6.3.2 Motion of Charged Particles

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11 Terms

1
<p>Explain the following </p>

Explain the following

-When fields point in the same direction, fields add up. Producing a stronger field

-When the point in the opposite direction, it cancels, so a weaker field is formed

-Strong field down and weaker field up causes the wire to be pushed upwards

<p>-When fields point in the same direction, fields add up. Producing a stronger field</p><p>-When the point in the opposite direction, it cancels, so a weaker field is formed</p><p>-Strong field down and weaker field up causes the wire to be pushed upwards</p>
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2

Describe the trajectory of a charged particle in a uniform magnetic field

Charged particles follow a circular path in a magnetic field

<p>Charged particles follow a circular path in a magnetic field </p>
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3

Why do charged particles follow a circular path in a magnetic field

Because the magnetic force is perpendicular to velocity and acts as a centripetal force

<p>Because the magnetic force is perpendicular to velocity and acts as a centripetal force</p>
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4

How to calculate the force on the charged particle travelling at right angles to a uniform magnetic field

F=BQv

F= force (N)

B= magnetic flux density (T)

Q= Charge (C)
v= velocity (ms-1)

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5

How can a velocity selector choose e- with a desirable speed

  • The source produces e- with a variety of speeds

  • Electric and magnetic fields are perpendicular

  • e- experiences: Electric force (F= qE) upwards and magnetic force downwards (F=Bqv)

  • The electric force is constant

  • Magnetic force is higher in faster-moving electrons

  • if FE=FB electron passes straight through (these are the electrons with the wanted velocity!)

  • if FB>FE, e- deflects downwards

  • if FE>FB, e- deflects upwards

<ul><li><p>The source produces e- with a variety of speeds </p></li><li><p>Electric and magnetic fields are perpendicular </p></li><li><p>e- experiences: Electric force (F= qE) upwards and magnetic force downwards (F=Bqv)</p></li><li><p>The electric force is constant  </p></li><li><p>Magnetic force is higher in faster-moving electrons </p></li><li><p>if F<sub>E</sub>=F<sub>B</sub> electron passes straight through (these are the electrons with the wanted velocity!)</p></li><li><p>if F<sub>B</sub>&gt;F<sub>E</sub>, e- deflects downwards </p></li><li><p>if F<sub>E</sub>&gt;F<sub>B</sub>, e- deflects upwards  </p></li></ul><p></p>
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6

Show that the speed of electrons chosen by the selector is given by v=E/B

F=Bqv
F=qE

Bqv=qE

v=E/B

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7

How to adjust the wanted speed of the e-

v=E/B

Increasing B, would target slower electrons

Decreasing B, targets faster electrons

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8

What happens to the chosen speed of e- is the p.d. across the plates is increased

The electric force increases, which is directly proportional to the velocity of e-

So the selector chooses faster electrons

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9

How does a spectrometer work

  • A source fires ions into a velocity selector

  • Ions with the wanted speed pass through the selector

  • So, now all the ions have the same speed ( v=E/B)

  • Ions now move into a strong perpendicular magnetic field with a known magnetic flux density

  • In the magnetic field, they travel on circular paths until they hit a detector

  • The distance from where they enter the field to where they hit the detector is 2r (measuring this the radius can be found)

<ul><li><p>A source fires ions into a velocity selector </p></li><li><p>Ions with the wanted speed pass through the selector</p></li><li><p>So, now all the ions have the same speed (<em> v=E/B</em>)</p></li><li><p>Ions now move into a strong perpendicular magnetic field with a known magnetic flux density </p></li><li><p>In the magnetic field, they travel on circular paths until they hit a detector </p></li><li><p>The distance from where they enter the field to where they hit the detector is <em>2r </em>(measuring this the radius can be found)</p></li></ul><p></p>
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10

How can a spectrometer measure the charge: mass ratio (q/m) of ions that travel through it

F= Bqv F= mv2/r
Bqv= mv2/r
r= mv/Bq
rBq=mv
rB/v=m/q
v/rB=
q/m

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11

Why is it important for all the ions to have the same speed

So, the only thing affecting the q/m ratio is the mass.
A variable speed affects the ratio

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