Algebraic Identities and Fundamentals of Maths

3.0(2)
Studied by 36 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/96

flashcard set

Earn XP

Description and Tags

Flashcards made from Maths Unplugged's crash course videos. Suitable for those writing JEE. Answer only with definition (I've included cards for both ways around). There are topics not covered in MU as well, marked.

Last updated 12:13 PM on 10/27/25
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai
Chat

No analytics yet

Send a link to your students to track their progress

97 Terms

1
New cards

(a+b)2(a+b)²

a2+b2+2aba²+b²+2ab

2
New cards

(a−b)2(a-b)²

a2+b2−2aba²+b²-2ab

3
New cards

a2+b2+2aba²+b²+2ab

(a+b)2(a+b)²

4
New cards

a2+b2−2aba²+b²-2ab

(a−b)2(a-b)²

5
New cards

(a+b)(a−b)(a+b)(a-b)

a2−b2a²-b²

6
New cards

a2−b2a²-b²

(a+b)(a−b)(a+b)(a-b)

7
New cards

amna^{m^n}

amna^{m^n}

8
New cards

(am)n(a^m)^n

amna^{mn}

9
New cards

(Σa)2(\Sigma a)²

Σ(a2)+2Σ(a1a2)\Sigma(a²)+2\Sigma(a_1a_2)

10
New cards

Σ(a2)+2Σ(a1a2)\Sigma(a²)+2\Sigma(a_1a_2)

(Σa)2(\Sigma a)²

11
New cards

Σa1a2\Sigma a_1a_2

(Σa)2−Σ(a2)2\dfrac{(\Sigma a)²-\Sigma (a²)}{2} 

12
New cards

(Σa)2−Σ(a2)2\dfrac{(\Sigma a)²-\Sigma (a²)}{2} 

Σa1a2\Sigma a_1a_2

13
New cards

Σa1a2=(Σa)2−Σ(a2)2\Sigma a_1a_2 = \dfrac{(\Sigma a)²-\Sigma (a²)}{2}

How is this derived?

By using identities like (a+b)2(a+b)² and (a+b+c)2(a+b+c)².

14
New cards

(1+a)(1+a2)(1+a4)(1+a8)…(1+an)(1+a)(1+a²)(1+a^4)(1+a^8)…(1+a^n)

1−a2n1−a\dfrac{1-a^{2n}}{1-a}

15
New cards

1−a2n1−a\dfrac{1-a^{2n}}{1-a}

(1+a)(1+a2)(1+a4)(1+a8)…(1+an)(1+a)(1+a²)(1+a^4)(1+a^8)…(1+a^n)

16
New cards

1−a2n1−a=(1+a)(1+a2)(1+a4)(1+a8)…(1+an)\dfrac{1-a^{2n}}{1-a}=(1+a)(1+a²)(1+a^4)(1+a^8)…(1+a^n)

How is this derived?

Multiple and divide RHS by (1−a)(1-a), then you use (a+b)(a−b)=a2−b2)(a+b)(a-b)=a²-b²) to cancel out all the consecutive terms.

17
New cards

(a+b+c)2(a+b+c)²

a2+b2+c2+2(ab+bc+ca)a²+b²+c²+2(ab+bc+ca)

18
New cards

a2+b2+c2+2(ab+bc+ca)a²+b²+c²+2(ab+bc+ca)

(a+b+c)2(a+b+c)²

19
New cards

(a+b+c+d)2(a+b+c+d)²

a2+b2+c2+d2+2(ab+ac+ad+bc+bd+cd)a²+b²+c²+d²+2(ab + ac + ad + bc + bd + cd)

20
New cards

(a+b)3(a+b)³

a3+b3+3ab(a+b)a³+b³+3ab(a+b)

21
New cards

a3+b3+3ab(a+b)a³+b³+3ab(a+b)

(a+b)3(a+b)³

22
New cards

a2+b2+c2+d2+2(ab+ac+ad+bc+bd+cd)a²+b²+c²+d²+2(ab + ac + ad + bc + bd + cd)

(a+b+c+d)2(a+b+c+d)²

23
New cards

a3+b3a³+b³

give both forms of this.

(a+b)3−3ab(a+b)(a+b)³-3ab(a+b)

(a+b)(a2+b2−ab)(a+b)(a²+b²-ab)

24
New cards

(a+b)3−3ab(a+b)(a+b)³-3ab(a+b)

a3+b3a³+b³

25
New cards

(a+b)(a2+b2−ab)(a+b)(a²+b²-ab)

a3+b3a³+b³

26
New cards

(a−b)3(a-b)³

a3−b3−3ab(a−b)a³-b³-3ab(a-b)

27
New cards

a3−b3−3ab(a−b)a³-b³-3ab(a-b)

(a−b)3(a-b)³

28
New cards

a3−b3a³-b³

give both forms

(a−b)3+3ab(a−b)(a-b)³+3ab(a-b)

(a−b)(a2+b2+ab)(a-b)(a²+b²+ab)

29
New cards

(a−b)(a2+b2+ab)(a-b)(a²+b²+ab)

a3−b3a³-b³

30
New cards

(a−b)3+3ab(a−b)(a-b)³+3ab(a-b)

a3−b3a³-b³

31
New cards

a2−ab+b2a²-ab+b²

Give all 3 forms

(a+b)2−3ab(a+b)²-3ab

(a−b)2+ab(a-b)²+ab

a3+b3(a+b)\dfrac{a³+b³}{(a+b)}

32
New cards

a3+b3(a+b)\dfrac{a³+b³}{(a+b)}

a2−ab+b2a²-ab+b²

33
New cards

a2+ab+b2a²+ab+b²

give all 3 forms

(a+b)2−ab(a+b)²-ab

(a−b)2+3ab(a-b)²+3ab

a3−b3a−b\dfrac{a³-b³}{a-b}

34
New cards

a3−b3a−b\dfrac{a³-b³}{a-b}

a2+ab+b2a²+ab+b²

35
New cards

a4−b4a^4-b^4

(a2+b2)(a2−b2)(a²+b²)(a²-b²)

36
New cards

a4+b4a^4+b^4

(a2+b2)2−2a2b2(a²+b²)²-2a²b²

37
New cards

a2+b2a²+b²

(a+b)2−2ab(a+b)²-2ab

38
New cards

a4+4b4a^4+4b^4

(a2+2b2−2ab)(a2+2b2+2ab)(a²+2b²-2ab)(a²+2b²+2ab)

derive simply and simplify

39
New cards

a4+a2+1a^4+a²+1

(a2+a+1)(a2−a+1)(a²+a+1)(a²-a+1)

40
New cards

(a2+a+1)(a2−a+1)(a²+a+1)(a²-a+1)

a4+a2+1a^4+a²+1

41
New cards

a8+a4+1a^8+a^4+1

(a4+a2+1)(a4−a2+1)(a^4+a²+1)(a^4-a²+1)

42
New cards

(a4+a2+1)(a4−a2+1)(a^4+a²+1)(a^4-a²+1)

a8+a4+1a^8+a^4+1

43
New cards

ab+bc+caab+bc+ca

(1a+1b+1c)abc\Big(\dfrac1a+\dfrac1b+\dfrac1c\Big)abc

44
New cards

(1a+1b+1c)abc\Big(\dfrac1a+\dfrac1b+\dfrac1c\Big)abc

ab+bc+caab+bc+ca

45
New cards

a2+b2+c2a²+b²+c²

(a+b+c)2−2(ab+bc+ca)(a+b+c)²-2(ab+bc+ca)

46
New cards

(a+b+c)2−2(ab+bc+ca)(a+b+c)²-2(ab+bc+ca)

a2+b2+c2a²+b²+c²

47
New cards

a3+b3+c3a³+b³+c³

(a+b+c)(a2+b2+c2−ab−bc−ca)+3abc(a+b+c)(a²+b²+c²-ab-bc-ca) + 3abc

48
New cards

(a+b+c)(a2+b2+c2−ab−bc−ca)+3abc(a+b+c)(a²+b²+c²-ab-bc-ca) + 3abc

a3+b3+c3a³+b³+c³

49
New cards

If a+b+c=0a+b+c=0, what is a3+b3+c3=a³+b³+c³=?

a3+b3+c3=3abca³+b³+c³=3abc

50
New cards

if  a3+b3+c3=3abca³+b³+c³=3abc, then what can you infer? (2 things)

either a+b+c=0a+b+c=0

or a=b=ca=b=c

51
New cards

a2+b2+c2−ab−bc−caa²+b²+c²-ab-bc-ca

Give all 3 forms of this.

=12[(a−b)2+(b−c)2+(c−a)2]=\dfrac{1}{2}[(a-b)²+(b-c)²+(c-a)²]

=(a+b+c)2−3(ab+bc+ca)=(a+b+c)²-3(ab+bc+ca)

=(a+b+c)3−3abca+b+c=\dfrac{(a+b+c)³-3abc}{a+b+c}

52
New cards

if a2+b2+c2−ab−bc−ca=0a²+b²+c²-ab-bc-ca=0, what can you infer (2 things)?

that a3+b3+c3=3abca³+b³+c³=3abc

and (a−b)2+(b−c)2+(c−a)2=0(a-b)²+(b-c)²+(c-a)²=0 which means a=b=ca=b=c

53
New cards

if a2+b2+c2=0a²+b²+c²=0, what can you infer?

a=b=c=0a=b=c=0

54
New cards

(a2−b2)3+(b2−c2)3+(c2−a2)3=?(a²-b²)³+(b²-c²)³+(c²-a²)³=?

How do you derive this?

3(a2−b2)(b2−c2)(c2−a2)3\left(a^2-b^2\right)\left(b^2-c^2\right)\left(c^2-a^2\right)

This is like X3+Y3+Z3X³+Y³+Z³.

Since X+Y+Z=0X+Y+Z=0, then X3+Y3+Z3=3XYZX³+Y³+Z³=3XYZ.

55
New cards

What can you infer from (x−a)2+(y−b)2+(z−c)3=0(x-a)²+(y-b)²+(z-c)³=0?

x=a,y=b,z=cx=a,y=b,z=c

56
New cards

What can you infer from (x−a)2+(x−b)2+(x−c)3=0(x-a)²+(x-b)²+(x-c)³=0?

a=b=ca=b=c

if not, the equation cannot exist

57
New cards

abc+(ab+bc+ca)+(a+b+c)+1abc+(ab+bc+ca)+(a+b+c)+1

(a+1)(b+1)(c+1)(a+1)(b+1)(c+1)

58
New cards

(a+1)(b+1)(c+1)(a+1)(b+1)(c+1)

abc+(ab+bc+ca)+(a+b+c)+1abc+(ab+bc+ca)+(a+b+c)+1

59
New cards

abcd+(a+b+c+d)+(ab+ac+ad+bc+bd+cd)+(abc+abd+acd+bcd)+1abcd+(a+b+c+d)+(ab+ac+ad+bc+bd+cd)+(abc+abd+acd+bcd)+1

(a+1)(b+1)(c+1)(d+1)(a+1)(b+1)(c+1)(d+1)

60
New cards

(a1+1)(a2+1)(a3+1)+…+(an+1)(a_1+1)(a_2+1)(a_3+1)+…+(a_n+1)

1+Σa1+Σ(a1a2)+Σ(a1a2a3)+…+(a1a2a3…an)1 + \Sigma a_1 +\Sigma (a_1a_2)+\Sigma (a_1a_2a_3)+…+(a_1a_2a_3…a_n)

61
New cards

1+Σa1+Σ(a1a2)+Σ(a1a2a3)+…+(a1a2a3…an)1 + \Sigma a_1 +\Sigma (a_1a_2)+\Sigma (a_1a_2a_3)+…+(a_1a_2a_3…a_n)

(a1+1)(a2+1)(a3+1)+…+(an+1)(a_1+1)(a_2+1)(a_3+1)+…+(a_n+1)

62
New cards

(a+b+c)3(a+b+c)³

a3+b3+c3+3(a+b)(b+c)(c+a)a³+b³+c³+3(a+b)(b+c)(c+a)

63
New cards

a3+b3+c3+3(a+b)(b+c)(c+a)a³+b³+c³+3(a+b)(b+c)(c+a)

(a+b+c)3(a+b+c)³

64
New cards

(a+b+c)3=a3+b3+c3+3(a+b)(b+c)(c+a)(a+b+c)³=a³+b³+c³+3(a+b)(b+c)(c+a)

How do you derive this?

consider X=a+bX=a+b and Y=cY=c and solve (X+Y)3(X+Y)³.

65
New cards

(a−b+c+d)(a+b−c+d)(a+b+c−d)(b+c+d−a)(a-b+c+d)(a+b-c+d)(a+b+c-d)(b+c+d-a)

How do you approach this?

(a+b+c+d−2b)(a+b+c+d−2c)(a+b+d+c−2d)(a+b+c+d−2a)(a+b+c+d-2b)(a+b+c+d-2c)(a+b+d+c-2d)(a+b+c+d-2a)

Let a+b+c+d=x)a+b+c+d=x)

then,

=(x−2a)(x−2b)(x−2c)(x−2d)=(x-2a)(x-2b)(x-2c)(x-2d).

66
New cards

Not from MU

Every prime number greater than 3 is in the form of _____, but the converse need not be true.

6k±16k\pm1

67
New cards

Not from MU

When given a question where a variable is a prime number, what can you do? Just like what is the first thing that should pop into your head?

Can factorise it, and the factors are always going to be 1 and itself.

68
New cards

Not from MU

If f(x)f(x)  is divided by ax−bax-b . what form will the remainder be in?

mx+nmx+n

69
New cards
<p><strong>Not from MU</strong></p><p>How would you approach this question?</p>

Not from MU

How would you approach this question?

Group some terms, it looks like componendo dividendo, apply that.

70
New cards

Not from MU

What is the relation between ∣a+b∣|a+b| and ∣a∣+∣b∣|a|+|b|?

∣a+b∣≤∣a∣+∣b∣|a+b|\le|a|+|b|

71
New cards

Not from MU

What is the relation between ∣a−b∣|a-b| and ∣a∣−∣b∣|a|-|b| ?

∣a−b∣≥∣a∣−∣b∣|a-b|\ge|a|-|b|

72
New cards

Not from MU

What are the limitations of logarithms? log⁡aN\log_aN

(three limitations)

  1. a>0a>0

  2. N>0N>0

  3. a≠1a\ne 1


73
New cards

What is log⁡ambn\log_{a^m}b^n ?

nmlog⁡ab\dfrac{n}{m}\log_ab

74
New cards

What is log⁡xa+log⁡xb\log_x a + \log_x b?

log⁡xab\log_x ab  

75
New cards

What is log⁡xa−log⁡xb\log_x a - \log_x b ?

log⁡xab\log_x \dfrac{a}{b} 

76
New cards

What is log⁡aa=\log_aa=?

11

77
New cards

What is log⁡a1=\log_a1=?

00

78
New cards

What is log⁡ablog⁡ac=\dfrac{\log_ab}{\log_ac}=?

log⁡cb\log_cb

79
New cards

What is alog⁡ac=a^{\log_ac}=?

cc

80
New cards

What is alog⁡bc=a^{\log_bc}=?

clog⁡bac^{\log_ba} 

81
New cards

If in log⁡ab\log_ab, both aa and bb are on the same side of 11 (on the number line), then will the value of log be negative or positive?

positive

82
New cards

If in log⁡ab\log_ab, both aa and bb are on different sides of 11 (on the number line), then will the value of log be negative or positive?

negative

83
New cards

Under what conditions will log⁡ab>1\log_ab>1 be true?

if b>ab>a and a>1a>1.

84
New cards

Not from MU

What is log⁡ea\log_ea in terms of log⁡\log to the base 1010?

log⁡ea=2.303×log⁡10a\log_ea=2.303\times\log_{10}a

85
New cards

Not from MU

What is 1log⁡ab\dfrac{1}{\log_ab}?

log⁡ba\log_ba 

86
New cards

Not from MU

What is log⁡10a\log_{10}a in terms of log⁡\log to the base ee?

log⁡10a=0.434×log⁡ea\log_{10}a=0.434\times\log_ea 

87
New cards

Not from MU

What does the graph for y=log⁡axy=\log_ax look like when a>1a>1?

knowt flashcard image
88
New cards

Not from MU

What does the graph for y=log⁡axy=\log_ax look like when a<1a<1?

knowt flashcard image
89
New cards

Not from MU

If log⁡ax<log⁡ay\log_ax < \log_ay, when is x>yx>y? When is x<yx<y?

x<yx<y when a>1a>1

x>yx>y when a<1a<1

90
New cards

Not from MU

when is x+1x≥2x+\dfrac1x\ge2?

when xx is a positive real number

91
New cards

Not from MU

When is x+1x≤2x+\dfrac1x\le2?

when xx is a negativ real number

92
New cards

Not from MU

What is the approximate value of log⁡102\log_{10}2?

0.30100.3010

93
New cards

Not from MU

What is the approximate value of log⁡103\log_{10}3?

0.47710.4771

94
New cards

Not from MU

What is the approximate value of log⁡e2\log_{e}2?

0.6930.693

95
New cards

Not from MU

What is the approximate value of log⁡e10\log_{e}10?

2.3032.303

96
New cards

Not from MU

if log⁡ax>p\log_ax>p, what happens when a>1a>1?

x>apx>a^p

97
New cards

Not from MU

if log⁡ax>p\log_ax>p, what happens when 0<a<10<a<1?

0<x<ap0<x<a^p