BPS 124L: Complexation and Redox reactions

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Last updated 6:21 AM on 4/6/26
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31 Terms

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Complexation

______ reactions between metals and ligands

2
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Metal-ligand complexes

___________ are formed by coordinate covalent bonds wherein the ligand provides the lone pair/s in the reaction.

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Complexing agents

___________ are used in pharmaceutical products to sequester metal cations that may affect product quality and stability.

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Metallochromic indicators

_________ are ligands that undergo definite color transitions in the presence of specific metal cations.

  • Change color when metal is removed by a stronger ligand (EDTA).

  • These indicators can be used to indicate the presence of metal cations in different pharmaceutical products.

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Monodentate ligands

They bind using one donor atom, can still form complex ions, and affect precipitation.

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Chelating agents

form stable soluble complexes and prevent precipitation of metal hydroxides and salts.

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disinfectants and antiseptics

Some of oxidizing agents have been routinely used as _____________.

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Reducing agents

__________ are important pharmaceutical excipients. They act as antioxidants to prevent the oxidative decomposition of pharmaceutical products.

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Color change (red to blue)

Ca²⁺ forms a complex with the indicator

Calcium-hydroxynaphthol complex

Calcium chloride + Hydroxynaphthol blue will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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return to the red color

EDTA binds Ca²⁺ more strongly

Ca–EDTA complex

Calcium chloride + Disodium edetate (EDTA) will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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formation of a red/pink color

Zn²⁺ complexes with dithizone

Zn–dithizone complex

Zinc Sulfate + Dithizone will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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disappearance of color or return to colorless

EDTA displaces dithizone

Zn–EDTA complex

Zinc Sulfate + Disodium Edetate will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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color change (blue → wine red)

Mg²⁺ binds to the indicator

Mg–erichrome complex

Manesium Sulfate + Erichrome black will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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return to blue color

EDTA removes Mg²⁺

Mg–EDTA complex

Manesium Sulfate + Disodium Edetate will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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Edetate (EDTA)

The strongest chelating agent that removes metals, not an indicator, that drives the reaction toward the endpoint.

Forms very stable complexes, used in complexometric titrations

  • brings back the color to original color

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Hydroxynaphthol blue

Eriochrome black

_________ & ________ are metallochromic indicators that change colors with alkaline metals

  • red to blue to red

  • blue to red to blue

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Dithizone

The metallochromic indicator that changes color with heavy metals.

  • Colorless to pink/red to colorless

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formation of a blue precipitate

Cu²⁺ reacts with OH⁻, hydroxide is insoluble

Cuprous hydroxide

Copper(II) Sulfate + Sodium hydroxide will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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reduced or no precipitate

EDTA forms strong, soluble complexes with copper (II), even insoluble hydroxides can be dissolved.

Cu–EDTA complex

Copper(II) Sulfate + Sodium hydroxide + EDTA will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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formation of a white precipitate

Ca²⁺ reacts with PO₄³⁻, Phosphate is insoluble

Calcium Phosphate or Ca₃(PO₄)₂

Calcium chloride + Sodium phosphate will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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decreased or no precipitate

citrate binds or removes Ca²⁺ = less Calcium phosphate precipitate forms

Ca-citrate complex

Calcium chloride + Sodium phosphate + Sodium citrate will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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formation of a blue precipitate

Cu²⁺ reacts with OH⁻, hydroxide is insoluble

Cuprous Hydroxide

Copper(II) Sulfate + Sodium hydroxide will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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partially dissolved precipitation

tartrate complexes Cu²⁺, but not strong enough as EDTA

Cu–tartrate complex

Copper(II) Sulfate + Sodium hydroxide + Sodium tartrate will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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Sodium tartrate

It can act as a mild chelating agent or masking agent, to dissolves precipitates.

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Sodium citrate

It often used to mask calcium or magnesium, controls precipitation in phosphate reactions.

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formation of a deep blue solution

Ammonia is a monodentate ligand that binds one lone pair of electrons to Copper (II)

Tetraamminecopper (II) complex

Copper(II) Sulfate + Sodium hydroxide + Ammonia will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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formation of a white precipitate

Zn²⁺ reacts with CO₃²⁻, carbonate is insoluble

Zinc Carbonate or ZnCO₃

Zinc Sulfate + Sodium carbonate will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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dissolution of precipitate

CN⁻ forms a stable complex, binds to zinc.

Tetracyanozincate (II) complex

Zinc Sulfate + Sodium carbonate + Sodium cyanide will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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formation of a red precipitate

formation of a red precipitate, has high bond with other and have low Ksp

Mercury iodide

Mercuric chloride + Potassium iodide will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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dissolution of precipitate

excess iodide forms a complex so the precipitate dissolves

Tetraiodomercurate (II) complex

Mercuric chloride + Potassium iodide + Excess Potassium iodide will have a visible result of __________, because ___________.

  • The product responsible is __________.

  • The final product is ___________.

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