1/23
Looks like no tags are added yet.
Name | Mastery | Learn | Test | Matching | Spaced |
|---|
No study sessions yet.
spring acceleration
ax = -k/m • x = d²x/dt²
x(t) =
Acos(ωt + φ); A = amplitude, ω = angular freq, phi = phase constant
solve for unknown phase constant by
plugging in t = 0 and using both x(0) and v(0) equations
ω =
√k/m = 2πf = 2π/T - frequency in rads/s, rather than full rotations
φ
phase constant → adjusts starting time
f
1/2π • √k/m
T
2π • √m/k
v(t) =
-Aωsin(ωt + φ)
Vmax =
Aω
a(t) =
-Aω²cos(ωt + φ)
total energy =
½ kA²
total energy as a function of position
½ kx² + ½ mv²
velocity as a function of position
= √(k/m)(A² - X²) = Aω√1 - (x²/A²) = Vmax√1 - (x/A)²
T of pendulum
2π • √L/g
θ of physical pendulum =
θmaxcos(ωt + φ)
period of something swinging?
T = 2π√Ip/mgd
drag from damping
-bvx
x(t) when damped
Ae-(b/2m)tcos(ωt + φ)
ω when damped
√(k/m) - (b/2m)²
ω when damped
√(k/m) - (b/2m)²
underdamped when
b/2m < √k/m
critically damped when
b/2m = √k/m
overdamped when
b/2m > √k/m
see damping graph
in notes