wave optics

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25 Terms

1
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some microscopic phenomena explained by wave optics

  • interference

  • diffraction

  • polarisation

2
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wavefront

  • it is the locus of all particles of a medium, which are vibrating in the same phase

  • a line perpendicular to a wavefront is called a ray

3
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spherical wavefront

  • when the source of light is a point source

  • its a sphere with the centre as source

(draw the diagram)

4
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cylindrical wavefront

  • when the source of light is linear (straight line/ slit etc.)

  • it is cylindrical in shape

  • all points equidistant from the source lie on the cylinder

(draw the diagram)

5
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plane wavefront

  • when the point/ linear source of light is at a very large distance

  • a small portion of the spherical/ cylindrical wavefront appears to be a plane

(draw the diagram)

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huygen’s principle

  • each point on the wavefront (primary wavefront) is the source of a secondary disturbance (secondary wavelets), and these wavelets spread out in all directions with the speed of the wave

    • the energy of the wave travels perpendicular to the wavefront

  • a surface touching these secondary wavelets tangentially in the forward direction at any instant of time gives a new wavefront (secondary wavelength)

(draw the diagram)

7
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why is there no backward secondary wavefront?

this is because the amplitude of the secondary wavefront is maximum in the forward direction and zero in the backward direction

8
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derivation of laws of reflection using huygen’s principle

derive it

(first & second laws)

9
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derivation of snell’s law using huygen’s principle

derive this

also prove that the frequency doesnt change after refraction

10
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behaviour of prism towards plane wavefront

  • the speed of light waves is less in glass

  • hence, the lower portion of the incident wavefront (which travels through the greatest thickness of the prism) will get delayed

  • this results in a tilt in the emerging wavefront

(draw diagram)

11
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behaviour of lens towards plane wavefront

  • the speed of light is less in lens

  • hence, the central portion of the incident wavefront travels through the thickest part and is delayed the most (convex lens)

  • this results in a depression at the centre of the refracted wavefront

    • thus, the wavefront becomes spherical and converges at the focus

(draw the diagram)

12
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behaviour of spherical mirror towards plane wavefront

  • the central part of the incident wavefront travels the largest distance before reflection (concave mirror)

  • hence, the reflected wavefront gets delayed at the centre

  • this results in the reflected wavefront becoming spherical, which converges at the focus

13
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coherent sources

they are sources of light which emit light waves of same wavelength, frequency and are in same phase or have constant phase difference

14
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incoherent sources

they are sources of light which do not emit light waves with constant phase difference

15
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interference term

  • when 2 independent sources of light emit monochromatic waves of intensities I1 & I2, and phase difference \phi meet at a point, then

  • resultant I = I1 + I2 + 2\sqrt{I1I2} \cos\phi

16
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interference term when \cos\phi remains constant with time

in this case,

  • maximum value: when \cos\phi is 1

    • I = (\sqrt{I1} + \sqrt{I2} )²

  • minimum value: when \cos\phi is -1

    • I = (\sqrt{I1} - \sqrt{I2} )²

  • hence, it is clear that we need 2 sources with same frequency & constant phase difference

    • so, we need 2 coherent sources

17
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inference term when \cos\phi various with time

  • assuming it varies with both positive and negative value, then the avg. value of \cos\phi over a full cycle is 0

  • hence, resultant I = I1 + I2

  • the 2 sources in this case are incoherent sources

18
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conditions for obtaining 2 coherent sources of light

  • they should be obtained from a single source from some device, such as

    • the source and its virtual image (lloyd’s mirror)

    • 2 virtual images of the same source (fresnel’s biprism)

    • two real images of the same source (young’s double slit)

  • the 2 sources should give monochromatic light

  • the path difference between light waves from both sources should be small

19
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fringe

bright/ dark band on the screen formed due to the constructive/ destructive interference of light from the two slits

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young’s double split experiment

supposing S1 and S2 are 2 slits distances d apart, with a screen distance D away. a source of light S with wavelength \lambda is passed through

  • constructive interference (bright fringes)

    • distance of nth bright fringe from midpoint O on the screen,

      • y = nD\lambda / d

  • destructive interference (dark fringes)

    • distance of nth dark fringe from midpoint O on the screen,

    • y = (2n - 1)D\lambda / 2d

where n = nth bright/ dark fringe

(draw diagram)

21
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fringe width

  • it is the separation between any 2 consecutive bright & dark fringes

  • \beta = D\lambda / d

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intensity of fringes

for bright fringe

  • \phi = 2n\pi

    • \cos\phi = 1

  • hence, I = I1 + I2 + 2\sqrt{I1I2}

  • I = 4Io (since in YDSE, I1 = I2 = Io)

for dark fringe

  • \phi = (2n - 1)\pi

    • \cos\phi = -1

  • hence, I = I1 + I2 - 2\sqrt{I1I2} = 0 (I1 = I2 = Io)

in general, the intensity at any point is

I = 4Iocos²(\phi /2)

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what happens to the fringe width when its immersed in a medium with R.I \mu ?

  • it decreases \mu times

  • this is because the wavelength decreases

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distribution of intensity

  • all bright interference fringes have intensity 4Io

  • all dark fringes have intensity 0

(draw diagram)

25
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conditions for sustained interference

in order to get a well defined interference pattern, intensity of constructive should be maximum and destructive should be 0. the following conditions must be satisfied

  • the 2 sources of light should be coherent

  • the 2 interfering ways must have same plane of polarisation

  • the 2 sources must be very close to each other and the pattern must be observed at a larger distance

  • the sources must be monochromatic

    • otherwise, the fringes of diff. colors would overlap

  • the 2 waves must have same amplitude for better contrast btw. bright and dark