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CFG to Chomsky steps
new start state
Eliminate all E rules
Remove all unit rules
Fix the rest
(S → V1V2 | t | E
V → V1V2 | t )
If A is a context free language, then there is a number p (the pumping length) where, if s E A and has at least p symbols, that is, |s| >= p, the string s can be divided into five substrings s = uvxyz satisfying the conditions…
For all i >= 0 and i E Z, uv^ixy^iz E A
|xy| > 0
|vxy| <= p
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