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Amount of substance (mol)
n=m (g)/Mr
Amount= mass (in grams) Ă· relative Molecular mass
mass (g)
n Ă— Mr
Amount Ă— relative molecular mass
relative molecular mass
m Ă· n
Mass (g) Ă· amount (mol)
Amount of gas
V(dmÂł) Ă· 24
OR V (cmÂł) Ă· 24000
Depends on unit of volume
Volume of gas (dmÂł)
V (dmÂł) = n Ă—24
Amount of substance in solution
n=( VĂ—C ) Ă· 1000
Volume (cmÂł) Ă— Concentration Ă· 1000
If volume is in dmÂł, do not Ă·1000
Neutralisation reaction
CaĂ—VaĂ—b = CbĂ—VbĂ—a
a=acid
b=base
C=concentration
V=volume
Percentage yield
(Actual yield Ă· theoretical yield ) Ă—100
Percentage purity
(Mass of pure substance Ă· mass of contaminated substance) Ă—100