Chapter 19: Electric Charges, Forces, and Fields

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62 Terms

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for lightning, you need…

  • electric charge (many electrons)

  • voltage (millions-billions of volts)

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charge is…

  • quantized

    • charge exists in integral multiple of a fundamental unit of charge, symbolized by e

    • quarks are an exception because they can exist in fractional charges

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Fundamental Charge

  • e = 1.6 x 10^-19 Coulombs (C)

  • the charge carried by a single proton (+e) or the negative charge of a single electron (-e)

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Electric charge is always…

  • conserved

    • charge is not created, only exchanged

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A positively charged atom has…

A negatively charged atom has…

  • more protons than electrons

  • more electrons than protons

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Charge Equation

  • q = ne

    • q: total charge

    • n: number of elementary charges

    • e: fundamental charge

  • measured in Coulombs

  • n = ±1, ±2, ±3, …

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A metallic object holds a charge of -3.8×10^-6 C.

  • What total number of electrons does this represent? (e = 1.6×10^-19 C is the magnitude of the electronic charge.)

  • How about 1 C of charge?

  • q = ne

  • n = q/e

  • n = -2.4×10^13 electrons

  • n = 0.6 electrons

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A defibrillator has a charge of 0.3 C. If the magnitude of the electronic charge is e = 1.6×10^-19 C, what is n?

  • q = ne

  • n = 1.8×10^18 electrons going to the heart

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Conductor

  • physical medium/object (copper wire or metallic object) that contains a sea of free electrons

  • allows electric current to flow easily through them in response to electric force

  • charges redistribute very easily

  • 10^(28)/m³ = 10^(22)/cm³

    • 10²⁸ electrons per cubic meter is the same density as 10²² electrons per cubic centimeter

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Do charges redistribute easily in conductors or insulators?

conductors

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Current

  • the flow of electric charge, typically measured in amperes (A). It represents the movement of electrons through a conductor.

  • need a wire, for example

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Insulator

  • not many free electrons

  • charges do not redistribute

  • ex: plastic, glass, rubber

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When a conductor is charged in a small region, the charge…

readily distributes itself over the entire surface of the material

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When insulators are charged by rubbing…

  • only the rubbed area becomes charged

  • there is no tendency for the charge to move into other regions of the material

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Semiconductor

  • characteristics between conductors and insulators

  • ex: silicon and germanium

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Initially, sphere A has a charge of -50e and sphere B has a charge of +20e. The spheres are made of conducting material and are identical in size. If the spheres then touch, what is the resulting charge on sphere A?

  • -50e + 20e = -30e

    • this is split equally between the two spheres because they are conductors of equal size, which then redistributes

  • -15e

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Copper vs. Silver vs. Gold as Conductors

  • Silver

    • Highest electrical conductivity

    • Lowest resistivity

    • Free electrons move the easiest

    • BUT (tarnishes and expensive)

  • Copper

    • Slightly less conductive than silver

    • WAY cheaper

    • Very ductile and flexible

    • Doesn’t corrode badly

  • Gold

    • Conductivity slightly worse than copper

    • Does not oxidize (corrosion-resistant)

    • Extremely stable over time

    • EXPENSIVE

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Charging by Conduction

  • charged object (rod) is placed in contact (touching) with another object (sphere)

    • some electrons on rod can move to the sphere

    • when rod is removed, the sphere is left with a charge (same charge as rod)

<ul><li><p>charged object (rod) is placed in <strong>contact (touching) </strong>with another object (sphere)</p><ul><li><p>some electrons on rod can move to the sphere</p></li><li><p>when rod is removed, the sphere is left with a charge (same charge as rod)</p></li></ul></li></ul><p></p>
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In charging by conduction, the object being charges is always left with…

a charge having the same sign as the object doing the charging

<p>a charge having the same sign as the object doing the charging</p>
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Charging by Induction

  • a negatively charged rubber rod is brought near an uncharged sphere

  • the charges in the sphere are redistributed

    • some of the electrons in the sphere are repelled from the electrons in the rod

  • a grounded conducting wire is connected to the sphere

    • allows some of the electrons to move from the sphere to the ground

  • the wire to ground is removed, the sphere is left with an excess of induced positive charge

  • charging by induction requires no contact with the object inducting the charge

<ul><li><p>a negatively charged rubber rod is brought near an uncharged sphere</p></li><li><p>the charges in the sphere are redistributed</p><ul><li><p>some of the electrons in the sphere are repelled from the electrons in the rod</p></li></ul></li><li><p>a grounded conducting wire is connected to the sphere</p><ul><li><p>allows some of the electrons to move from the sphere to the ground</p></li></ul></li><li><p>the wire to ground is removed, the sphere is left with an excess of induced positive charge</p></li><li><p>charging by induction requires <strong>no contact </strong>with the object inducting the charge</p></li></ul><p></p>
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Conduction vs. Induction

  • Conduction:

    • physical contact

    • generate same polarity

  • Induction:

    • no physical contact

    • do grounding

    • generate opposite polarity

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Charge Polarization

  • the charged object (on the left) induces charge on the surface of the insulator

  • this realignment of charge on the surface of an insulator is known as: polarization

<ul><li><p>the charged object (on the left) induces charge on the surface of the insulator</p></li><li><p>this realignment of charge on the surface of an insulator is known as: <strong>polarization</strong></p></li></ul><p></p>
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Charge Polarization: comb & paper

  • a charged comb attracts bits of paper due to polarization of the paper

  • if comb is positive, paper polarizes to be negative on closer side and positive on the far side, and continues on the other pieces of paper, forming a chain

<ul><li><p>a charged comb attracts bits of paper due to polarization of the paper</p></li><li><p>if comb is positive, paper polarizes to be negative on closer side and positive on the far side, and continues on the other pieces of paper, forming a chain</p></li></ul><p></p>
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<p>Light: Animation</p>

Light: Animation

  • blue wave: electric field

  • red wave: magnetic field

  • both self-generating fields

<ul><li><p>blue wave: electric field</p></li><li><p>red wave: magnetic field</p></li><li><p>both self-generating fields</p></li></ul><p></p>
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Light

  • electromagnetic wave

  • doesn’t need medium to travel

  • self-generating electric and magnetic field

  • speed = v = c = 3 x 10^8 m/s

    • also 300 × 10^6 m/s

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Example of Polarization: Bees

  • when the bee moves, its wings get a slight positive charge from interacting with the air (electrons free in clouds etc. from friction and air flow)

  • this helps the bee collect pollen because the pollen will stick to the slightly charged wings (just like pieces of paper stick to a charged comb)

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Polarizing Glass vs. 3D Glass

  • polarizing glass blocks light and has vertical fences

  • 3D glass has one vertical fence and one horizontal fence

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Coulomb’s Law

  • F = k​​e( |q1||q2| )/ r²

    • ke = Coulomb Constant = 8.9875×109 N m²/C²

    • F → electric force (Newtons)

      • vector quantity: direction matters

    • q₁, q₂ → charges (Coulombs)

    • r → distance between charges (meters)

  • Works best for point charges or spherical charges far apart: charges in the μC range

  • Inverse square law

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Force is proportional to…

  • q1q2

  • 1/r²

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  • mass leads to…

  • charge leads to…

  • magnet leads to…

  • gravitational field

  • electric field

  • magnetic field

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If body P, with a positive charge, is placed in contact with body Q (initially uncharged), what will be the nature of the charge left on Q?

  • in contact = conduction

  • conduction = same charge

  • Q must be positive

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According to Coulomb’s Law, force increases if…

  • Charges get bigger

  • Distance gets smaller

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Coulomb Inverse Square Law

  • Doubling distance = force ÷ 4

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Gravitational Force

  • F = G (m1m2)/r²

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Electrical Force vs. Gravitational Force

  • both are inverse square laws

  • the mathematical form of both laws is the same

    • masses replaced by charges

  • electrical forces can be either attractive or repulsive; gravitational forces are always attractive

  • electrostatic force is stronger than the gravitational force

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Two point charges are separated by a distance, d. q1 = -5e, q2 = +2e. Which charge experiences the strongest electric force (greatest magnitude)?

  • the force is the same magnitude for both charges

  • F = ke (|q1|q2|)/r²

  • think of Newton’s Law, equal and opposite reaction

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Coulomb’s Law for Multiple Charges

  • the resultant force on any one charge equals the vector sum of the forces exerted by the other individual charges that are present

  • remember to add the forces as vectors

  • Use Coulomb’s Law to find the force from each charge individually

  • Treat each force as a vector (direction matters!)

  • Add them vectorially → superposition (F1, net = F12 + F13 + F14 + F15 + F1n, …

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Vector Equations

  • A (QI)

  • B (QII)

  • C (QIII)

  • D (QIV)

  • A:

    • Ax = Acosθ

    • Ay = Asinθ

  • B:

    • Bx = Bsinθ

    • By = -Bcosθ

  • C:

    • Cx = -Ccosθ

    • Cy = -Csinθ

  • D:

    • Dx = Dcosθ

    • Dy = -Dsinθ

<ul><li><p>A:</p><ul><li><p>A<sub>x</sub> = Acos<span><span>θ</span></span></p></li><li><p><span><span>A</span><sub><span>y</span></sub><span> = Asin</span></span><span>θ</span></p></li></ul></li><li><p>B: </p><ul><li><p>B<sub>x</sub> = Bsin<span>θ</span></p></li><li><p><span>B</span><sub><span>y</span></sub><span> = -Bcosθ</span></p></li></ul></li><li><p>C:</p><ul><li><p>C<sub>x</sub> = -Ccos<span>θ</span></p></li><li><p><span>C</span><sub><span>y</span></sub><span> = -Csinθ</span></p></li></ul></li><li><p>D:</p><ul><li><p>D<sub>x </sub>= Dcos<span>θ</span></p></li><li><p><span>D</span><sub><span>y</span></sub><span> = -Dsinθ</span></p></li></ul></li></ul><p></p>
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If the vector is directly on the x-axis…

  • Dx = Dcosθ = D

  • Dy = 0

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Adding Vectors Graphically

<p></p><p></p>
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Adding Vector’s Mathematically

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<p>Which is the direction of the net force on the charge at the top?</p>

Which is the direction of the net force on the charge at the top?

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<p>What is the direction of the net force if the bottom left or bottom right charges are the point of interest?</p>

What is the direction of the net force if the bottom left or bottom right charges are the point of interest?

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A particle with charge 2microC is placed at the origin. An identical particle, with the same charge, is placed 2 m from the origin on the x axis, and a third identical particle, with the same charge, is placed 2 m from the origin on the y axis. The magnitude of the force on the particle at the origin is (ke = 8.9875×10^9 N*m²/C²).

If you are asked to find the force of q³, what will happen?

  • |F2| = |F3| based on where q’s are

  • |F2| = k(q1q2)/r² = 8.9×10^9 (2×10^-6)²/2²

    • 2² cancels on top and bottom

    • F = 8.99×10^-3 N

  • q1 = q2, q3 = 2×10^-6 C

  • Find Resultant now:

    • Rx = -F2

    • Ry = -F3

    • R = sqrt( (-F2)² + (-F3)²) = 1.3×10^-2 N

  • if asked to find force of q³, the F arrows will move and the Resultant will be different

<ul><li><p>|F<sub>2</sub>| = |F<sub>3</sub>| based on where q’s are</p></li><li><p>|F<sub>2</sub>| = k(q<sub>1</sub>q<sub>2</sub>)/r² = 8.9×10^9 (2×10^-6)²/2²</p><ul><li><p>2² cancels on top and bottom</p></li><li><p>F = 8.99×10^-3 N</p></li></ul></li><li><p>q<sub>1</sub> = q<sub>2</sub>, q<sub>3</sub> = 2×10^-6 C</p></li><li><p>Find <strong>Resultant </strong>now:</p><ul><li><p>R<sub>x</sub> = -F<sub>2</sub> </p></li><li><p>R<sub>y</sub> = -F<sub>3</sub> </p></li><li><p>R = sqrt( (-F<sub>2</sub>)² + (-F<sub>3</sub>)²) = <strong>1.3×10^-2 N</strong></p></li></ul></li></ul><p></p><ul><li><p>if asked to find force of q³, the F arrows will move and the Resultant will be different</p></li></ul><p></p>
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The Electric Field

A region around a charged object where other charges experience a force. It is defined as the force per unit charge at a point in space.

  • particle 2 pushes on particle 1 for example, despite a distance

  • object 1 fills space around itself with a field, when object 2 is placed in field, field acts on object 2

  • E = F/q0 = keQ/r2

    • units: N/C

    • vector quantity

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If an object has mass, it produces…

a gravitational field

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If an object has charge, it produces…

an electrical field

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The direction of the electrical field is defined as…

the direction of the electric force that would be exerted on a small positive test charge, q0, at that point

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The electric field produced by a negative charge is directed…

toward the charge

  • negative source charge attracts positive test charges

<p>toward the charge</p><ul><li><p>negative source charge attracts positive test charges</p></li></ul><p></p>
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The electric field produced by a positive charge is directed…

away from the charge

  • positive source charge repels positive test charge

<p>away from the charge</p><ul><li><p>positive source charge repels positive test charge</p></li></ul><p></p>
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Electric Field Lines

  • aid to visualize electric field patterns

  • drawn pointing in the direction of the field vector at any point

  • the electric field vector, E, is tangent to the electric field lines at each point

  • the number of lines per unit area through a surface perpendicular to the lines is proportional to the strength of the electric field in a given region

<ul><li><p>aid to visualize electric field patterns</p></li><li><p>drawn pointing in the direction of the field vector at any point</p></li><li><p>the electric field vector, E, is <strong>tangent to the electric field lines at each point</strong></p></li><li><p>the number of lines per unit area through a surface perpendicular to the lines is <strong>proportional to the strength of the electric field</strong> in a given region</p></li></ul><p></p>
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Electric Field Line Patterns - Point Charge

  • for a positive source charge

  • for a negative source charge

  • surround point charge, radiate equally in all directions

  • for a positive source charge, the lines will radiate outward

  • for a negative source charge, the lines will point inward

<ul><li><p>surround point charge, radiate equally in all directions</p></li><li><p>for a positive source charge, the lines will radiate outward</p></li><li><p>for a negative source charge, the lines will point inward</p></li></ul><p></p>
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Electric Field Line Patterns - Dipole

  • electric dipole = 2 equal and opposite charges

  • the high density of lines between the charges indicates the strong electric field in this region

  • no two field lines can cross each other

<ul><li><p>electric dipole = 2 equal and opposite charges</p></li><li><p>the high density of lines between the charges indicates the strong electric field in this region</p></li><li><p>no two field lines can cross each other</p></li></ul><p></p>
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Electrostatic Equilibrium

when no net motion of charge occurs within a conductor, the conductor is said to be in electrostatic equilibrium

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Isolated Conductor

  • electric field is zero everywhere inside the conducting material

  • any excess charge on an isolated conductor resides entirely on its surface

  • the electric field just outside a charged conductor is perpendicular to the conductor’s surface

  • on an irregularly shaped conductor, the charge accumulates at locations where the radius of curvature of the surface is smallest → at sharp points

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Faraday Cage

A structure that shields its contents from external electric fields by redistributing charge, ensuring the electric field inside remains zero.

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In an isolated conductor, if the electric field just outside a charged conductor is not perpendicular to the conductor’s surface, what would happen?

  • the component along the surface would cause the charge to move

  • it would not be in equilibrium

<ul><li><p>the component along the surface would cause the charge to move</p></li><li><p>it would not be in equilibrium</p></li></ul><p></p>
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In an isolated conductor that is irregularly shaped, what is true?

  • the charge accumulates at sharp points

  • any excess carge moves to its surface

  • the charges move apart until an equilibrium is achieved

  • the amount of charge perunit area is greater at the sharp end(s)

  • the forces from the charges at the sharp end(s) produce a larger resultant force away from the surface

  • it’s why a lightning rod works (pointy)

<ul><li><p>the charge accumulates at sharp points</p></li><li><p>any excess carge moves to its surface</p></li><li><p>the charges move apart until an equilibrium is achieved</p></li><li><p>the amount of charge perunit area is greater at the sharp end(s)</p></li><li><p>the forces from the charges at the sharp end(s) produce a <strong>larger resultant force away from the surface</strong></p></li><li><p><strong>it’s why a lightning rod works (pointy)</strong></p></li></ul><p></p>
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Electric Flux

  • Φ = E*A*cos(θ)

  • Electric field through a surface

    • field lines penetrating an area A perpendicular to the field

    • the perpendicular to the area A is at an angle θ to the field

<ul><li><p><strong><span>Φ = E*A*cos(</span></strong><span><strong><span>θ)</span></strong></span></p></li><li><p><span><span>Electric field through a surface </span></span></p><ul><li><p>field lines penetrating an area A perpendicular to the field </p></li><li><p><span><span>the perpendicular to the area A is at an angle </span><strong><span>θ </span></strong><span>to the field</span></span></p></li></ul></li></ul><p></p>
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In electric flux, when the area is constructed such that a closed surface is formed, flux lines passing into the interior of the volume are…

negative

<p>negative</p>
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In electric flux, when the area is constructed such that a closed surface is formed, flux lines passing out of the interior of the volume are…

positive

<p>positive</p>
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The Area Vector

  • a vector that points perpendicularly to a surface area, with a magnitude equal to the area of the surface. It is used in calculating electric flux through that surface.

  • A(→) = A

    • vector in direction of n̂, perpendicular to the surface

    • vector with magnitude A equal to the area of the surface

  • vector A(→) has units m²

<ul><li><p>a vector that points perpendicularly to a surface area, with a magnitude equal to the area of the surface. It is used in calculating electric flux through that surface. </p></li><li><p>A(→) = A<span><span>n̂</span></span></p><ul><li><p>vector in direction of <span>n̂, perpendicular to the surface</span></p></li><li><p><span>vector with magnitude A equal to the area of the surface</span></p></li></ul></li><li><p>vector A(→) has units m²</p></li></ul><p></p>

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