Unit 6 Stoichiometry

0.0(0)
studied byStudied by 0 people
0.0(0)
full-widthCall with Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/44

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No study sessions yet.

45 Terms

1
New cards

volume of gas

What does STP also mean?

2
New cards

moles —> STP

multiply by 22.4 L / 1 mol

3
New cards

STP —> moles

multiply by 1 mol / 22.4 L

4
New cards

moles —> mass

multiply by molar mass (g) / 1 mol

5
New cards

mass —> moles

multiply by 1 mol / molar mass (g)

6
New cards

moles —> number of particles

multiply by 6.023 × 1023 particles / 1 mol

7
New cards

number of particles —> moles

multiply by 1 mol / 6.023 × 1023 particles

8
New cards

percent composition

percent by mass of each element in a compound

9
New cards

% mass of element

(mass of element / mass of compound) * 100%

10
New cards

72.2% Mg, 27.8% N

A compound is formed when 9.03g Mg combined with 3.48g N. What is the percent composition of this compound?

tip: add two masses for total mass compound

11
New cards

82.22% N, 17.88% H

Calculate the percent composition of ammonia, NH3. Assume you have one mole, use the molar mass to solve the problem.

12
New cards

empirical formulas

smallest whole number ratio of different atoms in a chemical compound

Ex. C3H6O3 —> CH2O

13
New cards

molecular formula

actual number ratio of different atoms in a chemical reaction

Ex. C3H6O3

14
New cards

calculating empirical formula

  1. take percent comp

  2. multiply by 1 mol / molar mass (g)

  3. divide by smallest mole number

  4. multiply by constants for whole number constants

15
New cards

molecular formula from empirical formula

  1. molar mass / empirical formula mass

  2. multiply each subscript of empirical formula by number obtained in step 1

tip: find molar mass of entire compound for empirical formula; molar mass of molecule usually given

16
New cards

(s)

solid

17
New cards

(l)

liquid

18
New cards

(g)

gas

19
New cards

(aq)

in aqueous solution (dissolved in water)

20
New cards

diatomic elements

Br, I, N, Cl, H, O, F

21
New cards

rule for polyatomic ion in balancing equation

if unchanged on the other side of the equation, count as one unit

22
New cards

net ionic equation

equation containing only the elements that changed states of matter

23
New cards

Zn2+ (aq) + CO32- (aq) —> ZnCo3 (s)

net ionic equation of Zn(NO3)2 (aq) + NaCO3 (aq) —> ZnCO3 (s) + 2NaNO3 (aq)

24
New cards

Zn (s) + Cu2+ (aq) —> Zn2+ (aq) + Cu (s)

net ionic equation of Zn (s) + Cu(NO3)2 (aq) —> Zn(NO3)2 (aq) + Cu(s)

25
New cards

Zn (s) + 2HCl (aq) —> ZnCl2 (aq) + H2 (g)

net ionic equation of Zn (s) + 2H+ (aq) —> Zn2+ (aq) + H2 (g)

26
New cards

synthesis reactions

also known as combination reactions; A + B —> AB

27
New cards

halide salt

reaction of metals with halogens (all pure, elemental halogens are diatomic: BrINClHOF)

28
New cards

decomposition reactions

opposite of synthesis reactions; AB —> A + B

29
New cards

rule of diatomic elements in decomposition reactions

decompose into respective elements diatomically

Ex. 2HgO (s) —> 2 Hg (l) + O2 (g)

30
New cards

rule for metal carbonate in decomposition reactions

metal carbonates plus heat decompose into metal oxides plus carbon dioxide

Ex. Ca3CO3 (g) —> CaO (s) + CO2 (g)

31
New cards

rule for carbonic acid decomposing

H2CO3 (aq) —> CO2 (g) + H2O (l)

32
New cards

rule for ammonium hydroxide decomposing

NH2OH (aq) —> NH2 (aq) + H2O (l)

33
New cards

single replacement reactions

usually occur in aqueous environments and A & B independently solid; A + BX —> AX + B

34
New cards

rule for determining reactions of halogens and single replacement reactions

determining if it can occur or not requires activity series of metals —> higher reactivity = kicks other element out and reacts

Ex. Cu (s) + 2AgNO3 (aq) —> 2Ag (s) + Cu(NO3)2 (aq)

35
New cards

double replacement reactions

occur in aqueous solutions w/ two ionic compounds; one product usually precipitate or liquid & gas; AX + BY —> AY + BX

36
New cards

basic solubility rules

all nitrates, acetates, and ammoniums soluble (with few exceptions)

37
New cards

rules for formation of a precipitate (DR)

occurs when positive ions of one reactant combine w/ negative ions of another reactant —> rosm insoluble / slightly soluble product

Ex. 2NaPO4 (aq) + 3CaCl2 (aq) —> Ca3(PO4)2 (s) + 6NaCl (aq)

38
New cards

rules for formation of a gas (DR)

occurs when one product is a gas that bubbles out of mixture

Ex. 2HCl (aq) + K2CO3 (aq) —> 2KCl (aq) + H2O (l) + CO2 (g)

39
New cards

neutralization reaction

acid + base —> water + salt

Ex. HCl (aq) + NaOH (aq) —> NaCl (aq) + H2O (l)

40
New cards

hydrocarbon combustion reactions

burning of hydrocarbon / alcohol in presence of oxygen

Ex. CH4 (g) + 2O2 —> CO2 (g) + 2H2O (l)

41
New cards

complete combusion

turns all carbon atoms into carbon dioxide and all hydrogen atoms into water; assume this is true unless told otherwise

42
New cards

common gases

CO2, CO, NH3, H2S, SO2, N2O, NO2, H2, N2, O2, F2, Cl2

43
New cards
44
New cards
45
New cards