Arenes (Aromatic Chemistry)

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8 Terms

1
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How is benzene structured? (3 bullet points)

  • Cyclic, planar molecules with formula C6H6

  • Carbon has 4 valent electrons, each carbon is bonded to 2 other carbons and 1 hydrogen atom. Therefore the final lone electron is in a p-orbital which sticks out above and below the planar ring.

  • Lone electrons in the p-orbitals combine to form a delocalized ring of electrons.

    (as a result all C-C bonds have same bond length of 139pm)

<ul><li><p>Cyclic, planar molecules with formula <mark data-color="yellow" style="background-color: yellow; color: inherit">C<sub>6</sub>H<sub>6</sub></mark></p></li><li><p><mark data-color="yellow" style="background-color: yellow; color: inherit">Carbon has 4 valent electrons</mark>, each carbon is bonded to 2 other carbons and 1 hydrogen atom.<mark data-color="yellow" style="background-color: yellow; color: inherit"> Therefore the final lone electron is in a p-orbital which sticks out above and below the planar ring.</mark></p></li><li><p>Lone electrons in the p-orbitals combine to form a <mark data-color="yellow" style="background-color: yellow; color: inherit">delocalized ring of electrons.</mark></p><p>(as a result all C-C bonds have same bond length of 139pm)</p></li></ul><p></p>
2
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What is Kekule’s theoretical structure vs the current structure of Benzene?

Kekule (cyclohexa-1-3-5-triene)

  • shows benzene with alternating double bonds and single bonds.

Benzene

  • shows delocalised electron system

<p>Kekule (cyclohexa-1-3-5-triene)</p><ul><li><p>shows benzene with alternating double bonds and single bonds.</p></li></ul><p>Benzene</p><ul><li><p>shows delocalised electron system</p></li></ul><p></p>
3
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Compare the stability of benzene against Kekule's structure.

Measured by the hydrogenation of the structures (adding hydrogen)

Benzene is less exothermic (more endothermic) meaning it requires more energy to break bonds making it more stable

<p>Measured by the <mark data-color="yellow" style="background-color: yellow; color: inherit">hydrogenation</mark> of the structures (adding hydrogen)</p><p>Benzene is <mark data-color="yellow" style="background-color: yellow; color: inherit">less exothermic (more endothermic) </mark>meaning it requires more energy to break bonds making it more stable</p>
4
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What are the two ways of naming benzenes?

with benzene at the end

or named as phenyl - when it becomes a side group

<p>with benzene at the end</p><p>or named as phenyl - when it becomes a side group</p>
5
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What reactions do benzenes undergo?

They undergo electrophilic SUBSTITUTION (replaces hydrogen or functional group), as electrophilic addition disrupts the stable ring of electrons

<p>They undergo electrophilic SUBSTITUTION (replaces hydrogen or functional group), as electrophilic addition disrupts the stable ring of electrons</p>
6
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What is Friedel-Crafts acylation?

When an acyl group (RCO-) is added onto a benzene molecule to make it weaker and easy to modify.

To add this acyl group (electrophile) it has to have a very strong positive charge.

  • We use a halogen carrier to act as a catalyst (AlCl3) to produce a much stronger electrophile with a stronger positive charge.

    R-C(O)-Cl + AlCl3 → RC+O + AlCl-4

Change: benzene → phenylketone

Reagents: acyl chloride in the presence of anhydrous aluminium chloride catalyst

Conditions: heat under reflux (50 C)

H+ at the end reacts with AlCl4- to produce AlCl3 + HCl

<p>When an acyl group (RCO-) is added onto a benzene molecule to make it weaker and easy to modify.</p><p>To add this acyl group (electrophile) it has to have a very strong positive charge.</p><ul><li><p>We use a<mark data-color="yellow" style="background-color: yellow; color: inherit"> halogen carrier to act as a catalyst (AlCl3)</mark> to produce a much stronger electrophile with a stronger positive charge.</p><p><mark data-color="yellow" style="background-color: yellow; color: inherit">R-C(O)-Cl + AlCl3 → RC<sup>+</sup>O + AlCl<sup>-</sup><sub>4</sub></mark></p></li></ul><p>Change: <mark data-color="yellow" style="background-color: yellow; color: inherit">benzene → phenylketone</mark></p><p>Reagents: <mark data-color="yellow" style="background-color: yellow; color: inherit">acyl chloride in the presence of anhydrous aluminium chloride catalyst</mark></p><p>Conditions: <mark data-color="yellow" style="background-color: yellow; color: inherit">heat under reflux (50 C)</mark></p><p>H+ at the end reacts with AlCl4- to produce AlCl3 + HCl</p>
7
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What is the nitration of benzene?

Reagents - concentrated nitric acid (HNO3) and sulfuric acid (H2SO4)

Conditions - A temp below 55 celcius to ensure a single NO2 substitution → submerge in ice bath

making the electrophile (NO2+)

  • HNO3 + H2SO4 → H2NO3+ + HSO4-

  • H2NO3+ → NO2+ + H2O

  • Overall equation

    HNO3 + H2SO4 → HSO4- + NO2+ + H2O

<p>Reagents - <mark data-color="yellow" style="background-color: yellow; color: inherit">concentrated nitric acid (HNO3) and sulfuric acid (H2SO4)</mark></p><p>Conditions - <mark data-color="yellow" style="background-color: yellow; color: inherit">A temp below 55 celcius</mark> to ensure a single NO2 substitution → submerge in ice bath</p><p>making the electrophile (NO2+)</p><ul><li><p><mark data-color="yellow" style="background-color: yellow; color: inherit">HNO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub> → H<sub>2</sub>NO<sub>3</sub>+ + HSO<sub>4</sub>-</mark></p></li><li><p><mark data-color="yellow" style="background-color: yellow; color: inherit">H<sub>2</sub>NO<sub>3</sub>+ → NO<sub>2</sub>+ + H<sub>2</sub>O</mark></p></li><li><p>Overall equation </p><p> HNO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub> → HSO<sub>4</sub>- + NO<sub>2</sub>+  + H<sub>2</sub>O</p></li></ul><p></p>
8
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How do you reduce nitrobenzene to an aromatic AMINE?

Reagent - Sn (tin catalyst) and conc. HCl/ Fe and conc. HCl

Conditions - heating

Mechanism - reduction

As the reaction is carried out in HCl the ionic salt C6H5NH3+Cl- will be formed. Reacting this salt with NaOH will give phenylamine.

<p>Reagent - <mark data-color="yellow" style="background-color: yellow; color: inherit">Sn (tin catalyst) and conc. HCl/ Fe and conc. HCl</mark></p><p>Conditions - <mark data-color="yellow" style="background-color: yellow; color: inherit">heating</mark></p><p>Mechanism - <mark data-color="yellow" style="background-color: yellow; color: inherit">reduction</mark></p><p><em>As the reaction is carried out in HCl the ionic salt C6H5NH3+Cl- will be formed. Reacting this salt with <mark data-color="yellow" style="background-color: yellow; color: inherit">NaOH</mark> will give phenylamine.</em></p>