\ Only the second reaction is reversible due to the acid’s strong nature, but the HSO₄⁻ formed after the first reaction is weak
**Note that HSO₄⁻ is amphoteric because it can become SO₄²⁻(conjugate base) or H₂SO₄(conjugate acid)**
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Strong Bases
Strong electrolytes
* Formed from metals of groups 1A and 2A * Include LiOH, NaOH, KOH, Ba(OH)₂, Sr(OH)₂, Ca(OH)₂ * Dissociate completely in water * However, they have low solubility
KOH(s) → K⁺(aq) + OH⁻(aq)
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Weak Bases
Weak electrolytes
* Poor acceptors of H⁺ ions; not readily available to accept the H⁺ * Produce very few ions in solution * Include ammonia NH₃
A known volume of an acid is placed in a flask with an indicator and titrated with a measured volume of base solution to the neutralization endpoint
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Titration
A laboratory procedure used to determine the molarity of an acid
* Uses a base to neutralize a measured volume of an acid * Requires a few drops of indicator such as phenolphthalein to identify the endpoint
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Titration Endpoint
When the moles of base = the moles of acid
* The concentration of base is known * The volume of the base used to reach the endpoint is measured * The molarity of the acid is calculated using the neutralization equation for the reaction
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Indicator: Phenolphthalein
* In relation to titration
Added to identify the endpoint of a titration
* Turns pink when a solution is neutralized
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What is the molarity of an HCl solution if 18.5mL of 0.225M NaOH is needed to neutralize 0.0100L of HCl?
Always start with the volume that the M is given with
\ 18\.5 mL NaOH(1 L NaOH/1000 mL NaOH)(0.225 mol NaOH/1 L NaOH)(1 mol HCl/1 mol NaOH) = 0.00416
0\.00416 mol HCl/0.0100 L HCl = ***0.416 M HCl***
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Buffers
A buffer solution maintains the pH by neutralizing small amounts of added acid or base
* An acid must be present to react with an OH⁻ added and a base must be present to react with any H₃O⁺ added * Weak acid-base pairs
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Components of a buffer
Contains a combination of acid-base conjugate pairs, a weak acid, and a salt of its conjugate base
* Equal concentrations of weak acid and salt
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Function of a weak acid in a buffer
If a small amount of base is added, it is neutralized by the acid which shifts the equilibrium in the direction of the products
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Function of a conjugate base in a buffer
When a small amount of acid is added, the additional H₃O⁺ combines with the acid ion, causing the equilibrium to shift in the direction of the reactants
* The acid produced contributes to the available weak acid
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What chemical species affect pH?
H₃O⁺/H⁺ and OH⁻
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How does a buffer work?
* Added acid (H₃O⁺) * HA ⇌ A- + H₃O⁺
The added acid combines with the conjugate base and creates more of the original HA acid
* H₃O⁺ doesn’t change = no pH change
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How does a buffer work?
* Added base (OH⁻) * HA ⇌ A- + H₃O⁺
When a base is added, the H⁺ in the HA combines with the OH⁻ base to form water, and what’s left of the HA is A⁻, creating more of the conjugate base
* H₃O⁺ doesn’t change = no pH change
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In the body, what pH do buffers tend to maintain?
7\.4
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Can buffers soak up limitless amounts of acid or base, keeping the pH constant no matter what?
Nope, they have limits too
* Any contamination may also mess it up
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Which ones make a buffer?
1. HF and NaF 2. NH₄⁺ and NH₃ 3. HBr and Br 4. HCl and HClO
1. HF and NaF = yes
Whenever Na is in one of these, you simply cancel it out because it always ionizes, so you are left with HF and F⁻ which is weak and an acid-base pair
\ 2. NH₄⁺ and NH₃ = yes
It’s a weak acid-base pair
\ 3. HBr and Br = no
It’s an acid-base pair, but it’s strong, not weak
\ 4. HCl and HClO = no
It’s not an acid-base pair, since they do not differ by only an H⁺
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What are the pH values of
* Pure water * Blood plasma * 1M NaOH solution * 1 M HCl solution * Urine * Drinking water
**There are a ton more, look at the slides**
Pure water = 7.0
Blood plasma = 7.4
1M NaOH solution = 14.0
1 M HCl solution = 0.0
Urine = 6.0
Drinking water = 7.2
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What is the pH of a 0.260 M solution of KOH?
\-log(0.205) = the pOH value which is *0.602*
BUT we need the pH → pOH + pH = 14
\ 14 - 0.602 = 13.398, 3 sigfigs bc the og pH had three decimal places = ***13.4***
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The pH of an acidic solution is 2.11, what’s the \[H⁺\]?
10⁻²¹¹ (exponent = -2.11)
→ make sure it’s in scientific notation ***7.8 x 10⁻³ M***
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Predict whether the reaction has more products or reactants