Semiconductors Physics & Devices

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215 Terms

1
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What are the three classifications of materials based on conductivity?

Conductors, semiconductors, and insulators.

2
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How many valence electrons do conductors usually have?

Three or fewer.

3
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How many valence electrons do semiconductors have?

Four.

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How many valence electrons do insulators have?

Five or more.

5
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What are examples of conductors?

Silver, copper, gold, aluminum.

6
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What are examples of insulators?

Glass, plastic, rubber, mica.

7
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What are examples of semiconductors?

Silicon, germanium, and carbon.

8
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What is valence?

The combining ability of an atom determined by outer electrons.

9
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What is covalent bonding?

Sharing of valence electrons between atoms forming a crystal lattice.

10
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What is ionization?

The process by which atoms gain or lose electrons, forming ions.

11
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What is doping?

Adding impurities to a semiconductor to increase conductivity.

12
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What are intrinsic semiconductors?

Pure semiconductors with very low impurity levels.

13
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What are extrinsic semiconductors?

Doped semiconductors with increased conductivity.

14
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What are the two types of extrinsic semiconductors?

N-type and P-type.

15
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What impurity produces an N-type semiconductor?

Pentavalent impurity (5 valence electrons) like phosphorus or arsenic.

16
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What impurity produces a P-type semiconductor?

Trivalent impurity (3 valence electrons) like boron or gallium.

17
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What are free electrons?

Electrons that have gained enough energy to move freely through the lattice.

18
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What is a hole?

A missing electron in the valence band that acts as a positive charge carrier.

19
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What is a PN junction?

The boundary formed when P-type and N-type materials are joined together.

20
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What is the depletion region?

An area near the PN junction depleted of free charge carriers.

21
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What causes the depletion region to form?

Diffusion of electrons and holes creating fixed ions on each side.

22
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What is barrier potential (VB)?

The potential difference across a PN junction that opposes further carrier diffusion; ≈0.7 V (Si), 0.3 V (Ge).

23
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What does forward bias do to a diode?

Reduces the barrier potential and allows current flow.

24
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What does reverse bias do to a diode?

Widens the depletion region and blocks current flow.

25
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What is leakage current?

A small reverse current due to minority carriers, increasing with temperature.

26
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What is breakdown voltage (VBR)?

The reverse voltage at which the diode conducts heavily and may enter avalanche.

27
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What is avalanche breakdown?

A chain reaction where high-speed electrons knock other electrons free, causing heavy current.

28
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What is the first diode approximation?

Forward-biased diode = short circuit, reverse-biased = open circuit.

29
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What is the second diode approximation?

Forward-biased diode has 0.7 V drop (Si) or 0.3 V (Ge).

30
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What is the third diode approximation?

Includes the bulk resistance (rB) of the diode.

31
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How do you calculate a diode’s DC resistance?

RF = VF / IF.

32
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Example: If a silicon diode has VF = 0.7 V and IF = 2 mA, find RF.

RF = 0.7 V / 0.002 A = 350 Ω.

33
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How do you calculate bulk resistance of a diode?

rB = ΔV / ΔI.

34
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Example: A diode’s voltage changes by 0.1 V when current changes by 100 mA. Find rB.

rB = 0.1 V / 0.1 A = 1 Ω.

35
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What is an LED?

A Light-Emitting Diode that emits light when forward biased.

36
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What determines LED color?

The semiconductor material and dopant used.

37
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What is the typical forward voltage for LEDs?

Between 1.5 V and 2.5 V.

38
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What is the typical forward voltage assumption for calculations?

2.0 V.

39
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What is LED breakdown voltage range?

Between 3 V and 15 V (very low).

40
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Why must LEDs be protected from reverse voltage?

They can be destroyed by small reverse voltages.

41
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How do you protect an LED from reverse bias?

Connect a regular diode in parallel (reverse-parallel protection).

42
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Example: Calculate LED current if RS = 470 Ω, VS = 5 V, VLED = 2 V.

I = (5 – 2)/470 = 6.38 mA.

43
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Example: Determine RS for a 25 mA LED at 5 V supply, VLED = 2 V.

RS = (5 – 2)/0.025 = 120 Ω.

44
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What is a Zener diode?

A diode designed to operate in reverse breakdown for voltage regulation.

45
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What is zener voltage (VZ)?

The constant voltage maintained across the diode in breakdown.

46
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What is zener current (IZ)?

The reverse current through the zener during regulation.

47
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What is zener power dissipation formula?

PZ = VZ × IZ.

48
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What is maximum zener current formula?

IZM = PZM / VZ.

49
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Example: Calculate IZM for a 1 W, 10 V zener diode.

IZM = 1 W / 10 V = 0.1 A (100 mA).

50
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Example: In a 6.2 V zener regulator with 12 V supply and 470 Ω resistor, find IZ.

IZ = (12 – 6.2)/470 = 12.34 mA.

51
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What is a loaded zener regulator?

A voltage regulator where a load resistor is connected in parallel with the zener.

52
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If RL = 200 Ω, VZ = 6.2 V, find IL.

IL = 6.2/200 = 31 mA.

53
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54
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What is a transistor?

A semiconductor device with three regions used for amplification or switching.

55
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What are the three regions of a BJT?

Emitter, base, and collector.

56
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What is the main function of the emitter?

To inject charge carriers into the base.

57
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What is the function of the base?

To control the number of carriers flowing from emitter to collector.

58
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What is the function of the collector?

To collect charge carriers and dissipate heat.

59
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How is the emitter doped?

Heavily doped.

60
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How is the base doped?

Lightly doped and very thin.

61
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How is the collector doped?

Moderately doped and largest in size.

62
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What are the two types of BJTs?

NPN and PNP transistors.

63
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What are the majority carriers in an NPN transistor?

Electrons.

64
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What are the majority carriers in a PNP transistor?

Holes.

65
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What is the arrow direction on the emitter in an NPN transistor symbol?

Points outward.

66
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What is the arrow direction on the emitter in a PNP transistor symbol?

Points inward.

67
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How is an NPN transistor biased for operation?

Base-emitter junction forward biased, collector-base junction reverse biased.

68
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What happens if both junctions are reverse biased?

Transistor is in cutoff region (OFF).

69
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What happens if both junctions are forward biased?

Transistor is in saturation region (ON).

70
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What happens when base-emitter is forward biased and collector-base is reverse biased?

Transistor operates in the active region (amplification).

71
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What is the relationship between transistor currents?

IE = IB + IC.

72
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Define αdc.

Ratio of collector current to emitter current in a common-base connection (αdc = IC / IE).

73
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Define βdc.

Ratio of collector current to base current in a common-emitter connection (βdc = IC / IB).

74
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How are αdc and βdc related?

βdc = αdc / (1 – αdc) and αdc = βdc / (βdc + 1).

75
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Example: If αdc = 0.99, find βdc.

βdc = 0.99 / (1 – 0.99) = 99.

76
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Example: If βdc = 150, find αdc.

αdc = 150 / (150 + 1) ≈ 0.993.

77
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Example: Given IB = 20 µA and βdc = 100, find IC.

IC = βdc × IB = 100 × 20 µA = 2 mA.

78
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Example: Given IC = 4.98 A and IB = 20 mA, find IE.

IE = IC + IB = 4.98 + 0.02 = 5.00 A.

79
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Example: Given IE = 50 mA and IC = 49 mA, find IB.

IB = IE – IC = 50 – 49 = 1 mA.

80
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What is the cutoff region in a transistor?

When IB = 0, and IC ≈ 0 (transistor is OFF).

81
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What is the active region?

Where IC = βdc × IB; transistor acts as an amplifier.

82
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What is the saturation region?

When increasing IB no longer increases IC (transistor fully ON).

83
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What is a common-base connection?

Base is common to input and output; used for voltage amplification.

84
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What is a common-emitter connection?

Emitter is common; provides both current and voltage gain.

85
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What is a common-collector connection?

Collector is common; used for impedance matching (emitter follower).

86
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How is base bias provided?

By applying a fixed voltage (VBB) through a base resistor RB.

87
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Formula for base current IB in base bias circuit?

IB = (VBB – VBE) / RB.

88
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Formula for collector current IC in base bias?

IC = βdc × IB.

89
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Formula for collector-emitter voltage VCE?

VCE = VCC – IC × RC.

90
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Example: VCC = 12V, RB = 470kΩ, β = 100, RC = 4.7kΩ, VBE = 0.7V. Find IB.

IB = (12 – 0.7)/470k = 0.024 mA (24 µA).

91
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Example: Find IC and VCE.

IC = 24 µA × 100 = 2.4 mA; VCE = 12 – (2.4 mA × 4.7kΩ) = 0.72 V.

92
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What is the advantage of voltage-divider bias?

It provides stable operating point despite transistor β variations.

93
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Formula for VB in voltage divider bias?

VB = (R2 / (R1 + R2)) × VCC.

94
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Formula for VE in voltage divider bias?

VE = VB – VBE.

95
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Formula for IC in voltage divider bias?

IC ≈ VE / RE (assuming IE ≈ IC).

96
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Example: VCC = 12V, R1 = 47kΩ, R2 = 10kΩ, RE = 1kΩ, VBE = 0.7V. Find VB, VE, IC.

VB = 12×(10/(47+10))=2.11V; VE=2.11–0.7=1.41V; IC≈1.41mA.

97
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What is emitter bias?

A bias method using both +VCC and –VEE supplies for stability.

98
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Formula for emitter current in emitter bias?

IE = (VEE – VBE) / (RE + (RB / (β + 1))).

99
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What are the advantages of emitter bias?

Extremely stable Q-point and temperature independence.

100
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What are transistor operating regions?

Cutoff, Active, Saturation, and Breakdown regions.

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