features of arene compounds
contain a benzene ring
high melting points as a result of the benzene ring
low boiling points as they’re non-polar molecules
cannot be dissolved in water
structure of benzene
ring of delocalised electrons
outer electron from the p-orbital is delocalised in the centre to form the central ring
this forms pi bonds
this makes benzene very stable compared to other molecules of a similar size
thermodynamic stability of benzene
enthalpy of hydrogenation of cyclohexane: -119kJmol-1
with one double bond
so theoretically benzene should be triple that, at -357kJmol-1
however it is only -208kJmol-1
therefore benzene is more thermodynamically stable and has a different structure to that of cyclohexane
bond lengths in benzene
all bond lengths between carbon atoms in benzene are the same
if the cyclohexatriene structure was correct, three bond lengths would be shorter than the other three as they would be double bonds, causing distortion
why is benzene resistant to electrophilic addition reactions, eg bromination?
because addition mechanisms cause permanent disruption to the delocalised system in the centre of the benzene ring and its
substitution mechanisms cause momentary disruption, after which the ring is restored
electrophilic substitution of benzene
high electron density in the delocalised ring of benzene makes it susceptibe to attack from electrophiles
reagents in nitration of benzene
concentrated nitric acid to produce the NO2+ ion
concentrated sulfuric acid to act as the catalyst, so it not used up in the reaction
conditions in nitration of benzene
reflux at 55*
not higher or it will become explosive!
what is the electrophile in nitration of benzene?
nitronium ion
NO2+
generated in an acid base reaction
2H2SO4 + HNO3 ⇌ 2HSO4- + H3O+ + NO2+
use of nitration of benzene reaction
formation of dyes and explosives
draw a nitration of benzene mechanism
reagents in halogenation of benzene
chlorine
halogen carrier
conditions of halogenation of benzene
reflux in the presence of a catalyst (AlCl3, FeBr3)
anhydrous conditions
chlorine is nonpolar and not a good electrophile so a halogen carrier needs to polarise the hydrogen
draw a halogenation of benzene reaction mechanism
what is the electrophile in the halogenation of benzene and how is it generated?
the halogen
eg Br+ in FeBr3 of Cl- in AlCl3
eg for FeBr3
iron (III) bromide polarises the Br2 molecule, making it easier for the bromine bond to break so that the bromine atom can act as an electrophil
what occurs during a friedel-crafts acylation reaction
delocalised electron ring in benzene acts as a nucleophile, leading to nucleophilic attack on acyl chlorides
conditions required for a fridel-crafts acylation reaction
reflux at 50*
dry inert solvent (dry ether)
what must be produced for a friedel-crafts acylation reaction to occur and how is it done?
a reactive intermediate must be produced from a reaction between the acyl chloride and aluminium chloride catalyst
R-COCl + AlCl3 → R-CO+ + AlCl4-
how does a friedel-crafts acylation reaction progress?
reactive intermediate produced previously is attacked by the benzene ring of delocalised electrons
the H+ ion is removed from the ring and reacts with the AlCl4- ion to reform the AlCl3
hence AlCl3 is a catalyst
produces a phenylketone (benzene being the phenyl group)
what is the electrophile during fridel-crafts alkylation and how is it formed?
a carbocation
C2H5Cl + AlCl3 → AlCl4- + C2H5+
conditions required for a fridel-crafts alkylation reaction
room temperature
dry inert solvent (dry ether)
reagents required for a fridel-crafts acylation reaction?
acyl chloride and anhydrous AlCl3
reagents required for a fridel-crafts alkylation reaction
anhydrous AlCl3
haloalkane
overall equation for a fridel-crafts alkylation reaction
C6H6 + C2H5Cl → C6H5C2H6 + HCl
draw the mechanism for a fridel-crafts alkylation reaction
draw the mechanism for a fridel-crafts acylation reaction
phenol reaction with bromine water
reacts via multiple substitutions to produce 2,4,6-tribromophenol
white precipitate
distinctly smells of antiseptic
decolourises bromine water
benzene reaction with bromine water
cannot react with bromine water
due to increased reactivity of phenol because of the delocalised lone pair of electrons on the oxygen atom
therefore electron density is greater
less stable
more susceptible to attack from electrophiles compared to benzene
combustion of benzene
reacts with oxygen to produce CO2 and H2O
produces a smoky flame due to the high C content of benzene
2C6H6 + 15O2 → 12CO2 + 6H2O
phenol + Br2 →
2,4,6-tribromophenol + HBr
white ppt formed
no catalyst
phenol + NaOH
- H+ as NaOH protonates
sodium phenate + H2O produced
phenol + CH3COCl
forms an ester
phenylethanoate + HCl
why are quaternary ammonium salts not amines?
do NOT possess a lone pair of electrons on the N
hydrogen bonding in amine molecules
weaker than in alcohols, though there is some
NOT in tertiary amines as there is no H to form any
are amines bronsted lowry proton acceptors or donators?
weak acceptors (bases)
can act in this way due to the lone pair on the N
draw a reaction between a secondary amine + water
order of base strength of amines
tertiary > secondary > primary > NH3 > aromatic amine
explain the order of base strength of amine
the higher the electron density of the lone pair in the N, the better it is able to accept the H+, so the base is stronger
primary, secondary and tertiary amines compared to ammonia
the more alkyl groups that are substituted onto the N in place of H, the more electron density is pushed onto the N atom
this is because of the inductive effect of alkyl groups compared to H atoms
the more alkyl groups, the higher the electron density of the lone pair on the N
hence it is a stronger base
ammonia compared to aromatic amines
lone pair on the N is partially delocalised into the benzene ring
leads to a reduction in the electron density on the N atom
weaker base strength
primary aliphatic amine (butylamine) reaction with acid
forms an ammonium salt
amine acts as a base and accepts a proton to form a quaternary ammonium salt
primary aliphatic amines (butlyamine) reactions with ethanoyl chloride
N-subsitituted amide is produced
primary aliphatic amines (butlyamine) reactions with halogenoalkanes
H’s on the N are successively replaced by the R group from the haloalkanes
forms a secondary, tertiary then quaternary salt
primary aliphatic amines (butlyamine) reactions with copper (II) ions
copper ions react with the water to form a copper aqua ion
amine acts as a base to accept the protons from the water ligands
blue precipitate of Cu(OH)2(H2O)4 formed
ammonium salt formed
primary aliphatic amine (butylamine) reactions with ethanoyl chloride/acid anhydride
first produces an amide and a molecule of HCl/carboxylic acid
a second molecule of the amine reacts with the HCl/carboxylic acid to form a salt
via nucleophilic addition for acyl chlorides
what are the two ways of preparing a primary aliphatic amine
from a haloalkane
by the reduction of nitriles
producing a primary aliphatic amine from a haloalkane
haloalkane reacted with an excess of conc. ammonia dissolved in ethanol at pressure in a sealed container
via nucleophilic substitution
not usually used as the amine can react further with the haloalkane to produce secondary and tertiary
problem minimised by using an excess of conc. ammonia
still a problem due to low yield
production of aliphatic primary amines by the reductions of nitriles
only froms one amine rather than a mixture
two steps
adds a C to the chain
formation of a nirtile from a haloalkane
R-X + KCN → (warm ethanol) R - :C=-N + KX
reduction of the nirtile to form an amine
R-C=_N + 4[H] → (LiAlH4 in ethoxyethane) R-CH2-NH2
OR
R-C=_N + 2H2 → (Ni catalyst in heat) R-CH2-NH2
equations for the production of ethylamine
CH3-BR + KCN → CH3-C=_N + KBr
CH3-C=_N + 4[H] → CH3-CH2-NH2
two ways to prepare an amide
carboxylic acid + amine → amide + H2O
acyl chloride + amine → amide (or N-substituted amide) + HCl
how are polyamides formed
condensation polymerisation reaction
water is released
dicarboxylic acid + diamine
dicarboxylic acid + diol
polyester formed, water released
eg ethane-1,2-diol + benzene-1,4-dicarboxylic acid makes terylene/PET
draw the monomer structure of an amino acid
draw the polymer structure of an amino acid
draw the repeating unit of an amino acid
isoelectric point
the pH at which the amino acid becomes positively and negatively charged, so the net charge is zero
when a zwitterion forms
zwitterion in acidic conditions (pH below 7)
COO- group is more likely to accept a hydrogen ion, producing a positive end to the molecule
zwitterion in basic conditions
the hydrogen ion in the NH3 group is more likely to be lose, producing a negative end to the molecule
amino acid in neutral pH
is in a reversible reaction with a zwitterion, where the H on the OH joins the NH2 group to form NH3+
amino acid in acidic conditions
protonated
NH2 group becomes NH3
amino acid in alkaline conditions
deprotonated
any Hs bonded to a COO- group are lost
what makes an amino acid polar
the OH group on the COOH
how are aromatic amines produced
reduction of nitrobenzene using conc. HCl
tin catalyst
chirality of amino acids
all amino acids are chiral except glycine, whose R group is just H
they are therefore optically active, so a solution of amino acids rotates plane polarised monochromatic light
reactions of the NH2 group on the amino acid
protonated by acids
acylation w/acid chloride or acid anhydride
nucleophilic substitution w/ haloalkanes
reactions of the COOH group of an amino acid
deprotonated by bases
esterification with alcohols and acid catalyst
chromatography
proteins are a form of condensation polymer
sequence of amino acids joined by peptide bonds -C=ONH-
hydrolysed into constituent amino acids
separated an identified by thin layer chromatography
ninhydrin produces purple dots