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Point Line
Take the vector from a point on the line to your point.
Cross it with the line’s direction vector.
Divide the length of that cross product by the length of the line’s direction vector.
✅ Gives the shortest (perpendicular) distance.

Skew Lines
Take the vector connecting any point on line 1 to any point on line 2.
Dot it with the cross product of the two lines’ direction vectors.
Take the absolute value and divide by the length of the cross product of the directions.
✅ Gives the shortest distance between the lines.

Angle Line and plane
Take the line’s direction vector.
Dot it with the plane’s normal vector.
Divide by the product of their lengths.
Take the arcsine of that value.
✅ This gives the angle between the line and the plane.

Angle Plane and plane
Take the normals of the two planes.
Dot them together and divide by the product of their lengths.
Take the arccosine of that value.
✅ This gives the angle between the planes.

Perpendicular distance between a line and a plane in parallel
Pick any point $P(x_0, y_0, z_0)$ that lies on the line (this is usually given as the position vector in the line's equation).
Ensure the plane equation is in Cartesian form: $ax + by + cz + d = 0$.
Substitute the point's coordinates into the plane's expression: $ax_0 + by_0 + cz_0 + d$.
Take the absolute value of that result and divide it by the magnitude (length) of the normal vector $\sqrt{a^2 + b^2 + c^2}$.
✅ This gives the perpendicular distance $D$.

Distance between parallel planes
Make sure both planes are written in the form
ax+by+cz+d=0ax+by+cz+d=0
Check that the x,y,zx,y,z coefficients are the same.
✅ This confirms the planes are parallel.
Subtract the constant terms.
∣d2−d1∣∣d2−d1∣
Find the magnitude of the normal vector.
a2+b2+c2a2+b2+c2
Divide the difference in constants by the magnitude of the normal vector.
✅ This gives the perpendicular distance between the planes.
