5: magnetic resonance

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105 Terms

1
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describe types of atomic/molecular interaction at different areas of EM spectrum

radio = NMR

microwave = EPR

microwave = molecular rotation

IR = molecular vibration

UV/Vis = valence e- excitation

x-rays = core e- excitation

the type of EM radiation is dependent on the size of the energy gap of transition being probed

2
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describe NMR vs EPR

NMR = spectroscopy of nuclear spin states in a magnetic field

EPR = spectroscopy of electron spin states in a magnetic field

3
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describe magnetic vs electric dipoles

electric dipoles = arise from two equal and opposite electric charges separated by a small distance

magnetic dipole = arise from spinning charged particle generating an magnetic field

4
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describe NMR/EPR vs other types of spectroscopy

other = electric dipole moments interacting with electric component of EM radiation

NMR/EPR = magnetic dipole moment (electron/nucleus) interacting with magnetic component of EM radiation

5
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describe classical angular momentum

an object rotating around a point has angular momentum

= vector = magnitude and direction

two types

  • spin AM = mass spinning on axis

  • orbital AM = mass orbiting a central point

<p>an object rotating around a point has angular momentum</p><p><strong>= vector = magnitude and direction</strong></p><p>two types</p><ul><li><p>spin AM = mass spinning on axis</p></li><li><p>orbital AM = mass orbiting a central point</p></li></ul><p></p>
6
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describe the application of the rigid rotor model

to model angular momentum in rotating diatomic molecule

7
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describe the difference in angular momentum between molecules and elementary particles

molecules = acquire rotational angular momentum (by collisions)

elementary particles = intrinsic angular momentum (spin)

8
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what are charge and spin for the elementary particles

knowt flashcard image
9
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describe how to differentiate vectors and quantum numbers

vectors = bold

quantum numbers = italics

10
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describe nuclear spin

nuclear spin = intrinsic angular momentum = I

since it is angular momentum:

= vector = magnitude and direction

11
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what equation defines the magnitude of I? (given)

I = spin quantum number

hence, the magnitude of spin is constant for a given nuclei

only direction can be changed

<p><em>I </em>= spin quantum number </p><p>hence, the magnitude of spin is constant for a given nuclei </p><p>only direction can be changed</p>
12
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describe spin quantum number

unique to a given nuclei

= determined primarily by number of protons/neutrons

<p>unique to a given nuclei</p><p>= determined primarily by number of protons/neutrons </p>
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what nuclei are NMR active?

I > 0

= odd mass number

14
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describe Zeeman splitting

  • a nuclei with spin I is (2I + 1) degenerate due to m(I)

  • application of magnetic field breaks the degeneracy

  • gives rise to ‘Zeeman eigenstates’

<ul><li><p>a nuclei with spin <em>I </em>is (2<em>I </em>+ 1) degenerate due to m(I)</p></li><li><p>application of magnetic field breaks the degeneracy</p></li><li><p>gives rise to ‘Zeeman eigenstates’</p></li></ul><p></p>
15
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describe m(I)

m(I) = nuclear azimuthal/magnetic quantum number = describes orientation of nuclear spin (vector) in a magnetic field

= -I, -I+1, …, +I

16
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what equation defines the energy of the Zeeman eigenstates?

m(I) = controls number of Zeeman eigenstates
γ = gyromagnetic ratio = unique for a nucleus = controls extent of Zeeman splitting (size of E gap between eigenstates)

<p>m(I) = controls number of Zeeman eigenstates<strong><br></strong>γ = gyromagnetic ratio = unique for a nucleus = controls extent of Zeeman splitting (size of E gap between eigenstates) </p>
17
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<p>describe what varies the Zeeman eigenstates here</p>

describe what varies the Zeeman eigenstates here

(1)H and (13)C:

= same I = same m(I) = both split to 2 sublevels

= different γ = different energy gaps

(13)C and (23)Na:

= similar γ = similar energy gaps

= different I = different m(I) = split into different no. of sublevels

18
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what are the selection rules for a nuclei’s NMR activity?

  • I > 0 (odd mass number)

  • Δm(I) = ± 1

19
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describe the energy difference between allowed Zeeman eigenstates

(using m(I) = ½ as basis)

<p>(using m(I) = ½ as basis)</p>
20
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describe the Larmor frequency (conversion to v not given!!)

the frequency of the allowed transition between Zeeman eigenstates for a given nuclei

= frequency of transition between different orientations of nuclear spin (vector) in a magnetic field

(= frequency at which nuclear spins precess in a magnetic field)

= constant for a given nucleus

<p>the frequency of the allowed transition between Zeeman eigenstates for a given nuclei</p><p>= frequency of transition between different orientations of nuclear spin (vector) in a magnetic field</p><p>(= frequency at which nuclear spins precess in a magnetic field)</p><p>= <strong>constant for a given nucleus</strong></p>
21
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what units are B(0) in?

tesla (T)

22
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what does the value of the Larmor frequency of many common nuclei tell us?

= fall in radio part of EM spectrum

= radio used in NMR/EPR

23
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what is unit M (mega)?

10^6

24
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describe the relationship between spin and magnetism

= spinning charge (internal angular momentum), I, gives magnetic moment

= magnetic moment, μ, of a nucleus is proportional to spin angular momentum, I

gyromagnetic ratio = constant of proportionality

<p>= spinning charge (internal angular momentum), I, gives magnetic moment</p><p>= magnetic moment, <span>μ, of a nucleus is proportional to spin angular momentum, <strong>I</strong></span></p><p>gyromagnetic ratio = constant of proportionality </p>
25
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describe the possible values of gyromagnetic ratio

μ points in same direction as I = +ve γ

μ points in opposite direction of I = -ve γ

<p>μ points <strong>in same direction</strong> as <strong>I </strong>= +ve γ </p><p>μ points <strong>in opposite direction</strong> of <strong>I </strong>= -ve γ</p>
26
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describe a and B Zeeman eigenstates

alpha (a) = ‘up’ = +ve m(I)

beta (B) = ‘down’ = -ve m(I)

27
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describe the configuration of Zeeman eigenstate depending on values of gyromagnetic ratio

+ve γ = μ points in same direction as I

-ve m(I) (B) higher in energy (harder to flip)

-ve γ = μ points in opposite direction of I

+ve m(I) (a) higher in energy (harder to flip)

<p>+ve γ = μ points <strong>in same direction</strong> as <strong>I </strong></p><p>-ve m(I) (B) higher in energy (harder to flip)</p><p>-ve γ = μ points <strong>in opposite direction</strong> of <strong>I </strong></p><p>+ve m(I) (a) higher in energy (harder to flip)</p>
28
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describe the problem with the energy level approach

nuclei do not have to be in just one of these two states (up or down)

= mixture of wavefunctions associated with each energy level

i.e. coherent superposition/mixed state

29
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what is spin polarisation

alignment of nuclear spins in response to application of a magnetic field

30
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describe the direction of spin angular momentum vector, I, with magnetic moment vector, μ

+ve γ = μ parallel to I

-ve γ = μ anti-parallel to I

<p>+ve γ = μ parallel to <strong>I</strong></p><p>-ve γ = μ anti-parallel to <strong>I</strong></p>
31
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describe nuclei spins in absence of magnetic field

spin polarisation axes (spins, I) pointing in all possible direction

= no net magnetisation

32
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what happens when a magnetic field is appled?

the spin polarisation axes (spins, I) precess around the axis of magnetic field B(0)

<p>the spin polarisation axes (spins, <strong>I</strong>) precess around the axis of magnetic field B(0)</p>
33
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describe the frequency and angle of precession

frequency of precession = Larmor frequency

angle of precession = dependent on initial spin direction

<p>frequency of precession = Larmor frequency </p><p>angle of precession = dependent on initial spin direction </p>
34
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describe longitudinal relaxation

precession around axis of magnetic field = minimises energy of interaction between the spin magnetic moment and magnetic field = lower energy orientation

net magnetisation grows along z axis as spins come to equilibrium with magnetic field B(0)

= contributes to bulk magnetisation vector, M, which precesses around axis of magnetic field

<p>precession around axis of magnetic field = minimises energy of interaction between the spin magnetic moment and magnetic field = lower energy orientation</p><p>net magnetisation grows along z axis as spins come to equilibrium with magnetic field B(0)</p><p>= contributes to <strong>bulk magnetisation vector, M, which precesses around axis of magnetic field</strong></p>
35
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draw a graph representing longitudinal relaxation

knowt flashcard image
36
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describe signal:noise ratio

high signal:noise ratio desired

<p>high signal:noise ratio desired</p>
37
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describe population distributions between Zeeman eigenstates

remember ΔE = h|v(0)|

<p>remember<strong> </strong><span><strong>ΔE = h|v(0)|</strong></span></p>
38
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describe how population differences lead to bulk magnetisation vector

population differences between different Zeeman eigenstates = different m(I) values = different alignment to external magnetic field

n(upper) = excited state = anti aligned with B(0)

n(lower) = ground state = aligned with B(0)

the population difference is the difference in alignment to external magnetic field = bulk magnetisation vector, M

always more aligned (n(lower)) since lower energy configuration

39
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describe the size of population differences in NMR

very small = inherently insensitive

= small bulk magnetisation vector

40
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what increasing the sensitivity of NMR for certain nuclei?

 higher gyromagnetic ratios, γ

41
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describe detection in NMR

  1. external magnetic field (B(0)) is applied

= creates bulk magnetisation vector = precess at Larmor frequency due to small population difference

= aligns nuclear spins at equilibrium

  1. RF (radiofrequency) pulse at Larmor frequency tips magnetisation away from B(0) axis, causing bulk magnetisation vector M to precess in the transverse plane (xy) at Larmor frequency

  2. precessing magnetisation creates an oscillating magnetic field that induces current in receiver coil = free induction signal (FID)

42
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what expression describes the lifetime of the transverse component of bulk magnetisation (NOT GIVEN)

M(t) = bulk magnetisation at time t

M(0) = bulk magnetisation at time 0 (after RF pulse)

w = Larmor frequency

<p>M(t) = bulk magnetisation at time t</p><p>M(0) = bulk magnetisation at time 0 (after RF pulse)</p><p>w = Larmor frequency </p>
43
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how can exp(iwt) be expressed alternatively?

using Euler’s formula

<p>using Euler’s formula </p>
44
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describe free induction decay (FID)

= complex and time-dependent (since transverse component of bulk magnetisation decays over time)

M(y) = real component

M(x) = imaginary component

<p>= complex and time-dependent (since transverse component of bulk magnetisation decays over time)</p><p>M(y) = real component</p><p>M(x) = imaginary component </p>
45
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explain the application of the Fourier transform on free induction decay

to convert free induction decay (FID):

time domain signal → frequency domain spectrum

<p>to convert free induction decay (FID):</p><p>time domain signal → frequency domain spectrum </p>
46
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describe pulse acquisition diagrams

visualise sequence of events during NMR experiment

47
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what process can improve SNR (signal:noise ratio)

signal averaging

48
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describe signal averaging

  • experiment repeated multiple times = scans/transients

  • transients added up

SNR ∝ number of transients

49
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what is required of a magnetic to be a magnetic field in an NMR experiment?

  • strength

  • homogeneity

  • stability

50
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what types of magnets can be used in NMR?

  • permanent (<1.5 T)

  • electromagnetic (<2.5 T)

  • superconducting (<23.5T) best on all criteria

51
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describe NMR probes

  • contain rf coils (applied rf pulse AND receives signal)

  • houses the sample

  • can spin and vary temp

52
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describe continuous wave (CW) and Fourier transform (FT) NMR

CW NMR: either

  • keep B(0) constant and vary frequency of rf pulse

  • keep frequency of rf pulse constant and vary B(0)

FT NMR:

  • range of rf pulse frequencies applied at once

53
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what are the components of the electric/magnetic field experienced by a nuclear spin?

  • external field

  • the sample itself (internal)

<ul><li><p>external field</p></li><li><p>the sample itself (internal) </p></li></ul><p></p>
54
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compare solution state vs solid state NMR

solution state = anisotropies are averaged

solid state = anisotropies are NOT averaged = more complex

<p>solution state = anisotropies are averaged</p><p>solid state = anisotropies are NOT averaged = more complex </p>
55
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describe the effect of a nuclei’s local distribution

the local electron distribution around a nucleus effects the resonance frequency at which it processes around the external field

theory = 1H at B(0) = 9.4T should resonate at 400MHz

B(in) = induced magnetic field from external magnetic field caused by circulation of electrons in their AO/MOs

B(in) either opposes (shields = lowers B) or augments (deshields = increases B) the external field

B = effective field

56
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define effective field at nucleus

B = effective field

B(0) = external magnetic field

B(in) = induced magnetic field

σ = shielding

<p>B = effective field</p><p>B(0) = external magnetic field</p><p>B(in) = induced magnetic field</p><p>σ = shielding </p>
57
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describe the effect of shielding

shielding reduces the Larmor frequency of a nucleus

= reduces the energy gap between Zeeman eigenstates

<p>shielding reduces the Larmor frequency of a nucleus</p><p>= reduces the energy gap between Zeeman eigenstates </p>
58
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define chemical shift (given)

( / v(spectrometer) ) removes the dependence on the external field

defines the difference in Larmor frequency of a nucleus w.r.t. a reference

= define the extent of shielding

<p>( / v(spectrometer) ) removes the dependence on the external field </p><p>defines the difference in Larmor frequency of a nucleus w.r.t. a reference</p><p>= define the extent of shielding </p>
59
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describe shielding in atoms vs molecules

atoms = simple = only diamagnetic shielding

molecules = complex (motion of electrons more complex) = diamagnetic and paramagnetic de/shielding

<p>atoms = simple = only diamagnetic shielding </p><p>molecules = complex (motion of electrons more complex) = diamagnetic and paramagnetic de/shielding</p>
60
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describe diamagnetic and paramagnetic de/shielding

diamagnetic shielding = reduces the strength of the magnetic field = induced magnetic field opposing B(0)

= circulates with atomic and molecular orbitals

paramagnetic deshielding = increases the strength of magnetic field = induced magnetic field in the same direction as B(0)

= circulates between occupied ground state MO and unoccupied excited state MO

61
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<p>describe the chemical shifts here</p>

describe the chemical shifts here

diamagnetic shielding effect

aliphatic = circulating electron create B(in) = decrease B(0) = small ppm

Cl = EWG = reduces the shielding/B(in) = larger B(0) w.r.t aliphatic = large ppm

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what are different “anomalies” of chemical shift?

  • ring current

  • H bonding

  • paramagnetic compounds

  • anisotropy

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describe ring current

= aromatics

= ∏ electron clouds generate large electronic currents opposing/aligning with external field

downfield = larger chemical shift = larger B(0) than expected = smaller B(in) = ring currents align with and augment B(0)

= shielding effect directly above and below the ring

= deshielding effect in the external plane of the ring

<p>= aromatics</p><p>= ∏ electron clouds generate large electronic currents opposing/<strong>aligning</strong> with external field</p><p>downfield = larger chemical shift = larger B(0) than expected = smaller B(in) = ring currents align with and <strong>augment </strong>B(0) </p><p>= shielding effect directly above and below the ring</p><p>= deshielding effect in the external plane of the ring</p>
64
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describe hydrogen bonding

= largest (1)H chemical shifts

intramolecular » intermolecular

H bond acceptor draws H away from the heteroatom it is bonded too, reducing the electron density around the H nuclei

= deshielded = smaller B(in) = larger B(0) = larger v(signal) = larger ppm

<p>= largest (1)H chemical shifts</p><p><strong>intramolecular » intermolecular </strong></p><p>H bond acceptor draws H away from the heteroatom it is bonded too, reducing the electron density around the H nuclei</p><p>= deshielded = smaller B(in) = larger B(0) = larger v(signal) = larger ppm</p>
65
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describe paramagnetic compounds

compounds with unpaired electrons generate magnetic field in the presence of external magnetic field

= increase B(in)

= smaller B(0)

= lower ppm = upfield shift

<p>compounds with unpaired electrons generate magnetic field in the presence of external magnetic field </p><p>= increase B(in)</p><p>= smaller B(0) </p><p>= lower ppm = upfield shift</p>
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describe anisotropy (CSA = chemical shift anisotropy)

electron density is anisotropic = shielding is anisotropic = orientation dependent

liquids = rapid tumbling = anisotropic averaging

solids = different orientation of molecule = different amount of shielding

<p>electron density is anisotropic = shielding is anisotropic = orientation dependent </p><p>liquids = rapid tumbling = anisotropic averaging </p><p>solids = different orientation of molecule = different amount of shielding</p>
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describe CSA in single crystals

single crystals:

= all molecule have the same orientation w.r.t. applied field = equivalent anisotropy = single shift

<p>single crystals:</p><p>= all molecule have the same orientation w.r.t. applied field = equivalent anisotropy = single shift</p>
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describe CSA in powders

powder:

= millions of randomly orientated single crystals w.r.t. applied field = different shifts

static powder = broad peak

isotropic (all directions) rotation = CSA averages out = single isotropic chemical shift = sharp peak

<p>powder: </p><p>= millions of randomly orientated single crystals w.r.t. applied field = different shifts </p><p>static powder = broad peak</p><p>isotropic (all directions) rotation = CSA averages out = single isotropic chemical shift = sharp peak </p>
69
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<p>how can the CSA be described here?</p>

how can the CSA be described here?

Δ = 200ppm ?

δ(iso) = 0 = isotropic chemical shift

η = asymmetry of the chemical shift tensor (the variation from δ(iso)) = 0.5

<p><span>Δ = 200ppm ?</span></p><p><span>δ(iso) = 0 = </span>isotropic <span>chemical shift </span></p><p>η = asymmetry of the chemical shift tensor (the variation from <span>δ(iso)) = 0.5</span></p>
70
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describe dipolar interactions

= through space coupling

= magnetic moment (from spin) created when nuclei/unpaired electrons are placed in magnetic field can interact

= interaction of magnetic moments leads to splitting as there are multiple different arrangement of moments with different energies

i.e. parallel = lower E; anti-parallel = higher E

dipolar interaction ∝ gyromagnetic ratio (∝ magnetic moment)

dipolar interaction ∝ 1/r (distance between nuclei)

dipolar interaction related to θ (angle between nuclei)

<p><strong>= through space coupling</strong></p><p>= magnetic moment (from spin) created when nuclei/unpaired electrons are placed in magnetic field can interact</p><p><strong>= interaction of magnetic moments</strong> leads to splitting as there are multiple different arrangement of moments with different energies</p><p>i.e. parallel = lower E; anti-parallel = higher E</p><p>dipolar interaction ∝ gyromagnetic ratio (∝ magnetic moment)</p><p>dipolar interaction ∝ 1/r (distance between nuclei)</p><p>dipolar interaction related to θ (angle between nuclei)</p>
71
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describe dipolar interactions in solution vs solids

solutions = orientations of magnetic dipoles averaged = no interaction

solids = orientations of magnetic dipoles constant = interaction

split by the dipolar coupling constant

<p>solutions = orientations of magnetic dipoles averaged = <u>no interaction</u></p><p>solids = orientations of magnetic dipoles constant = interaction</p><p>split by the dipolar coupling constant</p>
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describe Pake Doublet

result of dipolar interaction in solid powder samples

powder sample = average of all possible magnetic moment orientations is observed (since magnetic moment/spin is nuclear property not structural)

= varying angles of θ = Pake doublet peak follows cosθ

<p>result of dipolar interaction in solid powder samples</p><p>powder sample = average of all possible magnetic moment orientations is observed (since magnetic moment/spin is nuclear property not structural)</p><p>= varying angles of θ = Pake doublet peak follows cosθ </p>
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compare powder chemical shift anisotropy vs dipolar interaction anisotropy

CSA: static = broad peak

isotropic rotation = sharp single peak

dipolar interaction anisotropy: static = average = Pake doublet

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describe J-coupling

= through bonds

= coupling of pairs of nuclear spins indirectly through electrons in bonding orbitals

= isotropic since through bonds

= independent of B(0) since I does not depend on B(0)

= very weak w.r.t. v(signal) ~10Hz

75
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what is the condition for weakly vs strongly coupled nuclei

weakly: difference in Larmor frequencies greatly exceeds their mutual coupling

strongly: difference in Larmor frequencies similar to their mutual coupling

<p>weakly: difference in Larmor frequencies greatly exceeds their mutual coupling</p><p>strongly: difference in Larmor frequencies similar to their mutual coupling </p>
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what are the options for coupling of a pair of spin = ½ nuclei?

A = weakly coupled = 2 doublets

B = strongly coupled = intermediate = ‘second-order’ appearance = roof effect

C = magnetically equivalent = 1 singlet

<p>A = weakly coupled = 2 doublets</p><p>B = strongly coupled = <strong>intermediate </strong>= ‘second-order’ appearance = roof effect</p><p>C = magnetically equivalent = 1 singlet</p>
77
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explain multiplet patterns in spin I = 1/2

the number of possible arrangement of spins depends on: I = spin

2I + 1, where I = spin

  • 1 nuclei: (I=1/2)

2(1/2) + 1 = 2

2 coupled spins can either be parallel or anti-parallel. this gives rise to a doublet peak.

  • 2 x 1 inequivalent nuclei: (I=1/2)

2(1/2) + 1 = 2

2(1/2) + 1 = 2

doublet of doublets

  • 2 x equivalent nuclei: (I=1/2)

total I = 1: 2(1) + 1 = 3

triplet

coupling to 1: 2(1/2) + 1 = 2 doublet

coupled to 1: 2(1/2) + 1 = 2 doublet

~doublet of doublets with coinciding central line = triplet

<p>the number of possible arrangement of spins depends on: I = spin </p><p>2I + 1, where I = spin </p><ul><li><p>1 nuclei: (I=1/2) </p></li></ul><p>2(1/2) + 1 = 2 </p><p>2 coupled spins can either be parallel or anti-parallel. this gives rise to a doublet peak. </p><ul><li><p>2 x 1 inequivalent nuclei: (I=1/2) </p></li></ul><p>2(1/2) + 1 = 2 </p><p>2(1/2) + 1 = 2</p><p>doublet of doublets</p><ul><li><p>2 x equivalent nuclei: (I=1/2) </p></li></ul><p>total I = 1: 2(1) + 1 = 3 </p><p>triplet </p><p>coupling to 1: 2(1/2) + 1 = 2 doublet</p><p>coupled to 1: 2(1/2) + 1 = 2 doublet </p><p>~doublet of doublets with coinciding central line = triplet</p>
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explain multiplet patterns in quadrupolar nuclei (I > 1/2)

= typically obscured by quadrupolar interaction

pattern should follow 2nI + 1

n = number of equivalent spin I nuclei 2

process:

  • find multiplicity by 2nI+1

  • find pattern to 1 by 2I+1

  • repeat for each equivalent nuclei

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<p></p>

knowt flashcard image
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describe the two types of equivalence

chemical = same electronic environment

magnetic = same interaction with applied magnetic field

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describe what happens when B(0) is very weak

Larmor frequency small = chemical shift is small = chance of strong ‘second-order’ appearance increases

<p>Larmor frequency small = chemical shift is small = chance of strong ‘second-order’ appearance increases </p>
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describe features of the roof effect

  • intensities of doublet distorted

  • doublets no longer centres on chemical shift

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describe quadrupolar interaction

quadrupolar nuclei (I>1/2) have non-spherical distribution of charge → electrical quadrupole (eQ) moment

quadrupolar nuclei have:

  • magnetic moment (related to spin)

  • eQ moment (related to charge distribution)

quadrupolar interaction = eQ moment couples to electric field gradient (EFG) created by electron density surrounding nucleus

= very large up to 50MHz

<p>quadrupolar nuclei (I&gt;1/2) have non-spherical distribution of charge → electrical quadrupole (eQ) moment</p><p>quadrupolar nuclei have:</p><ul><li><p>magnetic moment (related to spin)</p></li><li><p>eQ moment (related to charge distribution)</p></li></ul><p>quadrupolar interaction = eQ moment couples to electric field gradient (EFG) created by electron density surrounding nucleus</p><p>= very large up to 50MHz </p>
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describe quadrupolar interaction in liquids vs solids

quadrupolar interaction is anisotropic with respect to B(0) because the EFG is dependent on the direction of B(0)

liquids = rapid molecular motion = averaged = no interacton

solids = broad lines

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describe C(Q) and how it is approximated

C(Q) = quadrupolar coupling constant = describes extent of quadrupolar coupling

C(Q) ∝ size of EFG ∝ 1/symmetry of electron density distribution

EFG can be estimated by the symmetry of the molecule

higher symmetry = smaller EFG = lower C(Q)

lower symmetry = larger EFG = higher C(Q)

<p>C(Q) = quadrupolar coupling constant = describes extent of quadrupolar coupling </p><p>C(Q) <span>∝ size of EFG ∝ 1/symmetry of electron density distribution </span></p><p><span>EFG can be estimated by the symmetry of the molecule</span></p><p><span>higher symmetry = smaller EFG = lower C(Q)</span></p><p><span>lower symmetry = larger EFG = higher C(Q) </span></p>
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describe the appearance of a peak with quadrupolar interaction

doublet

solids = sharp peaks

liquids = averaged = Pake doublet = defined by cosθ

<p>doublet</p><p>solids = sharp peaks</p><p>liquids = averaged = Pake doublet = defined by cos<span>θ</span></p>
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define CT and ST

CT = central transition = between 2 magnetic quantum states (+ve → -ve)

ST = satellite transition = between adjacent m(I) states (+ve → +ve etc.) = more sensitive to quadrupolar coupling

<p>CT = central transition = between 2 magnetic quantum states (+ve → -ve) </p><p>ST = satellite transition = between adjacent m(I) states (+ve → +ve etc.) = <strong>more sensitive to quadrupolar coupling </strong></p>
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describe the relative magnitude of internal interaction in

  • isotropic liquids

  • solids

knowt flashcard image
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describe relaxation

  • spins are aligned to magnetic field B(0) along z-axis = precessing at Larmor frequency = z-magnetisation

  • RF pulse is applied along xy plane = x-y magnetisation

  • spins relax to ground state = z-magnetisation (NO xy magnetisation)

relaxation is caused by local fields which are different for each spin

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what is the conditions for local field inducing relaxation

MUST be at/around the Larmor frequency

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describe the two types of relaxation

  • spin-lattice (T1)

  • spin-spin (T2)

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describe spin-lattice relaxation/longitudinal relaxation

z-component of magnetisation coming to equilibrium

local fields cause spin to rotate either:

  • TOWARDS z-axis = energy release to surroundings

  • AWAY from z-axis = energy investment from surroundings

equal = zero z-magnetisation

lattice is more happy to take up energy than give out energy because it is at thermal/Boltzmann equilibrium = non-zero z-magnetisation (tending towards z-axis)

M(eq) = lattice frequency

<p>z-component of magnetisation coming to equilibrium </p><p>local fields cause spin to rotate either:</p><ul><li><p>TOWARDS z-axis = energy release to surroundings</p></li><li><p>AWAY from z-axis = energy investment from surroundings</p></li></ul><p>equal = zero z-magnetisation</p><p>lattice is more happy to take up energy than give out energy because it is at thermal/Boltzmann equilibrium = <strong>non-zero z-magnetisation </strong>(tending towards z-axis)</p><p>M(eq) = lattice frequency</p>
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describe T1

larger T1 = longer time to reach equilibrium = slower relaxation

smaller T1 = shorter time to reach equilibrium = fast relaxation

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what makes spin-lattice relaxation fast?

  • fast energy transfer between local fields and lattice (and vice versa)

  • B(loc) at the Larmor frequency from CSA/

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what are origins of local fields?

anything that causes fluctuations to local magnetic field (stronger) increases relaxation = more chance of approaching Larmor frequecy

  • dipolar interaction = magnetic field effected to approach the Larmor frequency

∝ γ(1)γ(2) = extent of interaction

∝ 1/r3

  • chemical shift anisotropy (CSA) =

anisotropic nuclei experience slightly different B(0) = B(loc) approaches Larmor frequency

  • quadrupolar interaction

very fast relaxation is C(Q)/quadrupolar interaction is large

  • paramagnetic species

unpaired electrons produce large magnetic moments which can affect B(loc)

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describe spin-spin relaxation/transverse relaxation

decay of xy component of magnetisation to equilibrium value of 0

spins interact with each and cause different local fields in xy plane = precess at slightly different Larmor frequencies = net xy magnetisation decreases over time

<p>decay of xy component of magnetisation to equilibrium value of 0</p><p>spins interact with each and cause different local fields in xy plane = precess at slightly different Larmor frequencies = net xy magnetisation decreases over time</p>
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describe T2

larger T2 = longer time to reach equilibrium = slower relaxation

smaller T2 = shorter time to reach equilibrium = fast relaxation

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describe the appearance of peak with T2

gives linewidth

long T2 = slow relaxation = sharp peak

short T2 = fast relaxation = broad peak

<p><strong>gives linewidth </strong></p><p>long T2 = slow relaxation = sharp peak</p><p>short T2 = fast relaxation = broad peak</p>
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<p>describe this graph </p>

describe this graph

low τ(c) = fast molecular vibration = liquid

high  τ(c) = slow molecular vibration = solid

liquid = equal contribution of longitudinal/transverse relaxation

solid = transverse relaxation > longitudinal relaxation

T₂ relaxation in solids is much faster than T₁ because the local field fluctuations due to dipolar interactions cause rapid dephasing, but the lack of molecular motion limits the efficiency of energy transfer to the lattice (T₁).

<p>low τ(c) = fast molecular vibration = liquid</p><p>high&nbsp; τ(c) = slow molecular vibration = solid</p><p>liquid = equal contribution of longitudinal/transverse relaxation</p><p>solid = transverse relaxation &gt; longitudinal relaxation</p><p><strong>T₂ relaxation</strong> in solids is much faster than <strong>T₁</strong> because the <strong>local field fluctuations</strong> due to dipolar interactions cause rapid dephasing, but the lack of molecular motion limits the efficiency of energy transfer to the lattice (T₁).</p>
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describe an application of NMR

= molecular dynamics

= can study inequivalent signals tending to equivalence due to molecular motion

<p>= molecular dynamics</p><p>= can study inequivalent signals tending to equivalence due to molecular motion </p>