organic chemistry 4: analyzing organic reactions

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41 Terms

1
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[...] acids are electron acceptors

lewis acids

  • contains vacant orbitals or postive polarized atoms

  • lewis acids are electron acceptors

<p>lewis acids </p><ul><li><p>contains vacant orbitals or postive polarized atoms  </p></li><li><p>lewis acids are electron acceptors </p></li></ul><p></p>
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[...] bases are electron donors

lewis bases

  • contain a lone pair of electrons and are often anions

<p>lewis bases</p><ul><li><p>contain a lone pair of electrons and are often anions </p></li></ul><p></p>
3
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A/an [...] acid is a proton donor

Bronsted-Lowry acid

<p>Bronsted-Lowry acid </p>
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A/an [...] base is a proton acceptor

A/an Brønsted-Lowry base is a proton acceptor

<p><span>A/an </span><span style="color: mediumseagreen"><strong>Brønsted-Lowry</strong></span><span> base is a </span><strong><u>proton</u></strong><span> acceptor</span></p><p></p>
5
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[...] molecules can act as either acids or bases

amphoteric

<p>amphoteric </p><img src="https://knowt-user-attachments.s3.amazonaws.com/3886e7d8-216c-43f4-a169-f15f3dcf9e79.png" data-width="100%" data-align="center"><p></p>
6
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Ka is the [...] constant

acid dissociation

  • an indicator of acid strength

  • it is the equilibrium constant corresponding to the dissociation of an acid, HA into a proton and its conjugate base

<p>acid dissociation </p><ul><li><p>an indicator of acid strength </p></li><li><p>it is the equilibrium constant corresponding to the dissociation of an acid, HA into a proton and its conjugate base </p></li></ul><p></p>
7
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Low pKa = [weak or strong] acid

strong

<p>strong </p>
8
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A/an [...] reaction is a reaction with the transfer of electrons from the substance being oxidized to the substance being reduced

redox

<p>redox </p><img src="https://knowt-user-attachments.s3.amazonaws.com/71f9d2ec-3c24-4c69-971a-8d50660e38c9.jpg" data-width="100%" data-align="center"><p></p>
9
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[...] is the charge an atom would have if all its bonds were completely ionic

oxidation number

<p>oxidation number </p>
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In REDOX reactions, the [oxidized or reduced] molecule loses electrons and the oxidation number increases

oxidized

<p>oxidized</p><p></p>
11
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An oxidizing agent [accepts or donates] electrons and is [oxidized or reduced] in the process

accepts; reduced

<p>accepts; reduced </p>
12
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n REDOX reactions, the [oxidized or reduced] molecule gains electrons and the oxidation number decreases

reduced

<p>reduced </p>
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reducing agent [accepts or donates] electrons and is [oxidized or reduced] in the process

donates

oxidized

<p>donates </p><p>oxidized </p>
14
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[...] is the ability of a reagent or inter­mediate to react with one group or atom in a mole­cule in preference to another group or atom present in the same molecule

chemoselectivity

15
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A/an [...] contains lone pairs of electrons or pi bonds and is “Nucleus-loving

nucleophile

<p>nucleophile </p>
16
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[...] is a term used to describe the strength of a  nucleophile

nucleophilicity

  • nucleophilicity is affected by:

    • charge

    • electronegativity

    • steric hindrance

    • solvent

<p>nucleophilicity </p><ul><li><p>nucleophilicity is affected by: </p><ul><li><p>charge</p></li><li><p>electronegativity </p></li><li><p>steric hindrance</p></li><li><p>solvent </p></li></ul></li></ul><p></p>
17
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[...] are electron loving

electrophiles

  • contain a positive charge or are positively polarized

<p>electrophiles</p><ul><li><p>contain a positive charge or are positively polarized  </p></li></ul><p></p>
18
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[...] are molecular fragments that retain the electrons after heterolysis

leaving groups

  • the least LG can stabilize additional charge through resonance of induction

  • weak bases make good leaving groups

<p>leaving groups </p><ul><li><p>the least LG can stabilize additional charge through resonance of induction </p></li><li><p>weak bases make good leaving groups </p></li></ul><p></p>
19
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Cl- and Br- are [good or bad] leaving groups

good

<p>good </p>
20
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-OH is a[good or bad]leaving group

bad

<p>bad </p>
21
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The "SN" in SN1 and SN2 reactions refers to [...]

nucleophilic substitution

<p>nucleophilic substitution </p>
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The number 1 in an SN1 reaction refers to the fact that the reaction is [...]

unimolecular

SN1 rate = k(substrate)1 = a first-order reaction

<p>unimolecular </p><p>SN1 rate = k(substrate)<sup>1 </sup> = a first-order reaction </p>
23
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An SN1 reaction has [#] step(s)

two

step 1: the LG leaves, forming a carbocation

step 2: the nucleophile attacks the planar carbocation from either side, leading to a racemic mixture of products

<p>two </p><p>step 1: the LG leaves, forming a carbocation </p><p>step 2: the nucleophile attacks the planar carbocation from either side, leading to a racemic mixture of products </p><img src="https://knowt-user-attachments.s3.amazonaws.com/3ebc9bfd-234f-448c-9390-5ab37d49616a.png" data-width="100%" data-align="center"><p></p>
24
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An SN2 reaction has [#] step(s)

one

  • the nucleophile attacks at the same time as the lG leaves

  • the nucleophile must perform a backside attack, which leads to inversion of stereochemistry

<p>one </p><ul><li><p>the nucleophile attacks at the same time as the lG leaves </p></li><li><p>the nucleophile must perform a backside attack, which leads to inversion of stereochemistry </p></li></ul><img src="https://knowt-user-attachments.s3.amazonaws.com/7e9253ff-8b32-4c6d-9c30-42581f1619e5.png" data-width="100%" data-align="center"><p></p>
25
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[SN1 or SN2] products are a racemic mixture

SN1

  • in the 2nd step, the nucleophile attacks the planar carbocation from either side, leading to a racemic mixture of products

<p>SN1  </p><ul><li><p>in the 2nd step, the nucleophile attacks the planar carbocation from either side, leading to a racemic mixture of products </p></li></ul><p></p>
26
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[SN1 or SN2] reactions lead to inversion of stereochemistry

SN2

  • the nucleophile must perform a backside attack, which leads to inversion of stereochemistry

<p>SN2</p><ul><li><p>the nucleophile must perform a backside attack, which leads to inversion of stereochemistry </p></li></ul><p></p>
27
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The rate law for an SN1 reaction is [...]

SN1 Rate = k[substrate]1

 

A first-order reaction

<p><span style="color: mediumseagreen"><strong>S<sub>N</sub>1&nbsp;Rate&nbsp;= k[substrate]<sup>1</sup></strong></span></p><p>&nbsp;</p><p>A <strong>first-order</strong> reaction</p>
28
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The rate law for an SN2 reaction is [...]

SN2 Rate = k[substrate]1[nucleophile]1

 

A second-order reaction

<p><span style="color: mediumseagreen"><strong>S<sub>N</sub>2&nbsp;Rate&nbsp;= k[substrate]<sup>1</sup>[nucleophile]<sup>1</sup></strong></span></p><p>&nbsp;</p><p>A <strong>second-order</strong> reaction</p>
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<p><span>A </span><strong><u>primary</u></strong><span> substrate will go </span><span style="color: mediumseagreen"><strong>[S<sub>N</sub>1&nbsp;or&nbsp;S<sub>N</sub>2]</strong></span></p>

A primary substrate will go [SN1 or SN2]

Sn2

1 step: if you were do an do an sn1 reaction on a primary substrate you’d get a primary carbocation which is very unstable

<p>Sn2</p><p>1 step: if you were do an do an sn1 reaction on a primary substrate you’d get a primary carbocation which is very unstable </p>
30
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<p><span>A </span><strong>tertiary</strong><span> substrate with a protic&nbsp;(or aprotic) solvent will go </span><span style="color: mediumseagreen"><strong>[S<sub>N</sub>1&nbsp;or&nbsp;S<sub>N</sub>2]</strong></span></p>

A tertiary substrate with a protic (or aprotic) solvent will go [SN1 or SN2]

sn1

2 steps

  • there is to much steric hinderance for the nucleophile to attack the carbon while the leaving group is still there. The LG must leave first

  • the products will be a mixture of sn1 and e1

<p>sn1</p><p>2 steps </p><ul><li><p>there is to much steric hinderance for the nucleophile to attack the carbon while the leaving group is still there. The LG must leave first </p></li><li><p>the products will be a mixture of sn1 and e1</p></li></ul><p></p>
31
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<p>theis reaction will go </p>

theis reaction will go

sn1

the substrate is secondary to CH3OH is a protic solvent

<p>sn1 </p><p>the substrate is secondary to CH3OH is a protic solvent </p>
32
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<p>this reaction will go </p>

this reaction will go

sn2

the substrate is secondary and acetone is an aprotic solvent

<p>sn2 </p><p>the substrate is secondary and acetone is an aprotic solvent </p><img src="https://knowt-user-attachments.s3.amazonaws.com/81c8fb50-39d8-4b95-ad2c-8f850d4fa72a.png" data-width="100%" data-align="center"><p></p>
33
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SN2 reactions prefer[...]substrates

methyl and primary

it is easy for the nucleophile to attack the carbon because the carbon is accessible (less steric hindrance)

the reaction can process in 1 step

<p>methyl and primary </p><p>it is easy for the nucleophile to attack the carbon because the carbon is accessible (less steric hindrance)</p><p>the reaction can process in 1 step </p>
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<p><span>A </span><strong><u>methyl</u></strong><span> substrate </span><strong>cannot</strong><span> undergo an </span><strong>elimination</strong><span> reaction because elimination reactions create </span><span style="color: mediumseagreen"><strong>[...]</strong></span></p>

A methyl substrate cannot undergo an elimination reaction because elimination reactions create [...]

double bonds between two carbons, C=C

there is only one carbon in methyl so no double bond can be created

<p>double bonds between two carbons, C=C</p><p>there is only one carbon in methyl so no double bond can be created </p>
35
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Strong bases favor [...] reactions

E2

<p>E2 </p>
36
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A secondary substrate with a protic solvent will go [SN1 or SN2]

Sn1

<p>Sn1 </p>
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A secondary substrate with an aprotic solvent will go [SN1 or SN2]

sn2

<p>sn2 </p>
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Polar [protic or aprotic] solvents are capable of hydrogen bonding

protic

  • Polar Protic: Acetic Acid, H2OROH, NH3

<p>protic </p><ul><li><p><span>Polar Protic: </span><strong><u>Acetic Acid</u></strong><span>, </span><strong><u>H<sub>2</sub>O</u></strong><span>,&nbsp;</span><strong><u>ROH</u></strong><span>, </span><strong><u>NH<sub>3</sub></u></strong></p></li></ul><p></p>
39
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Polar [protic or aprotic] solvents do not participate in hydrogen bonding

aprotic

  • Polar Aprotic: DMF, DMSOAcetone, Ethyl Acetate

<p>aprotic </p><ul><li><p><span>Polar Aprotic:&nbsp;</span><strong>DMF</strong><span>, </span><strong>DMSO</strong><span>,&nbsp;</span><strong>Acetone</strong><span>, </span><strong>Ethyl Acetate</strong></p></li></ul><p></p>
40
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Acetic acid is polar [protic or aprotic] 

protic

  • polar protic because it participates in hydrogen bonding

<p>protic </p><ul><li><p>polar protic because it participates in hydrogen bonding </p></li></ul><p></p>
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DMSO is polar [protic or aprotic] 

aprotic

-dimethyl sulfoxide is polar aprotic because it does not participate in hydrogen bonding

<p>aprotic </p><p>-dimethyl sulfoxide is polar aprotic because it does not participate in hydrogen bonding </p>