halides with sulfuric acid

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4 Terms

1
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chloride ions

NaCl + H2SO4 →NaHSO4 + HCl

steamy fumes observed

2
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bromide ions

NaBr + H2SO4 → NaH2SO4 + HBr

2Br- + H2SO4 + 2H+ → Br2 + SO2 + 2H2O

orange/brown fumes observed as well as steamy fumes

3
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iodide ions

NaI + H2SO4 → NaHSO4 + HI

2I- + H2SO4 +2H+ → I2 + SO2 + 2H2O

6I- + H2SO4 + 6H+ → 3I2 + S + 4H2O

8I- + H2SO4 + 8H+ → 4I2 + H2S + 4H2O

steamy fumes, purple fumes, colourless gas yellow solid, gas with bad egg smell (H2S)

4
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what’s the order of reducing agent from best to worst?

iodide ions has the strongest reducing power as they reduce sulfur the most, all the way from +6 to 0. Iodide ions are also most likely to lose their outermost electron. bromine is next, then chlorine