Unit 5 - random variables

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35 Terms

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Random variable

A numerical value whose value depends on the outcome of a chance experiment

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Discrete vs. continuous random variable

  • Discrete: the variable is a set of possible integer values

    • ex: the number of cats = {0, 1, 2, 3}

  • Continuous: A set of possible values that includes an entire interval (within a certain range)

    • ex: how long it takes to bake = 0 ≤ X ≤ 100

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Probability distribution of random variable

Add to 1

<p>Add to 1</p>
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Probability histogram

P(1 ≤ X ≤ 3) ≠ P(1 < X < 3)

<p>P(1 ≤ X ≤ 3)  ≠<strong>  </strong>P(1 &lt; X &lt; 3)</p>
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Expected value of random variable [by hand]

  • Expected value = mean

<ul><li><p>Expected value = mean</p></li></ul><p></p>
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Standard deviation of random variable [by hand]

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Mean & SD of random variable [calculator]

  • Go to list

  • Enter random variables in L1

  • Enter probabilities in L2

  • Stat → 1vars

  • Set list: L1

  • FreqList: L2

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What happens to mean/SD/variance when adding/subtracting?

Measures of position change, measures of spread do not

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What happens to mean/SD/variance when multiplying/dividing?

Both measures of position and spread change

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Adding or subtracting random variables

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Adding random variables, one of them is multiplied by a constant

<img src="https://knowt-user-attachments.s3.amazonaws.com/06fe4a24-9f9e-4674-a944-637e084bf8dc.png" data-width="100%" data-align="center"><p></p>
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How to normal distribution combining variables

  • Combine mean and standard deviation

  • Make a new graph with new mean and standard deviation

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Conditions for a binomial setting

  • Binary = either a success or failure

  • Independent

  • Number = the number of trials n of the chance process must be fixed

  • Success = on each trial, the probability  p of success must be the same

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Binomial formula

How to do (n/x) combination:

n → math → prob → nCr → x = answer

<p>How to do (n/x) combination:</p><p></p><p>n → math → prob → nCr → x = answer</p>
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binompdf (n, p, x)

Finds the probability of getting an exact value out of n trials with probability p

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binomcdf(n, p, x)

Finds the probability of getting a value [at most X times / X times or less] out of n trials with probability p

Even though the probability of exactly 7 successes is tiny, the cumulative probability up to 7 includes all possible outcomes 0,1,2,…,70, 1, 2, …, 70,1,2,…,7, so it must add up to 1.

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“The probability of having a cat is 0.3 What is the probability that exactly 5 people, out of 10, will have a cat.”

binompdf(10, 0.3, 5)

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“The probability of having a cat is 0.3 What is the probability that at most 5 people, out of 10, will have a cat.”

binomcdf(10, 0.3, 5)

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“The probability of having a cat is 0.3 What is the probability that between 4 and 7 people (inclusive), will have a cat.”

binomcdf(10, 0.3, 7) - binomcdf(10, 0.3, 3)

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“The probability of having a cat is 0.3 What is the probability at least 5 out of 10 people will have a cat.”

1 - binomcdf(10, 0.3, 4)

You do 1 - (…) because the calculator only does X OR LESS. It cannot count up

Also you do 4 instead of 5 bc binom function is inclusive

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Under what conditions is a normal distribution a good approximation to the binomial distribution?

  • np 10

  • n(1-p) 10

And in your sentence you have to say “therefore, using a normal distribution to approximate this binomial distrubition for this problem…”

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How to find mean and standard deviation of binary distribution

knowt flashcard image
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What is a geometric setting

A geometric setting arises when we perform independent trials of the same chance process and record the number of trials until the first success

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Conditions for a geometric distribution

BITS

  • B = binary (success or fail)

  • I = independent

  • T = stops after a success

  • S = on each trial, the probability p of success stays constant

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Rule for calculating geometric probabilities

P(X = n) = p(1 - p)n-1

This is essentially the multiplication rule; imagine landing on 5 for the first time on the 3rd roll of the die

(5/6)(5/6)(1/6) → multiplication rule!

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The probability that it takes more than n trials to see the first success P(X > n)

P(X > n) = (1 - p)n

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Mean and SD for geometric distribution

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geometpdf(.5, 3)

What is the probability that a success (0.5 chance) occurs on exactly the 3rd trial

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geometcdf(0.5, 3)

What is the probability that a success (0.5 chance) occurs on the 3rd or before

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In a geometric distribution, which trial has the highest probability of success?

The first, since with each trial you are multiplying by a number < 1

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Compare the shapes of the graphs of binomial distributions vs. geometric distributions

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Identifying each distribution

excepts it’s just B and G

<p>excepts it’s just B and G</p>
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