APBC calc tests for convergence and divergence

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13 Terms

1
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Nth-term test for DIVERGENCE

always do first

diverge if limit ā‰  0

2
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Geometric series test

if r < 1 converge

if r >= 1 diverge

find S = a/1-r

3
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Ratio test DO ENDPOINTS!!!

find An+1

limit ABOLUTE VALUE then DIVIDE An+1 by An

if limit < 1, series converges

if limit > 1, series diverges

if limit = 1, test is inconclusive

write everything out, declare terms

4
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Integral test

f(x) MUST BE

POSITIVE, DECREASING, CONTINUOUS

find the integral of bound

if the limit of integral ā‰  infinity converges

if the limit of integral = infinity diverges

5
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P-series test

for pure 1/n

p > 1 converges

p ā‰¤ 1 diverges

6
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Direct Comparison Test

POSITIVE

mutated series, but not as much

SIMPLIFY, find CONVERGENCE

big converge small converge >

small diverge big diverge <

7
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Limit Comparison Test

POSITIVE

Limit, Longer Test + Terms

SIMPLIFY, find CONVERGENCE

LIMIT of NORMAL / SIMPLIFIED =

if it approaches FINITE number, both converge or diverge

8
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Alternating Series Test for CONVERGENCE

MUST BE:

-alternating

-decrease in magnitude (compare An > An+1)

-have limit of 0

Then, REMOVE the alternator, take the limit, and use nth term test

If conditions match, series converge

9
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Absolute and Conditional Convergence

Check convergence for abs value and normal

-if abs value of An converge, absolute convergence

-if An converge but abs value of An donā€™t, conditional convergence

10
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integral tan inverse formula

1/a tan-1(u/a) + c

11
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integral sin inverse

sin -1 (u/a) +c

12
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Alternating Series Remainder

expand

must write: since series is

  • decreasing in magnitude

  • alternating

  • limit of zero

    Sn - error <= Sn <= Sn + error

error is the absolute value of the next term

show that error < fraction number

13
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Alternating series ERROR

WRITE CONDITIONS FOR AST

alternating, decrease, limit of 0

find term that is less than error

state that S - abs error <= Sum <= S + abs error

declare all terms