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B


C
find peak voltage (approx 9.9)
2 x peak voltage must fit (peak and trough) approx 19.8
19.8/8 = 2.47
must be higher than 2.47


D
time difference = 0.6 divs
0.6 × 5 ×10^-3 = 3 ×10^-3
3x10^-3 / 40×10^-3 = 3/40
3/40 × 2pi = 3/20 pi = 0.15 pi


A


B
P = I² R
I rms = I/√2
P’ = (1/√2)² x 2 R = P
