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Given [H3O], find pH
pH=-log[h3o]
Given pH, find [H3O]
[h3o]=10^(-pH)
Given [OH], find pOH, then pH
pOH=-log[OH-] then 14-pOH
Given pH, find [OH]
pOH=14-pH then [OH]=10^(-pOH)
If you have [H3O] of [OH-] to get the other
1×10^-14/known[H30] or [OH]