1/6
Looks like no tags are added yet.
Name | Mastery | Learn | Test | Matching | Spaced |
---|
No study sessions yet.
conjugate acid from base
gain one H+ lose one -1
conjugate base from acid
lose one H+ gain one -1
pH to pOH
pH + pOH = 14
pH to [H+]
pH=-log[H+] / [H+]=10^-pH
[H+] to [OH-]
[H+]x[OH-]=1.0×10^-14
[OH-] to pOH
pOH=-log[OH-] / [OH-]=10^-pOH
Amphoteric
HCO3 / H2O / H2PO4