11.3 volume and temperature of an ideal gas

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12 Terms

1
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amount of gas measured in

n/m

2
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increase in temperature

increase in collision frequency and collision energy, increase in volume

3
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decrease temperature

decrease collision frequency and collision energy, decreased volume

4
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temperature and volume have a

direct relationship at constant n/m and P

5
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convert °C to K

add 273.15

6
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convert K to °C

subtract 273.15

7
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charles law

volume is directly proportional to the temperature of an ideal gas as long as the temperature is in Kelvin and constant number of moles per mass

8
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charles law derived equation

V1 / V2 = T1 / T2 (T must be in Kelvin)

9
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gay-lussacs law

pressure is directly proportional to temperature (in Kelvin) as constant # of moles per mass and volume

10
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gay-lussacs law derived equation

P1 / P2 = T1 / T2 (T must be in Kelvin)

11
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standard conditions

  • PSTP = 101.3 kPa

  • TSTP = 0.00000 degrees C or 273.15 K

12
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standard ambient T and P

  • PSATP = 100.0 kPa

  • TSATP = 25.00 degrees C = 298.15 kPa