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Magnetic moment for a bar magnet
\overrightarrow{M}=m\overrightarrow{l}
m = magnetic pole strength
Magnetic moment for a current carrying loop
\overrightarrow{M}=NI\overrightarrow{A}
Torque experienced by a magnetic dipole
\overrightarrow{\tau}=\overrightarrow{M}✕\overrightarrow{B}=MB\sin\theta
M = magnetic moment
Torque experienced by a current carrying loop in a magnetic field
\overrightarrow{\tau}=NI\left(\overrightarrow{A}✕\overrightarrow{B}\right)=NIAB\sin\theta
“Torque is NIAB”
Energy stored in a dipole
U=-\overrightarrow{M}\cdot\overrightarrow{B}=MB\cos\theta
U=\Delta W
‘change in work done’
If area is halved, how does the pole strength of the dipole change
halved