cef1-46ad-8d9f-b2c702ef251c.png" data-width="100%" data-align="center" alt=""><p></p><ol start="3"><li><p><strong>Cellular selection </strong>— due to a <u>growth advantage or disadvantage</u></p></li></ol><ul><li><p>Example 1: Loss-of-function mutation in TORC1</p><ul><li><p>TORC1 is a protein complex that is part of the G1 cell cycle checkpoint, responsible for sensing nutrient availability</p></li><li><p>If nutrients are limited, TORC1 will arrest the cell cycle in G1</p></li><li><p>If there is a mutation in TORC1 so that TORC1 is unable to sense nutrient availability, cells with the mutation will divide without adequate nutrients and die</p></li><li><p>If the mutated TORC1 is on the Xm chromosome, those cells will have a higher chance of dying, so there will be <u>non-random X-inactivation where cells that inactivate the mutated Xm chromosome have a survival advantage over cells that inactivate the normal Xp chromosome</u></p></li></ul></li></ul><img src="https://knowt-user-attachments.s3.amazonaws.com/e26f23e4-51d1-4a45-9350-80563d6ff02f.png" data-width="100%" data-align="center" alt=""><p></p><ul><li><p>Example 2: Gain-of-function mutation in TORC1</p><ul><li><p>A gain-of-function mutation in TORC1 will stimulate the cell cycle and result in increased rates of cell division for cells containing the mutated Xm chromosome — therefore, <u>there will be non-random X-inactivation because cells containing the mutated Xm chromosome will outcompete cells containing the normal Xp chromosome</u></p></li></ul></li></ul><img src="https://knowt-user-attachments.s3.amazonaws.com/e2b3be09-d00d-4ef6-968e-890560cf77a4.png" data-width="100%" data-align="center" alt=""><p></p>
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Explain the significance of biological females being genetic mosaics.

  • Females almost always have less severe manifestations of X-linked diseases, because heterozygous females are not homozygous for the pathogenic variant and contain both affected and unaffected cells

    • Variant cells expressing the deleterious allele receive sufficient levels of protein from cells expressing the normal allele to carry out essential metabolic functions → a way for females to ameliorate the effects of pathogenic variants