Analysis Final Exam

0.0(0)
studied byStudied by 0 people
0.0(0)
full-widthCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/86

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

87 Terms

1
New cards

Axiom of Completeness

Every nonempty subset of R that is bounded above has a supremum.

2
New cards

Upper Bound/Lower Bound

Let A subset R. b∈R is an Upper Bound for A if b≥a for all a in A. l in R is a Lower Bound for A if l≤a for all a in A

3
New cards

Supremum

S is the least upper bound or supremum of A if

(i) S is an upper bound for A

(ii)  If b is an upper bound for A then s≤b

4
New cards

Infimum

L is the greatest lower bound or infimum of A if

(i) L is a lower bound for A

(ii) If m is a lower bound for A then m≤L

5
New cards

m is the maximum of A 

if m is an element and upper bound i.e., m is in A and m≥a for all a in A

6
New cards

m is the minimum of A

if m is an element and lower bound i.e., m is in A and m≤a for all a in A

7
New cards

A subset R is dense in R

If for all a,b ∈ R with a < b there exists x ∈ A such that a<x<b

8
New cards

A has the same cardinality as B written A ~ B if there exists

f: A —> B that is bijective

9
New cards

A is countable

if A ~ Natural Numbers

10
New cards

A is uncountable

if A is infinite and not countable

11
New cards

Convergence of a Series

Let (bn) be a sequence. An infinite series is a formal expression of the form

bn = b1 + b2 + b3 + b4 + b5 + · · ·  from n=1 to infinity.

We define the corresponding sequence of partial sums (sm) by s_m =b1 +b2 +b3 +···+b_m, and say that the series (n=1 to infinity) bn converges to B if the sequence (sm) converges to B.

In this case, we write series (from n=1 to infinity) bn = B.

12
New cards

Bounded

A sequence (xn) is bounded if there exists a number M > 0 such that |xn|≤M for all n∈N

13
New cards

Subsequence of (a_n)

Let (an) be a sequence of real numbers and let n1 < n2 < n3 < n4 < n5 < . . . be an increasing sequence of natural numbers. Then the sequence (an1,an2,an3,an4,an5,...) is called a subsequence of (a_n_, denoted by (a_n_k), where k ∈ N indexes the subsequence.

14
New cards

Cauchy Sequence

for every ε > 0, there exists an N ∈ N such that whenever m,n ≥ N it follows that |am − an| < ε

15
New cards

Triangle Inequality

Let a,b in Real Numbers. Then |a+b|≤|a|+|b|

16
New cards

Triangle Inequality Properties

(i) |ab| = |a||b|

(ii) |a+b| ≤ |a| + |b|

(iii) |a-b| ≤ |a-c| + |b-c|

(iv) ||a| - |b|| ≤ |a-b|

17
New cards

Sup Epsilon Criterion

If s an upper bound, s=sup(A) if and only if for all epsilon>0, there exists an a in A s.t. s-epsilon<a.

18
New cards

Nested Interval Property

For each n ∈ N, assume we are given a closed interval In =[an,bn]={x∈R : an ≤x≤bn}. Assume also that each In contains In+1. Then, the resulting nested sequence of closed intervals has a non-empty intersection.

19
New cards

Archimedian Principle

(i) Given any number x ∈ R, there exists an n ∈ N satisfying n > x.

(ii) Given any real number y > 0, there exists an n ∈ N satisfying 1/n < y.

20
New cards

Subsets of countable sets are…

countable or finite

21
New cards

A countable union of countable sets…

is countable

22
New cards

Cantor’s Theorem

Let there be a set A. Then there exists no function f: A —> P(A) which is surjective.

23
New cards

Uniqueness of Limits

The limit of a sequence, when it exists, must be unique

24
New cards

Algebraic Limit Theorem

Let lim an = a, and lim bn = b. Then,

·      (i) lim(can) = ca, for all c ∈ R

·      (ii) lim(an +bn) = a+b;

·      (iii) lim(an*bn) = ab

·      (iv) lim(an/bn) = a/b, provided b ≠ 0.

25
New cards

Bolzano-Weierstrass Theorem

Every bounded sequence contains a convergent subsequence.

26
New cards

A series (an) converges implies

(an) → 0

27
New cards

Comparison Test

Assume (ak) and (bk) are sequences satisfying 0≤ak ≤bk for all k∈N.

·      (i) If sum(from k=1 to infinity) bk converges, then sum (from k=1 to infinity) ak converges.

·      (ii) If sum (from k=1 to infinity) ak diverges, then sum (from k=1 to infinity) bk diverges.

28
New cards

Open Set

A set O ⊆ R is open if for all points a ∈ O there exists an ε-neighborhood Vε(a) ⊆ O.

29
New cards

Limit Point

A point x is a limit point of a set A if every ε-neighborhood Vε(x) of x intersects the set A at some point other than x.

30
New cards

Closed Set

A set F ⊆ R is closed if it contains its limit points.

31
New cards

Closure

Given a set A ⊆ R, let L be the set of all limit points of A. The closure of A is defined to be A = A ∪ L.

32
New cards

Compact

A set K ⊆ R is compact if every sequence in K has a subsequence that converges to a limit that is also in K.

33
New cards

Open Cover

Let A ⊆ R. An open cover for A is a (possibly infinite) collection of open sets {Oλ : λ ∈ Λ} whose union contains the set A; that is, A subset U λ in Λ O_λ.

34
New cards

Finite Subcover

A finite subcover is a finite subcollection of open sets from the original open cover whose union still manages to completely contain A.

35
New cards

Functional Limit

Let f : A → R, and let c be a limit point of the domain A. We say that lim x→c f(x) = L provided that, for all ε > 0, there exists a δ > 0 such that whenever 0 < |x − c| < δ (and x ∈ A) it follows that |f (x) − L| < ε.

36
New cards

Continuity

A function f : A → R is continuous at a point c∈A if, for all ε>0, there exists a δ>0 such that whenever |x−c|<δ (and x ∈ A) it follows that |f(x) − f(c)| < ε.

37
New cards

Uniform Continuity

A function f : A → R is uniformly continuous on A if for every ε > 0 there exists a δ > 0 such that for all x, y ∈ A, |x−y|<δ implies |f(x)−f(y)|<ε.

38
New cards

Theorems of Collection of Open Sets

(i) The union of an arbitrary collection of open sets is open. (ii) The intersection of a finite collection of open sets is open.

39
New cards

Theorem for Collection of Closed Sets

(i) The union of a finite collection of closed sets is closed.

(ii) The intersection of an arbitrary collection of closed sets is closed.

40
New cards

Limit Point IFF

A point x is a limit point of a set A if and only if x = lim(a_n) for some sequence (an) contained in A satisfies an ≠ x for all n ∈ N.

41
New cards

Closed IFF

A set F ⊆ R is closed if and only if every Cauchy sequence contained in F has a limit that is also an element of F.

42
New cards

Complement of a Set (Open/Closed)

A set O is open if and only if O^c is closed. Likewise, a set F is closed if and only if F^c is open.

43
New cards

Heine-Borel Theorem

Let K be a subset of R. All of the following statements are equivalent:

(i) K is compact.
(ii) K is closed and bounded

(iii) Every open cover for K has a finite subcover.

44
New cards

Nested Compact Set Property

K1 ⊇K2 ⊇K3 ⊇K4 ⊇··· is a nested sequence of nonempty compact sets, then the intersection (from n=1 to Kn) is not empty.

45
New cards

Sequential Criterion for Functional Limits

Given a function f : A → R and a limit point c of A, the following two statements are equivalent:

(i) lim x→c f(x) = L

(ii) For all sequences (xn) ⊆ A satisfying xn ≠ c and (xn) → c, it follows that f(xn) → L.

46
New cards

Divergence Criterion for Functional Limits

Let f be a function defined on A, and let c be a limit point of A. If there exist two sequences (xn) and (yn) in A with xn ≠ c and yn ≠ c and

lim xn = lim yn = c but limf(xn) ≠ limf(yn),

then we can conclude that the functional limit lim x→c f(x) does not exist.

47
New cards

Algebraic Limit Theorem for Functional Limits

Let f and g be functions defined on a domain A ⊆ R, and assume lim x→c f (x) = L and lim x→c g(x) = M for some limit point c of A. Then,

(i) lim x→c kf(x)=kL for all k∈R,

(ii) lim x→c [f(x)+g(x)]=L+M,

(iii) lim x→c [f(x)g(x)] = LM, and

(iv) lim x→c f(x)/g(x) = L/M, provided M ≠ 0.

48
New cards

Compositions of continuous functions…

are continuous

49
New cards

Preservation of Compact Sets

Let f : A → R be continuous on A. If K ⊆ A is compact, then f(K) is compact as well.

50
New cards

Extreme Value Theorem

If f : K → R is continuous on a compact set K ⊆ R, then f attains a maximum and minimum value. In other words, there exist x0,x1 ∈ K such that f(x0) ≤ f(x) ≤ f(x1) for all x∈K.

51
New cards

Sequential Criterion for Absence of Uniform Continuity

A function f : A → R fails to be uniformly continuous on A if and only if there exists a particular ε0 > 0 and two sequences (xn) and (yn) in A satisfying |xn −yn|→0 but |f(xn)−f(yn)|≥ε0.

52
New cards

Uniform Continuity on Compact Sets

A function that is continuous on a compact set K is uniformly continuous on K.

53
New cards

Intermediate Value Theorem

Let f : [a,b] → R be continuous. If L is a real number satisfying f(a) < L < f(b) or f(a) > L > f(b), then there exists a point c ∈ (a, b) where f(c) = L.

54
New cards

Intermediate Value Property

A function f has the intermediate value property on an interval [a,b] if for all x < y in [a,b] and all L between f(x) and f(y), it is always possible to find a point c ∈ (x,y) where f(c) = L.

55
New cards

Differentiability

Let g : A → R be a function defined on an interval A. Given c ∈ A, the derivative of g at c is defined by

g’( c ) = lim x→c g(x)-g(c) / x-c

56
New cards

Differentiability Implies Continuity

If a function f is differentiable over [a,b], it follows that f is continuous over taht same interval

57
New cards

Algebraic Differentiability Theorem

Let f and g be functions defined on an interval A, and assume both are differentiable at some point c ∈ A. Then,

(i) (f+g)’(c) = f’(c) + g’(c)

(ii) (kf)′(c) = kf′(c), for all k ∈ R

(iii) (fg)′(c) = f′(c)g(c) + f(c)g′(c)

(iv) (f/g)’(c) = g(c)f’(c) - f(c)g’(c) / [g(c)]² provided that g(c) ≠ 0.C

58
New cards

Chain Rule

Let f : A → R and g : B → R satisfy f(A) ⊆ B so that the composition g ◦ f is defined. If f is differentiable at c∈A and if g is differentiable a tf(c)∈B,then g◦f is differentiable at c with (g ◦ f)′(c) = g′(f(c)) · f′(c).

59
New cards

Interior Exterior Theorem

Let f be differentiable on an open interval (a, b). If f attains a maximum value at some point c ∈ (a, b) (i.e., f(c) ≥ f(x) for all x ∈ (a,b)), then f′(c) = 0. The same is true if f(c) is a minimum value.Darboux’s Theorem

60
New cards

Darboux’s Theorem

If f is differentiable on an interval [a,b], and if α satisfies f′(a) < α < f′(b) (or f′(a) > α > f′(b)), then there exists a point c ∈ (a, b) where f′(c) = α.

61
New cards

Rolle’s Theorem

Let f : [a, b] → R be continuous on [a, b] and differentiable on (a,b). If f(a) = f(b), then there exists a point c ∈ (a,b) where f′(c) = 0.Mean Value Theorem

62
New cards

Mean Value Thoeorem

If f : [a, b] → R is continuous on [a, b] and differentiable on (a, b), then there exists a point c ∈ (a, b) where f’(c)= f(b)-f(a) / b-a

63
New cards

Generalized Mean Value Theorem

If f and g are continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists a point c ∈ (a, b) where [f(b) − f(a)]g′(c) = [g(b) − g(a)]f′(c).

64
New cards

Differentiability and Constant

If g : A → R is differentiable on an interval A and satisfies g′(x) = 0 for all x ∈ A, then g(x) = k for some constant k ∈ R.

65
New cards

Diffferentiability and Constant (Addition)

If f and g are differentiable functions on an interval A and satisfy f′(x) = g′(x) for all x ∈ A, then f(x) = g(x) + k for some constant k ∈ R.

66
New cards

L’Hospital’s Rule: 0/0 case

Let f and g be continuous on an interval containing a, and assume f and g are differentiable on this interval with the possible exception of the point a. If f(a) = g(a) = 0 and g′(x)≠0 for all x≠a, then

lim x→a f’(x) / g’(x) = L implies lim x→a f(x) / g(x) = L.

67
New cards

L’Hopital’s Rule: Infty/Infty Case

Assume f and g are differentiable on (a, b) and that g′(x) ≠ 0 for all x ∈ (a, b). If lim x→a g(x) = infty (or −infty), then

lim x→a f’(x) / g’(x) = L implies lim x→a f(x) / g(x) = L.

68
New cards

Uniform Convergence

Let (fn) be a sequence of functions defined on a set A ⊆ R. Then, (fn) converges uniformly on A to a limit function f defined on A if, for every ε > 0, there exists an N ∈ N such that |fn(x)−f(x)|<ε whenever n≥N and x∈A.

69
New cards

Cauchy Criterion for Uniform Convergence

A sequence of functions (fn) defined on a set A ⊆ R converges uniformly on A if and only if for every ε > 0 there exists an N ∈ N such that |fn(x)−fm(x)| < ε whenever m, n ≥ N and x ∈ A.

70
New cards

Continuous Limit Theorem

Let (fn) be a sequence of functions defined on A ⊆ R that converges uniformly on A to a function f. If each fn is continuous at c ∈ A, then f is continuous at c.

71
New cards

Differentiable Limit Theorem

Let f_n → f pointwise on [a,b]. Assume f_n differentiable on [a,b] and (f_n’) → g uniformly on [a,b]. Then f is differentiable and f’=g on [a,b]

72
New cards

Strong Form of Differentiable Limit Theorem

Let (fn) be a sequence of differentiable functions on [a,b]. Assume (fn’) → g uniformly on [a,b]. Assume there exists an x0 in [a,b] s.t. (fn(x0)) converges. Then (fn) converges uniformly to an f in [a,b] s.t. f’=g.

73
New cards

Series Converges Pointwise

Let fn,f be functions on A subset R for all n in N. The (sum from n=1 to infty) fn(x) converges pointwise to f(x) if for all x0 in A, the (sum from n=1 to infty) fn(x0) converges to f(x0), i.e. the sequence of partial sums lim n→infty ((sum from n=1 to k) fk(x0)) = f(x0)

74
New cards

Services Converges Uniformly

The (sum from n=1 to infty) fn(x) converges uniformly to f(x) if the sequence of functions Sn(x)= (sum from k=1 to N) fk(x) converges uniformly on f(x) on A.

75
New cards

Term by Term Continuity Theorem

fn continuous on A subset R for all n in N. Then the (sum from n=1 to infinity) fn(x) → f(x) uniformly on A, f(x) is continuous.

76
New cards

Cauchy Criterion for Uniform Convergence of a Series

(sum from n=1 to infty) fn(x) converges uniformly on A subset R iff for all epsilon>0 there exists N in N s.t. n>m>=N, x in A implies |(sum from k=m+1 to n) fk(x)| < epsilon.

77
New cards

Weierstrass M-Test

Let fn function on A subset R for all n in N and Mn is an upper bound of fn(x) on A, |fn(x)| <= Mn for all x in A. Then the (sum from n=1 to infty) Mn converges implies (sum from n=1 to infty) fn converges uniformly on A.

78
New cards

Partition

A partition of [a,b] is a subset P of [a,b] s.t. a,b is an element of P. P = {a=x0,x1,x2…,xn=b} x_i < x_i+1

79
New cards

Definition of mk(f) and Mk(f)

If f is a bounded function on [a,b] and P is a partition of [a,b], define

mk(f) = mk = inf {f(x): x in [x_k-1,x_k]}

Mk(f) = Mk = sup {f(x): xin [x_k-1, x_k]}

80
New cards

Lower Sum

The Lower Sum of f w/ respect to P is L(f,P) = (sum from k=1 to N) m_k(x_k-x_k-1)

81
New cards

Upper Sum

The upper sum of f w.r.t. P is U(f,P)= (sum from k=1 to N) M_k(x_k - x_k-1)

82
New cards

Refinement

A refinement of a partition P is a partition Q s.t. P subset Q.

83
New cards

Upper and Lower Integral

Let Fancy P= {All partitions of [a,b]}

The upper integral of f on [a,b] is U(f)= inf{U(f,P), P in Fancy P}

The lower integral of f on [a,b] is L(f) = sup(L(f,P): P in Fancy P}

84
New cards

Riemann integral

Let f be bounded on [a,b]. f is riemann integrable on [a,b] if U(f)=L(f). If so, the integral of f over [a,b] is

integral (from a to b) f = U(f) = L(f)

85
New cards

Continuity + Intergrability Theorem

f continuous on [a,b] implies f is integrable on [a,b]

86
New cards

Pointwise Convergence (Sequence of Functions)

For each n ∈ N, let fn be a function defined on a set A ⊆ R. The sequence (fn) of functions converges pointwise on A to a function f if, for all x ∈ A, the sequence of real numbers fn(x) converges to f(x).

87
New cards

Uniform COnvergence (Sequence of Functions)

Let (fn) be a sequence of functions defined on a set A ⊆ R. Then, (fn) converges uniformly on A to a limit function f defined on A if, for every ε > 0, there exists an N ∈ N such that |fn(x)−f(x)|<ε whenevern≥N andx∈A.

Explore top flashcards

Shut Up
Updated 964d ago
flashcards Flashcards (65)
hbs 5.1
Updated 953d ago
flashcards Flashcards (61)
CSE111 - Indexes
Updated 385d ago
flashcards Flashcards (52)
The Knee
Updated 89d ago
flashcards Flashcards (33)
Shut Up
Updated 964d ago
flashcards Flashcards (65)
hbs 5.1
Updated 953d ago
flashcards Flashcards (61)
CSE111 - Indexes
Updated 385d ago
flashcards Flashcards (52)
The Knee
Updated 89d ago
flashcards Flashcards (33)