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Complexation
______ reactions between metals and ligands
Metal-ligand complexes
___________ are formed by coordinate covalent bonds wherein the ligand provides the lone pair/s in the reaction.
Complexing agents
___________ are used in pharmaceutical products to sequester metal cations that may affect product quality and stability.
Metallochromic indicators
_________ are ligands that undergo definite color transitions in the presence of specific metal cations.
Change color when metal is removed by a stronger ligand (EDTA).
These indicators can be used to indicate the presence of metal cations in different pharmaceutical products.
Monodentate ligands
They bind using one donor atom, can still form complex ions, and affect precipitation.
Chelating agents
form stable soluble complexes and prevent precipitation of metal hydroxides and salts.
disinfectants and antiseptics
Some of oxidizing agents have been routinely used as _____________.
Reducing agents
__________ are important pharmaceutical excipients. They act as antioxidants to prevent the oxidative decomposition of pharmaceutical products.
Color change (red to blue)
Ca²⁺ forms a complex with the indicator
Calcium-hydroxynaphthol complex
Calcium chloride + Hydroxynaphthol blue will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
return to the red color
EDTA binds Ca²⁺ more strongly
Ca–EDTA complex
Calcium chloride + Disodium edetate (EDTA) will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
formation of a red/pink color
Zn²⁺ complexes with dithizone
Zn–dithizone complex
Zinc Sulfate + Dithizone will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
disappearance of color or return to colorless
EDTA displaces dithizone
Zn–EDTA complex
Zinc Sulfate + Disodium Edetate will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
color change (blue → wine red)
Mg²⁺ binds to the indicator
Mg–erichrome complex
Manesium Sulfate + Erichrome black will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
return to blue color
EDTA removes Mg²⁺
Mg–EDTA complex
Manesium Sulfate + Disodium Edetate will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
Edetate (EDTA)
The strongest chelating agent that removes metals, not an indicator, that drives the reaction toward the endpoint.
Forms very stable complexes, used in complexometric titrations
brings back the color to original color
Hydroxynaphthol blue
Eriochrome black
_________ & ________ are metallochromic indicators that change colors with alkaline metals
red to blue to red
blue to red to blue
Dithizone
The metallochromic indicator that changes color with heavy metals.
Colorless to pink/red to colorless
formation of a blue precipitate
Cu²⁺ reacts with OH⁻, hydroxide is insoluble
Cuprous hydroxide
Copper(II) Sulfate + Sodium hydroxide will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
reduced or no precipitate
EDTA forms strong, soluble complexes with copper (II), even insoluble hydroxides can be dissolved.
Cu–EDTA complex
Copper(II) Sulfate + Sodium hydroxide + EDTA will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
formation of a white precipitate
Ca²⁺ reacts with PO₄³⁻, Phosphate is insoluble
Calcium Phosphate or Ca₃(PO₄)₂
Calcium chloride + Sodium phosphate will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
decreased or no precipitate
citrate binds or removes Ca²⁺ = less Calcium phosphate precipitate forms
Ca-citrate complex
Calcium chloride + Sodium phosphate + Sodium citrate will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
formation of a blue precipitate
Cu²⁺ reacts with OH⁻, hydroxide is insoluble
Cuprous Hydroxide
Copper(II) Sulfate + Sodium hydroxide will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
partially dissolved precipitation
tartrate complexes Cu²⁺, but not strong enough as EDTA
Cu–tartrate complex
Copper(II) Sulfate + Sodium hydroxide + Sodium tartrate will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
Sodium tartrate
It can act as a mild chelating agent or masking agent, to dissolves precipitates.
Sodium citrate
It often used to mask calcium or magnesium, controls precipitation in phosphate reactions.
formation of a deep blue solution
Ammonia is a monodentate ligand that binds one lone pair of electrons to Copper (II)
Tetraamminecopper (II) complex
Copper(II) Sulfate + Sodium hydroxide + Ammonia will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
formation of a white precipitate
Zn²⁺ reacts with CO₃²⁻, carbonate is insoluble
Zinc Carbonate or ZnCO₃
Zinc Sulfate + Sodium carbonate will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
dissolution of precipitate
CN⁻ forms a stable complex, binds to zinc.
Tetracyanozincate (II) complex
Zinc Sulfate + Sodium carbonate + Sodium cyanide will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
formation of a red precipitate
formation of a red precipitate, has high bond with other and have low Ksp
Mercury iodide
Mercuric chloride + Potassium iodide will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.
dissolution of precipitate
excess iodide forms a complex so the precipitate dissolves
Tetraiodomercurate (II) complex
Mercuric chloride + Potassium iodide + Excess Potassium iodide will have a visible result of __________, because ___________.
The product responsible is __________.
The final product is ___________.