Preparation of Amines

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14 Terms

1
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What are the two main methods for preparing amines?

  1. Nucleophilic substitution of halogenoalkanes with ammonia.

  2. Reduction of nitriles.

2
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What type of amine is produced from the reaction of a halogenoalkane with ammonia?

  • A primary amine.

3
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What is a major disadvantage of preparing amines by nucleophilic substitution?

  • It produces a mixture of primary, secondary, and tertiary amines unless a large excess of ammonia is used.

4
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Why is excess ammonia used in the nucleophilic substitution method?

  • To prevent further substitution of the primary amine product into secondary and tertiary amines.

5
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What type of amine is produced from the reduction of a nitrile?

  • A primary amine.

6
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What is the key advantage of preparing an amine via a nitrile?

  • It produces a pure primary amine without the mixture of products.

<ul><li><p><span>It produces a </span><strong>pure primary amine</strong><span> without the mixture of products.</span></p></li></ul><p></p>
7
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Name two different reagents that can be used to reduce a nitrile to an amine

  1. LiAlH₄ in dry ether and dilute HCl

  2. H₂ with a Ni catalyst

<ol><li><p class="ds-markdown-paragraph"><strong>LiAlH₄</strong> in dry ether and dilute HCl</p></li><li><p class="ds-markdown-paragraph"><strong>H₂</strong> with a Ni catalyst</p></li></ol><p></p>
8
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Write the general formulas for the reduction of a nitrile (R-CN) to a primary amine (R-CH₂-NH₂) using:
a) LiAlH₄
b) H₂ with a Ni catalyst

a) Using LiAlH₄:

  • Reagents: R-CN + LiAlH₄

  • Conditions: In dry ether, followed by dilute HCl acid work-up.

  • Equation:
    R-CN + 4[H] → R-CH₂-NH₂
    (The [H] comes from the LiAlH₄ + acid)

b) Using H₂ with Ni catalyst:

  • Reagents: R-CN + 2H₂

  • Conditions: High pressure of H₂ gas, Nickel catalyst.

  • Equation:
    R-CN + 2H₂ → R-CH₂-NH₂


<p><strong>a) Using LiAlH₄:</strong></p><ul><li><p class="ds-markdown-paragraph"><strong>Reagents:</strong> R-CN + LiAlH₄</p></li><li><p class="ds-markdown-paragraph"><strong>Conditions:</strong> In <strong>dry ether</strong>, followed by <strong>dilute HCl acid</strong> work-up.</p></li><li><p class="ds-markdown-paragraph"><strong>Equation:</strong><br><strong>R-CN + 4[H] → R-CH₂-NH₂</strong><br><em>(The [H] comes from the LiAlH₄ + acid)</em></p></li></ul><p class="ds-markdown-paragraph"><strong>b) Using H₂ with Ni catalyst:</strong></p><ul><li><p class="ds-markdown-paragraph"><strong>Reagents:</strong> R-CN + 2H₂</p></li><li><p class="ds-markdown-paragraph"><strong>Conditions:</strong> High pressure of <strong>H₂ gas</strong>, <strong>Nickel catalyst</strong>.</p></li><li><p class="ds-markdown-paragraph"><strong>Equation:</strong><br><strong>R-CN + 2H₂ → R-CH₂-NH₂</strong></p></li></ul><p><br></p>
9
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What is the name of the reaction and mechanism for adding a nitro group to benzene?

  • Nitration, via Electrophilic Substitution.

<ul><li><p><strong>Nitration</strong><span>, via </span><strong>Electrophilic Substitution</strong><span>.</span></p></li></ul><p></p>
10
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What are the reagents and temperature for the nitration of benzene?

  • Reagents: Concentrated HNO₃ and concentrated H₂SO₄.

  • Temperature: 50°C.

<ul><li><p class="ds-markdown-paragraph"><strong>Reagents:</strong> Concentrated <strong>HNO₃</strong> and concentrated <strong>H₂SO₄</strong>.</p></li><li><p class="ds-markdown-paragraph"><strong>Temperature:</strong> <strong>50°C</strong>.</p></li></ul><p></p>
11
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What is the organic product of benzene's nitration?

  • Nitrobenzene (C₆H₅NO₂).

<ul><li><p><strong>Nitrobenzene</strong><span> (C₆H₅NO₂).</span></p></li></ul><p></p>
12
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Why is the nitration reaction so important industrially?

  • Because the nitro group can be reduced to an amino group (-NH₂), forming phenylamine, which is a key starting material for many products.

<ul><li><p>Because the nitro group can be <strong>reduced to an amino group (-NH₂)</strong>, forming phenylamine, which is a key starting material for many products.</p></li></ul><p></p>
13
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How is nitrobenzene reduced to phenylamine? Give one set of reagents.

  • Reagents: Tin (Sn) and concentrated HCl (this produces an intermediate with the formula C6H5NH3+, followed by NaOH.

  • OR: H₂ gas with a Nickel catalyst.

  • Conditions: Under reflux, and steam distillation after NaOH to separate

<ul><li><p class="ds-markdown-paragraph"><strong>Reagents:</strong> <strong>Tin (Sn)</strong> and <strong>concentrated HCl  </strong>(this produces an intermediate with the formula C<sub>6</sub>H<sub>5</sub>NH3<sup>+</sup>, followed by <strong>NaOH</strong>.</p></li><li><p class="ds-markdown-paragraph"><strong>OR:</strong> <strong>H₂ gas</strong> with a <strong>Nickel catalyst</strong>.</p></li><li><p><strong>Conditions: Under reflux, and steam distillation after NaOH to separate</strong></p></li></ul><p></p>
14
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Write the overall balanced equation for the reduction of nitrobenzene to phenylamine (including the reagents Sn/HCl and NaOH).

C₆H₅NO₂ + 7[H] → C₆H₅NH₂ + 2H₂O
*(The [H] comes from: Sn + 2HCl → SnCl₂ + 2[H], and the NaOH neutralizes the acid)*