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What does the direction of the field lines represent?
The direction of the force acting on a positive test charge
Electrical field strength??
Force / unit charge
Or also E=kq/r²
Where k= 9×109
Coulomb’s law ?
The product of the two charges is directly proportional to the force of attraction/repulsion but inversely proportional to the square of the distance between them
F = kQ1Q2 /r²
Electrical potential ?
The work done to take a positive test charge from infinity to a point
V= wd/q
Electrical potential in a radial field??
Here we use V= kQ/r
we add in the sign of the charge here
Field line properties?
Parallel and evenly spaced (uniform)
the concentration across the field lines is equal
goes from + to -
acceleration of electrons in the field is equal
on a positive test charge the direction of the force is outwards
Equipotential surface?
Point at which zero work is done to overcome to force of attraction/#
follows the shape of the plates and should be perpendicular to the field lines
Electric potential in parallel plates?
w = f x d and E = f/q so if f = qe then w= qe x d, we know w/q is V so V= Ed and therefore V/d is the potential
We only use this in parallel plates NOT radial fields
Electric field strength in a radial field?
E =kq/r²
Acceleration of a particle in an electric field?
f =ma and f =qe so ma=qe , ma =qv/d so a = qv/md
we use e=v/d as it applies to moving particles in parallel plates
Potential difference?
Work done per unit charge
Will the acceleration of many electrons in an electric field between two plates be the same?
YES!!
Following a=qv/md , all values for the electrons are the same
Will the acceleration of an electron and a proton be the same in an electric field between two plates?
NO!!
Following a=qv/md, the variable which is different is m as a proton is heavier than an electron