SPH3U1 - Physics Unit 1

studied byStudied by 8 people
0.0(0)
learn
LearnA personalized and smart learning plan
exam
Practice TestTake a test on your terms and definitions
spaced repetition
Spaced RepetitionScientifically backed study method
heart puzzle
Matching GameHow quick can you match all your cards?
flashcards
FlashcardsStudy terms and definitions

1 / 43

encourage image

There's no tags or description

Looks like no one added any tags here yet for you.

44 Terms

1

Kinesmatics

The study of motion/how objects move

New cards
2

Scaler Quantities

A quantity that has only magnitude (size)

Ex: Distance

New cards
3

Vector Quantities

A quantity that has both magnitude and direction

Ex: Velocity - Measures speed and direction

New cards
4

Reference point

A place or object used for comparison to determine if something is in motion

New cards
5

Position

The distance and direction of an object from the reference point

New cards
6

Displacemnet

Change in position of an object

Formula:

New cards
7

Total displacement if an object moves more than once

Formula:

New cards
8

Vector Scale Diagram

Vectors associated with total displacements drawn to a proportionate scale.

Ex:

New cards
9

Directed line Segment

A straight line between 2 points with a specific direction

New cards
10

Difference between speed and velocity

Speed - Deals with how fast an object moves

Velocity - Deals with how fast and what direction an object moves

New cards
11

Average Speed

Vav = Avg Speed

Δd = Total distance

Δt = Total time

New cards
12

Average Velocity

Vav = Avg Velocity

Δd = Total distance + direction

Δt = Total Time

New cards
13

Motion with uniform/constant velocity

Object travels in a straight line with a constant velocity

New cards
14

Motion with non-uniform/constant velocity

Motion in which the object’s speed changes or the object does not travel in a straight line

Ex: Traveling at a constant velocity, but in multiple directions

New cards
15

What is acceleration

Rate of change of velocity (m/s²)

New cards
16

Position-Time Graph: Horizontal Line ABOVE X-Axis

  • No velocity - object at rest 

  • Slope = 0

  • Stationed east of the reference point

<ul><li><p><span>No velocity - object</span><strong><span> at rest&nbsp;</span></strong></p></li><li><p><span>Slope = 0</span></p></li><li><p><span>Stationed </span><strong><span>east </span></strong><span>of the reference point</span></p></li></ul>
New cards
17

Velocity and Acceleration Time Graphs if position-time graph is a horizontal line ABOVE x-axis

knowt flashcard image
New cards
18

Position-Time Graph: Horizontal Line BELOW X-Axis

  • No velocity - object at rest

  • Slope = 0

  • Stationed WEST of reference point

<ul><li><p><span>No velocity - object </span><strong><span>at rest</span></strong></p></li><li><p><span>Slope = 0</span></p></li><li><p><span>Stationed </span><strong><span>WEST of reference point</span></strong></p></li></ul>
New cards
19

Velocity and Acceleration Time Graphs if position-time graph is a horizontal line BELOW x-axis

knowt flashcard image
New cards
20

Position-Time Graph: Gradual Positive Slope

  • Straight Line =  Constant Velocity

  • Positive Slope = Displacement in y-axis indicator

  • Y-axis title indicates direction

<ul><li><p><span>Straight Line =&nbsp; </span><strong><span>Constant Velocity</span></strong></p></li><li><p><strong><span>Positive Slope = Displacement in y-axis indicator</span></strong></p></li><li><p><span>Y-axis title indicates direction</span></p></li></ul>
New cards
21

Velocity and Acceleration Time Graphs if position-time graph is a gradual positive slope

knowt flashcard image
New cards
22

Position-Time Graph: Steep Positive Slope

  • Straight Line =  Constant Velocity

  • Positive Slope = Displacement in y-axis indicator

  • Y-axis title indicates direction

<ul><li><p><span>Straight Line =&nbsp; </span><strong><span>Constant Velocity</span></strong></p></li><li><p><strong><span>Positive Slope = Displacement in y-axis indicator</span></strong></p></li><li><p><span>Y-axis title indicates direction</span></p></li></ul>
New cards
23

Velocity and Acceleration Time Graphs if position-time graph is a STEEP positive slope

knowt flashcard image
New cards
24

Position-Time Graph: Negative Slope

  • Straight line = Constant Velocity

  • Negative Slope = Displacement in a negative Eastward direction until it passes the reference point.

  • If slope passes the x-axis or reference point object starts moving in the opposite direction

<ul><li><p><span>Straight line = Constant Velocity</span></p></li><li><p><strong><span>Negative Slope = Displacement in a negative Eastward direction until it passes the reference point.</span></strong></p></li><li><p><span>If slope passes the x-axis or reference point object starts moving in the opposite direction</span></p></li></ul>
New cards
25

Velocity and Acceleration Time Graphs if position-time graph is a negative slope

knowt flashcard image
New cards
26

Position-Time Graph: Positive Parabola ABOVE the horizontal line

  • Object speeding up EASTWARD

  • Upward parabola above X-Axis = Object speeding up

<ul><li><p><span>Object speeding up </span><strong><span>EASTWARD</span></strong></p></li><li><p><span>Upward parabola above X-Axis = Object speeding up</span></p></li></ul>
New cards
27

Velocity and Acceleration Time Graphs if position-time graph is a Positive Parabola ABOVE the horizontal line

knowt flashcard image
New cards
28

Position-Time Graph: Positive Parabola BELOW the horizontal line

  • Object slowing down WESTWARD

  • Negative velocity

<ul><li><p><span>Object slowing down </span><strong><span>WESTWARD</span></strong></p></li><li><p><span>Negative velocity</span></p></li></ul>
New cards
29

Velocity and Acceleration Time Graphs if position-time graph is a Positive Parabola BELOW the horizontal line

knowt flashcard image
New cards
30

Position-Time Graph: Negative Parabola ABOVE the horizontal line

Object slowing down EASTWARD

<p><span>Object slowing down </span><strong><span>EASTWARD</span></strong></p>
New cards
31

Velocity and Acceleration Time Graphs if position-time graph is a Negative Parabola ABOVE the horizontal line

knowt flashcard image
New cards
32

Position-Time Graph: Negative Parabola BELOW the horizontal line

Object speeding up WESTWARD - moving in a negative direction

<p><span>Object speeding up </span><strong><span>WESTWARD </span></strong><span>- moving in a negative direction</span></p>
New cards
33

Velocity and Acceleration Time Graphs if position-time graph is a Negative Parabola BELOW the horizontal line

knowt flashcard image
New cards
34

How to go from time graph to time graph

Position —> Velocity —> Acceleration

  • Find the SLOPE

Acceleration —> Velocity —> Position

  • Find the AREA

<p>Position —&gt; Velocity —&gt; Acceleration</p><ul><li><p>Find the <strong>SLOPE</strong></p></li></ul><p>Acceleration —&gt; Velocity —&gt; Position</p><ul><li><p>Find the <strong>AREA</strong></p></li></ul>
New cards
35

Instantaneous Velocity

Velocity at a specific interval of time

  • Ex: A car is moving for 10 seconds, and you must find the instantaneous velocity from 6-7 seconds

New cards
36

Equation 1

Variables Found: Δd, Δt, Vf, VI

Variables Not Found: aav

<p><strong>Variables Found:</strong><span> Δd, Δt, V<sub>f</sub>, V<sub>I</sub></span></p><p><strong><span>Variables Not Found: </span></strong><span>a<sub>av</sub></span></p>
New cards
37

Equation 2

Variables Found: Δt, Vf, VI, aav

Variables Not Found: Δd

<p><strong>Variables Found:</strong>  Δt, V<sub>f</sub>, V<sub>I</sub>, a<sub>av</sub></p><p><strong>Variables Not Found: </strong>Δd</p>
New cards
38

Equation 3

Variables Found: Δd, Δt, VI, aav

Variables Not Found: Vf

  • When trying to find Δt it can be tricky if initial velocity is not 0 

  • However, using quadratic equations (ax2+bx+c) it can be solved by rearranging the formula and using the quadratic formula to find the roots.

<p><strong>Variables Found:</strong> Δd, Δt, V<sub>I</sub>, a<sub>av</sub></p><p><strong>Variables Not Found: </strong>V<sub>f</sub></p><ul><li><p><span>When trying to find Δt it can be tricky if initial velocity is not 0&nbsp;</span></p></li><li><p><span>However, using quadratic equations (ax<sup>2</sup>+bx+c) it can be solved by rearranging the formula and using the quadratic formula to find the roots.</span></p></li></ul>
New cards
39

Equation 4

Variables Found: Δd, Vf, VI, aav

Variables Not Found: Δt

New cards
40

Equation 5

Variables Found: Δd, Δt, Vf, aav

Variables Not Found: VI

<p><strong>Variables Found:</strong> Δd, Δt, V<sub>f</sub>, a<sub>av</sub></p><p><strong>Variables Not Found: </strong>V<sub>I</sub></p>
New cards
41

What is the value of g

g = 9.8m/s²

New cards
42

Object’s acceleration if moving up or down

  • If the object is moving down, the g = -9.8m/s2

  • If the object is moving up, the g = 9.8m/s2

New cards
43

Positive and Negative Convention

  • If the object is moving left and down then it is going to be NEGATIVE (-)

  • If the object is moving right or up then it is going to be POSITIVE (+)

New cards
44

Steps in solving problems involving gravitational pull:

Question: A flowerpot is knocked off a window ledge and accelerates uniformly to the ground. If the window ledge is 10.0 m above the ground and there is no air resistance, how long does it take the flowerpot to reach the ground?

  • Using equation 3: find the variables that have been given

    • In this case:

    • Required: Time

  • Rearrange the formula to isolate the variable →

    • ViΔt is canceled out due to initial velocity being 0

  • Lastly, plug in the numbers

New cards
robot