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Trend in atomic radius of the halogens
Atomic radius increases down the group
As you go down the group, there is more shells and more shielding, so a weaker attraction between the nucleus and outer electrons
Why is the ionic radius of halogens bigger than the atomic radius?
The halide ion (X-) has the same number of protons but more electrons than the atom (X) so the attraction between nucleus and outer electron is weaker
Trend in boiling point of halogens
Increases down the group
The halogens become less volatile (evaporate less easily)
This is because as you go down the group
Molecules (X2) are larger with more electrons
Vdws intermolecular forces between molecules are stronger
More energy Is needed to overcome them
Trend in electronegativity of halogens
Electronegativity decreases down the group
As you go down the group
There are more shells and more shielding
So the attraction between the nucleus and the pair of electrons in the covalent bond is less
Trend in first ionisation energy of halogens
First ionisation energy decreases down the group
As you go down the group
There are more shells and more shielding
So the attraction between the nucleus and outer electron is less
Less energy is needed to remove it
Appearance of Cl2
Green
Gas at room temp
Pale green in aqueous solution (polar solvent)
Pale green layer formed in cyclohexane (non-polar solvent)
Appearance of Br2
Red/brown
Liquid at room temp
Orange in aqueous solution (polar solvent)
Orange top layer forms in cyclohexane (non-polar solvent)
Appearance of I2
Black
Solid at room temp
Brown in aqueous solution (polar solvent)
Pink/purple top layer forms in cyclohexane (non-polar solvent)
Why are halogens more soluble in non-polar solvents (cyclohexane)?
The halogens are non-polar, so dissolve better in non-polar solvents
What do redox reactions of halogens provide evidence for?
The trend in oxidising powers of the halogens (halogens X2 are oxidising agents (they accept electrons)
Redox reaction of Cl2 with KBr
Forms potassium chloride and bromine
Chlorine is reduce, Cl2 is the oxidising agent
Cl2 + 2e- —> 2Cl-
Bromine is oxidised, Br- is the reducing agent
2Br- —> Br2 + 2e-
First write the full equation, then shorten to ionic and then half equations
Orange solution forms (Br2)
Redox reaction of Cl2 with KI
Forms potassium chloride and iodine
Chlorine is reduce, Cl2 is the oxidising agent
Cl2 + 2e- —> 2Cl-
Iodine is oxidised, I- is the reducing agent
2I- —> I2 + 2e-
First write the full equation, then shorten to ionic and then half equations
Brown solution forms (I2)
Redox reaction of Br2 with KI
Forms potassium bromide and iodine
Bromine is reduce, Br2 is the oxidising agent
Br2 + 2e- —> 2Br-
Iodine is oxidised, I- is the reducing agent
2I- —> I2 + 2e-
First write the full equation, then shorten to ionic and then half equations
Brown solution forms (I2)
Further reactions of halogens with no change
When KCl is reacted with Br2 it remains orange
When KCl and KBr are reacted with I2 they remain brown
Why are Br2 and I2 less good at acting as oxidising agents?
An oxidising agent is species that accepts electrons, halogens act as oxidising agents by accepting electrons to form halide ions
As you go down group 7,
There are more shells and more shielding
So the nuclear attraction to the outer shell is less
Electrons are less readily accepted
X2 is able to oxidise Y- is X if higher up the group than Y
Disproportionation definition
A redox reaction in which the same element is both oxidised and reduced
Disproportionation (redox) reaction of chlorine and water
equilibrium is establish between Cl2 and H2O, and on the other side HCl and HClO
Chlorine is both oxidised and reduced
Chlorine is pale green solution, HCl turns blue litmus red, HClO (chloric (I) acid) bleaches litmus paper
Used of chlorine in water treatment
Benefit: kills bacteria
Risks: toxic in large quantities
In presence of sunlight : hydrochloric acid and oxygen are produced, chloric (I) acid decomposes in sunlight to form the products
Disproportionation (redox) reaction of chlorine and cold dilute sodium hydroxide solution
Produces sodium chlorine, sodium chlorate (I) and water
Cl2 +2NaOH —> NaCl + NaClO + H2O
Green colour of chlorine fades and smell is less pungent
Chlorine is both oxidised and reduced
Used to kill bacteria and as a bleach
Test for aqueous halide ions
Determined from a precipitation reaction using acidified silver nitrate solution
Cl- ions form white precipitate (AgCl)
Br- ions form cream precipitate (AgBr)
I- ions form yellow precipitate (AgI)
F- ions do not form precipitate a precipitate as AgF is soluble in water- a colourless solution is seen
Silver chloride is soluble in dilute ammonia, silver bromide in concentrated ammonia and silver iodide in neither (used to distinguish between precipitates)
What do redox reactions of halide ions provide evidence for?
Halides are reducing agents (electron donors) as they donate electrons to form halogen molecules
Halide ions act as reducing agents to different extents- this can be investigated by studying the reaction of halide ions with concentrated sulfuric acid
Reaction of solid halide salts e.g. KCl, NaBr, with concentrated sulfuric acid
If sulfuric acid is reduced, there are a few possible reduction products
If it is reduced, X- will be oxidised to the halogen molecule X2
Possible products of reduction of concentrated sulfuric acid
Sulfuric acid has an oxidation number of +6
SO2 sulfur (IV) oxide, +4, appearance = choking gas (acidic, toxic)
S sulfur, 0, yellow solid
H2S hydrogen sulfide, -2, gas with a smell of bad eggs
What are the two types of reaction when a solid halide salt reacts with concentrated sulfuric acid?
Acid-base: sulfuric acid acts as an acid (H+) donor, X- is the base so accepts electrons
Redox: sulfuric acids acts as oxidising agent (e- acceptor) (X- acts as reducing agent)
Observations of NaCl and H2SO4
Acid-base: steamy white fumes HCl
Also forms NaHSO4
No redox reaction because no element has changed its oxidation state
Cl- (base) cannot reduce sulfuric acid (acid) so chloride ions are a weak reducing agent
Observations of NaBr and H2SO4
Acid-base: steamy white fumes HBr and also forms KHSO4
Sulfuric acid: H+ donor, Br-: H+ acceptor
Redox: Br- ion reduces sulfuric acid to SO2, Br- ion is reducing agent (donates electrons to sulfuric acid), sulfuric acid is oxidising agent (accepts electrons)
Observations: orange fumes of Br2 (product of oxidation), choking gas SO2 (product of reduction)
Observations of NaI and H2SO4
Acid-base: steamy white fumes HI and NaHSO4 also forms
Sulfuric acid: H+ donor, I-: H+ acceptor
Redox: I- reduces sulfuric acid to SO2, S, H2S
SO2: choking gas (product of reduction), black solid I2 (product of oxidation)
S: yellow solid (product of reduction), black solid I2 (product of oxidation)
H2S: gas with a smell of bad eggs (product of reduction), black solid I2 (product of oxidation)
H2S is the lowest oxidation number of sulfur
Iodide ions are powerful reducing agents, the sulfuric acid acts as an oxidising agent (electron acceptor) in each of these redox reactions
Why are some halides better at being reducing agents than others?
A reducing agent donates electrons (causes gain)
Halide ions donate electrons to form X2
The reducing strength of halides increases down the group
As you go down the group, the halide ion has more shells and more shielding so the nuclear attraction to the outer shell is less and electrons are more readily lost
Summary of the strength of oxidising agents and reducing agents
The halogens are oxidising agents- strength increases up the group and electrons are gained more readily
The halides are reducing agents- strength increases down the group as electrons are lost more readily