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Solve and graph: y = 2x - 3
Take (0, -3) as y-intercept; slope = 2 → up 2, right 1. Plot and draw the line.
Find the slope between (2, 5) and (4, 9)
m = (9 - 5) / (4 - 2) = 4 / 2 = 2
Evaluate f(x) = -3x + 4 when x = -2
f(-2) = -3(-2) + 4 = 6 + 4 = 10
Is the relation {(1, 3), (2, 5), (1, -2)} a function?
No - input 1 has two different outputs
Solve |x - 4| = 6
x = 10 or x = -2
Solve and graph: 3x - 5 < 7
x < 4; graph open circle at 4 with arrow left
Solve and graph: |x + 2| > 5
x < -7 or x > 3; graph both with open circles, arrows left and right
Graph y = -½x + 1
Plot (0, 1); slope = down 1, right 2 → (2, 0); draw line
Evaluate f(x) = 2x² - x when x = 3
f(3) = 2(9) - 3 = 18 - 3 = 15
Solve |2x - 1| ≤ 5
-2 ≤ x ≤ 3; graph closed circle at -2 and 3 with line in between
Does a graph fail the vertical line test if a vertical line hits it twice?
Yes - it's not a function
Solve and graph: -2x + 3 ≥ 7
x ≤ -2; flip sign when dividing by negative. Graph closed circle at -2, arrow left.