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speed
scalar
velocity
vector
on a plate, the ball’s instantaneous velocity
straight line tangent to the curve
rolling a ball at a constant speed around on the plate, is it accelerating?
yes because it’s changing direction
A=(change of v)/t
A force perpendicular to an objects motion….
…will cause it to change direction not speed
Period (T)
The time it takes for something to complete 1 entire cycle/revolution
Reciprocal to frequency
Frequency (f)
The number of cycles /revolutions completed by an object in a second
Reciprocal to period
Equation for Period
T = 1/f
Speed equation
V=d/t = 2(pi)R/T = 2(pi)Rf
V is what to the curve?
Tangent
Centripetal acceleration
Represents the rate of direction change (turning rate)
Always points into the circle traveled by the object
Only changes direction of velocity, it doesn’t speed up the object or slow down the object
Equation for centripetal acceleration
Ac. V² / R
v= speed of object moving in circle
R=radius of circle the object travels in
UCM
Uniform circular motion
Constant speed
Only Ac, no Atan
Relationship between v and Ac
V:Ac
Direct relationship
Relationship between R and Ac
Opposite
R would decrease as Ac increases
Inverse relationship
What can rapid turn rate be from
High speed, sharp turns, or both
If you slow down/speed up, Atan and Ac will…
…will be present
Force Fg
Directly proportional to the masses (M + m) and is inversely proportional to the square of the center to center distance R between the objects
Newtons universal force of gravity
All masses M in the universe pull/attract every other mass m with gravitational force Fg
Relationships btwn M1M2 and Fg
Proportional
Direct relationship
Relationship btwn R and Fg
Inverse relationship
Gravitational force
FG = Gm1(m2) / R²
R= the center-to-center distance btwn the two masses M and m
little g
Acceleration due to gravity (gravitational field)
Masses create a gravitational field g around them
The filled g exerts grav force on other masses in its field
Method 1 of calculating g
Fg=mg
Fg=Gmm2/R²
g=GMp/R²
Method 2 for calculating g
g=Fg/m
m=mass placed in the gravitational field
Fg= gravitational force exerted on mass m
Density
p=m/v
m=pv
Volume of a sphere
V=4/3(pi)R³
Gravitational orbit
When an astronomical object (like a planet) orbits another Astro. Obj , we say it is in a gravitational orbit
If the orbit is a circle we can use the form for Ac to relate the speed, radius of orbit, and mass
Formula for gravitational orbit
Vo=(square root) GMp/R
Gravitational field due to a uniform solid sphere
max strength of the Fg is right at the surface of the planet
As you leave a planet, g decreases w 1/R²
Outside the sphere, it is the same as if all of the objet’s mass were concentrated at its center of mass
Tunneling into the center of a planet, g wold decrease linearly
Grav field due to a uniform thin, hollow shell
g=0 inside
G=GMp/R²
Gravitational force on an object inside a solid sphere
an object inside a solid sphere of uniform density experiences a new gravitational force from only a partial
Mass of the sphere
Fg=Gm1m2/R²
Martial =p4/3(pi)(rpartial)³
Period equation
T= time/number of cycles
frequency equation
f=number of cycles/time
Force of friction
Fg (less than or equal to) (mew)FN