Genotype Frequencies flashcards 9-10

0.0(0)
studied byStudied by 0 people
GameKnowt Play
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/7

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

8 Terms

1
New cards

Homozygous Dominant

A genotype with two identical dominant alleles, typically written as AA.

2
New cards

Heterozygous

A genotype with one dominant and one recessive allele, written as Aa.

3
New cards

Homozygous Recessive

A genotype with two identical recessive alleles, written as aa.

4
New cards

Genotype Frequencies

The proportion of each genotype (AA, Aa, aa) in a population. They must sum to 1: f(AA) + f(Aa) + f(aa) = 1.

5
New cards

Allele Frequencies (p and q)

The relative proportion of specific alleles (e.g., A as p, a as q) in a population. p + q = 1. Derived from genotype frequencies as p = f(AA) + \frac{1}{2} f(Aa) and q = f(aa) + \frac{1}{2} f(Aa).

6
New cards

Hardy
Weinberg Equilibrium

A theoretical state where genotype frequencies in a population remain constant across generations because specific conditions are met (large population, random mating, no evolutionary forces). Under HW equilibrium, frequencies are f(AA) = p^2, f(Aa) = 2pq, and f(aa) = q^2.

7
New cards

Calculating Genotype Frequencies (Direct Counting)

To calculate genotype frequencies by directly counting the number of individuals with each genotype (x for AA, y for Aa, z for aa) in a sample of n individuals: f(AA) = \frac{x}{n}, f(Aa) = \frac{y}{n}, f(aa) = \frac{z}{n}.

8
New cards

Relationship between Allele and Genotype Frequencies

Allele frequency p is the frequency of the homozygous dominant genotype plus half the frequency of the heterozygous genotype (p = f(AA) + \frac{1}{2} f(Aa)). Similarly, q = f(aa) + \frac{1}{2} f(Aa).