Waves 2

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Superposition of waves

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Overlap of two waves at a point in space

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Principle of superposition (of waves)

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When two waves meet at a point the resultant displacement at that point is equal to the sum of the displacements of the individual waves.

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32 Terms

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Superposition of waves

Overlap of two waves at a point in space

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Principle of superposition (of waves)

When two waves meet at a point the resultant displacement at that point is equal to the sum of the displacements of the individual waves.

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Interference

Superposition of two progressive waves from coherent sources to produce a resultant wave with a displacement equal to the sum of the individual displacements from the two waves

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Constructive interference

Superposition of two waves in phase so that the resultant wave has greater amplitude than the original waves

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Destructive interference

Superposition of two waves in antiphase so that the waves cancel each other out and the resultant wave has smaller amplitude than the original waves

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Coherent waves/ waves sources

Waves/ waves sources that have a constant phase difference. For this to happen they must have the same frequency

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Path difference

  • The difference in the distance travelled by two waves from their source to a specific point

  • Difference is often measured in wavelengths

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Monocromatic wave (source)

(Source that emits) Waves of a single frequency

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How you can obtain two coherent light sources from a laser

  • Light from a Laser is coherent

  • The two slits act as two coherent point sources. They diffract the coherent light from the laser.

<ul><li><p>Light from a Laser is coherent</p></li><li><p>The two slits act as two coherent point sources. They diffract the coherent light from the laser.</p></li></ul><p></p>
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How you can obtain two coherent light sources from a white light filament bulb

  • Place a monochromatic filter in fron of the bulb.

  • The Monochromatic filter only transmits one wavelength.

  • A single narrow slit selects and diffracts the light from one point, so that all the light emerging from it is coherent.

  • The double slits act as two identical coheren point sources. They diffract the coherent light passing through them.

<ul><li><p>Place a monochromatic filter in fron of the bulb. </p></li><li><p>The Monochromatic filter only transmits one wavelength.</p></li><li><p>A single narrow slit selects and diffracts the light from one point, so that all the light emerging from it is coherent.</p></li><li><p>The double slits act as two identical coheren point sources. They diffract the coherent light passing through them.</p></li></ul><p></p>
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Young’s double slit equation

λ = ax/D

λ is the wavelength in metres, a is the slit separation in metres, x the fringe separation in metres, D is the distance between the slits and the screen in metres.

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Youngs double slit experiment (diagram, equipment, method, analysis, uncertainties)

Aim of this experiment is to find the wavelength of a light source. λ is the wavelength, a is the slit separation, x the fringe separation, D is the distance between the slits and the screen.

Diagram:

  • Shown above

Equipment:

  • Laser

  • Double slit

  • White Screen

  • Ruler

  • Tape measure

  • Travelling microscope

Method:

  • To obtain two coherent sources shine light

    from a laser through a double slit.

  • The equipment needs to be set up so that D is greater than 1m. Measure the distance D with a tape measure.

  • Measing slit separation using a travelling microscope.

  • To find fringe spacing x, use a ruler to measure the distance from the centre of the first dot to the centre of the last visible dot. Count the number of spaces between the dots. x = distance / number of spaces

  • The distance is measured over a number of

    fringes to reduce the percentage uncertainty

    in x.

  • Increase D and repeat measurements to determine the new value of x . Repeat for this at least 6 different D values

Analysis:

  • Rearranging λ = ax/D gives x = λD / a

  • Plot a graph of x against D: x = (λ/a)D + 0

  • This should be a straight line through the origin

  • The gradient is equal to λ/a. Rearranging gives λ = gradient × a

Uncertainties:

  • The measurements of D, a and x all have uncertainties from the measuring instruments used. The absolute uncertainty in each remains constant, but the percentage uncertainty can be reduced. To do this, you can:

    • Increase D

    • For x, use x = distance / number of spaces, and measure the distance over a number of

      fringes

<p>Aim of this experiment is to find the wavelength of a light source. λ is the wavelength, a is the slit separation, x the fringe separation, D is the distance between the slits and the screen.</p><p>Diagram:</p><ul><li><p>Shown above</p></li></ul><p>Equipment:</p><ul><li><p>Laser</p></li><li><p>Double slit</p></li><li><p>White Screen</p></li><li><p>Ruler</p></li><li><p>Tape measure</p></li><li><p>Travelling microscope</p></li></ul><p>Method:</p><ul><li><p>To obtain two coherent sources shine light</p><p>from a laser through a double slit.</p></li><li><p>The equipment needs to be set up so that D is greater than 1m. Measure the distance D with a tape measure.</p></li><li><p>Measing slit separation using a travelling microscope.</p></li><li><p>To find fringe spacing x, use a ruler to measure the distance from the centre of the first dot to the centre of the last visible dot. Count the number of spaces between the dots. x = distance / number of spaces</p></li><li><p>The distance is measured over a number of</p><p>fringes to reduce the percentage uncertainty</p><p>in x.</p></li><li><p>Increase D and repeat measurements to determine the new value of x . Repeat for this at least 6 different D values</p></li></ul><p>Analysis:</p><ul><li><p>Rearranging λ = ax/D gives x = λD / a</p></li><li><p>Plot a graph of x against D: x = (λ/a)D + 0</p></li><li><p>This should be a straight line through the origin</p></li><li><p>The gradient is equal to λ/a. Rearranging gives λ = gradient × a</p></li></ul><p>Uncertainties:</p><ul><li><p>The measurements of D, a and x all have uncertainties from the measuring instruments used. The absolute uncertainty in each remains constant, but the percentage uncertainty can be reduced. To do this, you can:</p><ul><li><p>Increase D</p></li><li><p>For x, use x = distance / number of spaces, and measure the distance over a number of</p><p>fringes</p></li></ul></li></ul><p></p>
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Monochromatic light / source / filter

Light of a single frequency / source that emitts single frequency / filter that transmitts a single frequency

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Conditions necessary for the formation of a stationary wave

  • Two waves that superpose

  • Same wavelength or frequency

  • Equal and opposite velocities

  • Same or similar amplitudes

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Key condition for harmonics to occur on string

  • The length of a vibrating section of string is a whole number of half wavelengths

  • Time for a wave to travel along the string & back is equal to the time for a whole number of waves

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<p>The diagram shows a string stretched between two posts. The string is plucked and a stationary wave is set up. What is the phase difference between P and Q?</p><ul><li><p>A: 0 rad</p></li><li><p>B: π/4 rad</p></li><li><p>C: π/2 rad</p></li><li><p>D: π rad</p></li></ul><p></p>

The diagram shows a string stretched between two posts. The string is plucked and a stationary wave is set up. What is the phase difference between P and Q?

  • A: 0 rad

  • B: π/4 rad

  • C: π/2 rad

  • D: π rad

Multichoice answer: A

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<p>Explain how the stationary wave is formed on the stretched string shown in the diagram</p>

Explain how the stationary wave is formed on the stretched string shown in the diagram

  • Waves are reflected at the pulley end.

  • This produces nodes and antinodes on the string.

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Stationary/ standing wave

  • Wave that remains in a constant position with no net transfer of energy

  • Characterised by its nodes and antinodes

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Node

Point(s) on a stationary wave where the amplitude is always zero

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Anti-node

Point(s) on a stationary wave where there is alway the maximum amplitude

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2nd Harmonic in a string (diagram)

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3rd Harmonic in a string (diagram)

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2nd Harmonic in a air colomn closed at one end (diagram)

There is no 2nd ___, or any even ____, in an air column closed at one end

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3nd Harmonic in a air colomn closed at one end (diagram)

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5nd Harmonic in a air colomn closed at one end (diagram)

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Fundamental frequency

The lowest frequency at which an object (e.g., an air column in a pipe or a string fixed at both ends) can vibrate

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Fundamental mode of vibration

A vibration at the fundamental frequency; the first harmonic

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Which type of ends do nodes form at on strings?

___ form at fixed ends of a string

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Which type of ends do nodes form at in strings?

___ form at closed ends of an air column

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Phase difference of points between a pair of nodes

All points between the pair of ___ are in phase

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Phase difference of points either side of a node

The points are in anti phase

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Phase difference

The difference in degrees/radians between two points on the same wave or similar points on two waves